shopt, shopt -o (set -o) manage the same flag (interactive_comments)

Description: it's not a bug, but a strange behavior the flag interactive_comments is accessible from both shopt and shopt -o shopt | grep interactive_comments shopt -o | grep interactive_comments in your documentation (bashref), shopt -o (set -o) does not have this flag... thanks for y

Re: bash leaves all for loop constructs when assignment w. expression fails

[EMAIL PROTECTED] wrote: Configuration Information [Automatically generated, do not change]: Machine: i486 OS: linux-gnu Compiler: gcc Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i486' -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu' -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/

Re: shopt, shopt -o (set -o) manage the same flag (interactive_comments)

antonio wrote: Description: it's not a bug, but a strange behavior the flag interactive_comments is accessible from both shopt and shopt -o shopt | grep interactive_comments shopt -o | grep interactive_comments in your documentation (bashref), shopt -o (set -o) does not have this flag...

Re: Q: bash: trap in subshell

Dmitry V. Levin wrote: Hi, I wonder whether such difference in "trap" behavior is valid: $ sh -c 'f() { echo f; }; t() { trap f EXIT; trap; }; t' trap -- 'f' EXIT f $ sh -c 'f() { echo f; }; t() { trap f EXIT; trap; }; t&' trap -- 'f' EXIT $ sh -c 'f() { echo f; }; t() { trap f EXIT; trap; }; (

FAQ E4

E4) If I pipe the output of a command into `read variable', why doesn't the output show up in $variable when the read command finishes? Would it cause a great deal of upset if the last section of a pipeline ran in the current process? Regards, Max

Select menu list formatting

Hi All, I have noticed that any number larger than 10 items in my select menu list will wrap the menu. I am not sure if this is a terminal issue or it is the way the BASH select function works Current Example: 1) mark3) paul 5) greg 7) mike9) justin 2) james 4) simon 6) kate 8) a