Thanks for the explanation. I didn't know any of these
On 11/8/19 4:50 PM, Oğuz wrote:
v=foo
echo ${v#[[:"lower":]]}
should print oo, but it prints foo instead. This is reproducible on bash
4.4
Plus
case foo in (*[![:"lower":]]*) echo bar; esac
prints bar, while
The idea is that at this point in command processing, quote removal hasn't
been p
FWIW, Andreas's description really was sufficient...
Date:Sat, 09 Nov 2019 06:46:05 -0800
From:L A Walsh
Message-ID: <5dc6d12d.6040...@tlinx.org>
| Is this really what the standard says,
Yes, I used cut&paste (and then some line length/wrappoing reformatting)
| because '\\' is not a character, but 2 characters.
I
On Nov 09 2019, L A Walsh wrote:
> On 2019/11/09 04:49, Robert Elz wrote:
>> There's also
>>
>> The special characters '.', '*', '[', and '\\'
>> (, , , and ,
>> respectively) shall lose their special meaning within a bracket
>> expression.
>>
>
> Is this really what th
You've already answered it, thank you. I didn't know that [:, [., [= were
special *sequences*, I guess I overlooked that part. Thanks again for
taking time to explain it in detail, I'm grateful
9 Kasım 2019 Cumartesi tarihinde Robert Elz yazdı:
> Date:Sat, 9 Nov 2019 07:35:16 +0300
On 2019/11/09 04:49, Robert Elz wrote:
> There's also
>
> The special characters '.', '*', '[', and '\\'
> (, , , and ,
> respectively) shall lose their special meaning within a bracket
> expression.
>
Is this really what the standard says, because '\\' is not a char
Date:Sat, 9 Nov 2019 07:35:16 +0300
From:=?UTF-8?B?T8SfdXo=?=
Message-ID:
| is correct, as "foo" does not contain a ']' which would be required
| > to match there (quoting the ':' means there is no character class,
| > hence we have instead (the negation of) a
is correct, as "foo" does not contain a ']' which would be required
> to match there (quoting the ':' means there is no character class,
> hence we have instead (the negation of) a char class containing '[' ':'
> 'l' 'o' 'w' 'e' ';r' (and ':' again), preceded by anything, and
> followed by ']' and
Date:Sat, 9 Nov 2019 00:50:52 +0300
From:=?UTF-8?B?T8SfdXo=?=
Message-ID:
These two
| v=foo
| echo ${v#[[:"lower":]]}
| case foo in (*[![:"lower":]]*) echo bar; esac
are because bash believes that the character class name must not
be quoted (which is likely
v=foo
echo ${v#[[:"lower":]]}
should print oo, but it prints foo instead. This is reproducible on bash
>4.4
Plus
case foo in (*[![:"lower":]]*) echo bar; esac
prints bar, while
case foo in (*[![":lower":]]*) echo bar; esac
doesn't print anything. And this is only reproducible on bash >5.0
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