[EMAIL PROTECTED] (Bob Proulx) writes:
> John Tromp wrote:
>> The idea of "escaping" a '!' with a backslash is rather lost if the
>> escaping character shows through. Wouldn't it be more useful to
>> remove the backslash? Now, when I want to echo the 3 characters
>> '!', I have to do something li
Please keep replies to the mailing list so that others can participate
in the discussion and any answers will be archived. Thanks.
John Tromp wrote:
> That is perfectly clear!
>
> However, the question remains: what is the rationale of that specification?
I was not part of the decision and can
John Tromp wrote:
> echo "hi\!" still shows the backslash
Thank you for your report. However this is intended behavior. And it
is also documented! :-)
man bash
Enclosing characters in double quotes preserves the literal value of
all characters within the quotes, with the exception
Configuration Information [Automatically generated, do not change]:
Machine: sparc
OS: solaris2.7
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='sparc'
-DCONF_OSTYPE='solaris2.7' -DCONF_MACHTYPE='sparc-sun-solaris2.7'
-DCONF_VENDOR='sun' -DSHELL -DHAVE_CONFIG_H -D_LARGEFILE
