Re: Word splitting for $@ in variable assignment

On Thu, Jun 24, 2021 at 5:20 PM Chet Ramey wrote: > On 6/24/21 4:09 AM, Ilkka Virta wrote: > > > But 3.4 Shell Parameters is a bit confusing: "Word splitting is not > > performed, with the exception of "$@" as explained below." > > This means that "$@" expands to multiple words, even though doubl

Re: Word splitting for $@ in variable assignment

On 2021-06-26 01:05, Robert Elz wrote: > | If Chet feels that a change is needed here, I would remove the "with > | the exception of" clause entirely. Just say "Word splitting is not > | performed." > > My suspicion (I'm guessing) is that exception is to cover > > x=("$@") `name=[

Re: Word splitting for $@ in variable assignment

On 2021-06-25 12:11, Greg Wooledge wrote: > > | A variable may be assigned to by a statement of the form > > | name=[value] > > | [...] > > | Word splitting is not performed, with the exception of "$@" as > > | explained below. > > This isn't the full sentence in the current man page. In the b

Re: Word splitting for $@ in variable assignment

Date:Fri, 25 Jun 2021 12:11:33 -0400 From:Greg Wooledge Message-ID: | That matches the behavior that I saw (and pasted on this mailing list the | other day). (Which by the way is *not* the same as "$*" unless IFS happens | to be unset or to begin with a space.

Re: Word splitting for $@ in variable assignment

On Fri, Jun 25, 2021 at 03:15:25PM +0200, Nora Platiel wrote: > But at least it is documented, and that part of the doc is clear to me. > The part of the doc that I'm complaining about is this one: > > | A variable may be assigned to by a statement of the form > | name=[value] > | [...] > | Wo

Re: Word splitting for $@ in variable assignment

Date:Thu, 24 Jun 2021 21:03:22 -0400 From:Greg Wooledge Message-ID: | Bash is ALL about these special cases. If you don't like it, don't write | code that uses it. In any sensible programming language, var="$@" | would have been an error. In bash, it's not.

Re: Word splitting for $@ in variable assignment

On 2021-06-25 7:36, Oğuz wrote: > > To me, "$@" expanding to multiple words would mean that: > > > > $ var="$@" foo > > > > for $# > 0, behaves the same as: > > > > $ var="$1" "${@:2}" foo > > But it wouldn't make any sense. `foo' would be subjected to alias > substitution even though it isn't kno

Re: Word splitting for $@ in variable assignment

On 2021-06-24 21:03, Greg Wooledge wrote: > "$@" expands like "$1 "$2" ... when used in most contexts. For example, Yes, that is clear to me. > The assignment-ness of the command overrides everything else. It > completely changes how the "$@" expansion occurs. Now, instead of > expanding like

Re: Word splitting for $@ in variable assignment

25 Haziran 2021 Cuma tarihinde Nora Platiel yazdı: > > To me, "$@" expanding to multiple words would mean that: > > $ var="$@" foo > > for $# > 0, behaves the same as: > > $ var="$1" "${@:2}" foo > But it wouldn't make any sense. `foo' would be subjected to alias substitution even though it isn't

Re: Word splitting for $@ in variable assignment

On Fri, Jun 25, 2021 at 01:47:01AM +0200, Nora Platiel wrote: > To me, "$@" expanding to multiple words would mean that: > > $ var="$@" foo > > for $# > 0, behaves the same as: > > $ var="$1" "${@:2}" foo > > which is obviously not the case. "$@" expands like "$1 "$2" ... when used in most con

Re: Word splitting for $@ in variable assignment

I was also confused by the same statement. On 2021-06-24 10:20 Chet Ramey wrote: > > But 3.4 Shell Parameters is a bit confusing: "Word splitting is not > > performed, with the exception of "$@" as explained below." > > This means that "$@" expands to multiple words, even though double quotes > wo

Re: Word splitting for $@ in variable assignment

On 6/24/21 4:09 AM, Ilkka Virta wrote: But 3.4 Shell Parameters is a bit confusing: "Word splitting is not performed, with the exception of "$@" as explained below." This means that "$@" expands to multiple words, even though double quotes would usually inhibit that. -- ``The lyf so short,

Re: Word splitting for $@ in variable assignment

On Thu, Jun 24, 2021 at 05:52:47PM +1000, Alvin Seville wrote: > Hello! I want to understand why the following code doesn't produce any > error: > set -- "a b" "c" > a="$@" It doesn't produce an error because the designers of the shell tried to make it "user-friendly" by having it guess what you

Re: Word splitting for $@ in variable assignment

On Thu, Jun 24, 2021 at 10:53 AM Alvin Seville wrote: > Hello! I want to understand why the following code doesn't produce any > error: > set -- "a b" "c" > a="$@" > ? I expected smth like: main.sh: line 2: b: command not found due to word > splitting according to documentation > < > https://www

Word splitting for $@ in variable assignment

Hello! I want to understand why the following code doesn't produce any error: set -- "a b" "c" a="$@" ? I expected smth like: main.sh: line 2: b: command not found due to word splitting according to documentation .