Thank you, Greg.
It turned out I was wrong in the basics.
Your explanation made me to review my code.
I will be more careful in the future.
19 марта 2014 г., в 18:27, Greg Wooledge написал(а):
> On Wed, Mar 19, 2014 at 02:18:52PM +0400, Dmitry Arkhireev wrote:
>> And if run it sample with echo
On Wed, Mar 19, 2014 at 02:18:52PM +0400, Dmitry Arkhireev wrote:
> And if run it sample with echo $I after ((I++)) everything works as expected
> I=0; while [ $I -ne 1 ]; do ((I++)); echo $I; done; echo $?
> 1
> 0
Here, $? is the exit status of the echo, instead of the ((...)) command.
The ((...)
