On 3/14/11 2:38 AM, Peggy Russell wrote:
> This helps clarify the "set -x" difference below which show $r going through
> parameter expansion done by the shell before the command [[ sees the
> expression.
> Okay...
>
> command [[ that
> contains expr set -x
> --
> The `r' is not a word expansion. It's a word that's evaluated as an
> expression when the command is executed. Arithmetic expansion is
> the $((...)) word expansion.
The command being [[ and the dollar-sign indicating the expansion.
This helps clarify the "set -x" difference below which show
On 3/13/11 8:06 PM, Peggy Russell wrote:
> I got the expected results below, but I didn't get the expected
> expansion in case (3).
>
> I expected to see "+ [[ 0 -eq 0 ]]" and not "+ [[ 0 -eq r ]]".
>
> With set -x, aren't the left and right parameters in a expression
> the final result of all ex
