On 1/19/21 5:38 AM, Oğuz wrote:
See:
$ a=(1 2 3)
$ b=a[@]
$ declare -n c=a[@]
$
$ printf '<%s>\n' "${!b}"
<1>
<2>
<3>
$ printf '<%s>\n' "$c"
<1 2 3>
Thanks for the report. This is an easy fix.
--
``The lyf so short, the craft so long to lerne.
19 Ocak 2021 Salı tarihinde Greg Wooledge yazdı:
> On Tue, Jan 19, 2021 at 01:38:13PM +0300, Oğuz wrote:
> > $ declare -n c=a[@]
>
> "However, nameref variables can reference array variables and
> subscripted array variables."
>
> Is a[@] a "subscripted array variable"?
>
It is, `@' is the
On Tue, Jan 19, 2021 at 01:38:13PM +0300, Oğuz wrote:
> $ declare -n c=a[@]
"However, nameref variables can reference array variables and
subscripted array variables."
Is a[@] a "subscripted array variable"?
