On Sat, 16 Dec 2023 at 07:21, Giacomo Comes wrote:
> debugon () {
> trap 'if (($?)); then echo "$((LINENO-1)): $(sed -n "$((LINENO-1))p"
> "$0")" ; fi' DEBUG
> }
> debugoff () {
> trap '' DEBUG
> }
>
>
Although LINENO is the command that's about to be executed, that does not
imply that LI
2023年12月16日(土) 6:22 Giacomo Comes :
The original post asks the reason for the difference in the status
between the following two cases:
if ((0)); then :; else echo "here \$? is 1"; fi
if ((0)); then :; fi; echo "but here \$? is 0"
and the answer is that the former returns the status of ((0)) (wh
On Sat, 16 Dec 2023 00:09:10 +
Kerin Millar wrote:
> At this point, the value of $? is 1, prior to executing true - a simple
> command. Just as for any other simple command, the trap code shall be
> executed beforehand. Consequently, your test observes that $? is
> arithmetically false and
On Fri, 15 Dec 2023 17:21:23 -0400
Giacomo Comes wrote:
> Hi,
> I have stumbled upon a bug or something I don't understand while
> using the debug trap.
> Please run the script at the end.
> When debug is turned on, during its execution the program
> prints the line number and the line content wh
