On 6/24/24 2:37 PM, Oğuz wrote:
You can do these
$ %f(){ :;}
$ declare -f %f
%f ()
{
:
}
$ unset -f %f
$ declare -f %f
$ echo $?
1
but not call them
$ %f
bash: fg: %f: no such job
$ '%f'
bash: fg: %f: no such job
$ \%f
bash: fg: %f: no such job
Why is that?
Think of it as a built-in al
On Tue, Jun 25, 2024 at 3:32 PM Emanuele Torre wrote:
> There are actually ways to call them:
>
> $ %f(){ echo hi;}
> $ compgen -F %f
> bash: compgen: warning: -F option may not work as you expect
> hi
Neat
On Mon, Jun 24, 2024 at 09:37:42PM +0300, Oğuz wrote:
> You can do these
>
> $ %f(){ :;}
> $ declare -f %f
> %f ()
> {
> :
> }
> $ unset -f %f
> $ declare -f %f
> $ echo $?
> 1
>
> but not call them
>
> $ %f
> bash: fg: %f: no such job
> $ '%f'
> bash: fg: %f: no such job
> $ \%f
> bash: fg:
On Mon, Jun 24, 2024 at 2:37 PM Oğuz wrote:
> $ %f
> bash: fg: %f: no such job
> $ '%f'
> bash: fg: %f: no such job
> $ \%f
> bash: fg: %f: no such job
Set +m won't fix this either.
$ %f(){ :;}
$ %f
-bash: fg: %f: no such job
$ set +m
$ %f
-bash: fg: no job control
Unlike ! in an arithmetic con
