Oh Mike,
thanks a lot for such detailled and well structured clarification! That
did it, now I can use it (and it gave my script a speedup of nearly 70 %
less running time).
Many thanks!
Dirk
Mike Stroyan schrieb:
On 3/13/06, Paul Jarc <[EMAIL PROTECTED]> wrote:
"Dirk H. Schulz" <[EMA
On 3/13/06, Paul Jarc <[EMAIL PROTECTED]> wrote:
> "Dirk H. Schulz" <[EMAIL PROTECTED]> wrote:
> > Paul Jarc schrieb:
> >> ac=12 eval "dings$ac=wasannersder"
> >
> > And how do I reference it then?
>
> ac=12 eval "value=\$dings$ac"
> echo $value
>
> Or:
>
> ac=12 name=dings$ac echo ${!name}
It see
"Dirk H. Schulz" <[EMAIL PROTECTED]> wrote:
> Paul Jarc schrieb:
>> ac=12 eval "dings$ac=wasannersder"
>
> And how do I reference it then?
ac=12 eval "value=\$dings$ac"
echo $value
Or:
ac=12 name=dings$ac echo ${!name}
paul
___
Bug-bash mailing lis
Paul Jarc schrieb:
"Dirk H. Schulz" <[EMAIL PROTECTED]> wrote:
ac=12 dings$ac=wasannersder
-bash: dings12=wasannersder: command not found
Variable names in assignments are not subject to expansion. So since
"dings$ac", as-is, does not fit the syntax for variable names, it
isn't tr
"Dirk H. Schulz" <[EMAIL PROTECTED]> wrote:
>> ac=12 dings$ac=wasannersder
>> -bash: dings12=wasannersder: command not found
Variable names in assignments are not subject to expansion. So since
"dings$ac", as-is, does not fit the syntax for variable names, it
isn't treated as an assignment. Thi
