Stupid me, everything makes sense now.
Thanks for explaining and sorry for the trouble!
2018-02-08 19:56 GMT+01:00 Ilkka Virta :
> On 8.2. 15:05, Jaan Vajakas wrote:
>
>> Hi!
>>
>> I noticed a weird behavior. Is it a bug?
>>
>> Namely, why does
>>
>> echo "$(for f in a b c; do if [[ \"$f\" > b ]
On 8.2. 15:05, Jaan Vajakas wrote:
Hi!
I noticed a weird behavior. Is it a bug?
Namely, why does
echo "$(for f in a b c; do if [[ \"$f\" > b ]]; then echo "$f > b"; else
echo "$f <= b"; fi; done)"
If I'm not mistaken, what you're doing is essentially this:
$ for f in '"a"' '"b"' '"c"'; do i
On Thu, Feb 8, 2018 at 4:27 PM, Jaan Vajakas wrote:
> So should Bash report a syntax error?
>
You do not have a syntax error, the rules for quoting inside $( ) are the
same as outside, whether you use outside quotes "$( )" or not
So in your case you are escaping the double quotes and concatena
So should Bash report a syntax error?
2018-02-08 15:24 GMT+01:00 Clark Wang :
> On Thu, Feb 8, 2018 at 9:05 PM, Jaan Vajakas
> wrote:
>
>> Hi!
>>
>> I noticed a weird behavior. Is it a bug?
>>
>> Namely, why does
>>
>> echo "$(for f in a b c; do if [[ \"$f\" > b ]]; then echo "$f > b"; else
>> e
On Thu, Feb 8, 2018 at 9:05 PM, Jaan Vajakas wrote:
> Hi!
>
> I noticed a weird behavior. Is it a bug?
>
> Namely, why does
>
> echo "$(for f in a b c; do if [[ \"$f\" > b ]]; then echo "$f > b"; else
> echo "$f <= b"; fi; done)"
>
Should be:
echo "$(for f in a b c; do if [[ $f > b ]]; then e
