On Thu, Jun 7, 2012 at 1:01 AM, Pierre Gaston wrote:
> Fwiw here is a robust and simple solution for in_:
>
> _in () {
> local e t
> t="${2:?}[@]";
> for e in "${!t}"; do [[ $1 = "$e" ]] && return 0;done
> return 1;
> }
>
>
The following won't have a name space collision with the 'e' variable
On Thu, Jun 7, 2012 at 12:27 PM, Dan Douglas wrote:
> On Thursday, June 07, 2012 10:01:51 AM Pierre Gaston wrote:
>> On Thu, Jun 7, 2012 at 6:07 AM, Linda Walsh wrote:
>> >(no I haven't made it space/bracket...whatever proof...just a bit
>> > more work)
>>
>> It's not just "a bit more work", ther
On Thursday, June 07, 2012 10:01:51 AM Pierre Gaston wrote:
> On Thu, Jun 7, 2012 at 6:07 AM, Linda Walsh wrote:
> >(no I haven't made it space/bracket...whatever proof...just a bit
> > more work)
>
> It's not just "a bit more work", there are many workarounds but it's not
> really possible to ma
On Thu, Jun 7, 2012 at 6:07 AM, Linda Walsh wrote:
>(no I haven't made it space/bracket...whatever proof...just a bit
> more work)
It's not just "a bit more work", there are many workarounds but it's not
really possible to make a really robust generic solution for assignment,
and in the end it ju
On Thu, Jun 7, 2012 at 6:07 AM, Linda Walsh wrote:
>
>
> Greg Wooledge wrote:
>>
>> The only Bourne-family shell that can manipulate arrays whose names are
>> passed to a function is ksh93, with its "nameref" command. Bash has
>> nothing analogous to that yet.
>
> =
>
> I don't unders
Greg Wooledge wrote:
The only Bourne-family shell that can manipulate arrays whose names are
passed to a function is ksh93, with its "nameref" command. Bash has
nothing analogous to that yet.
=
I don't understand.
Are you saying that ${!nameofvar} isnt' supported?
I need a fun
On 5/30/12 12:14 PM, Bill Gradwohl wrote:
> Admittedly, bash doesn't go out of its way to highlight this technique, but
> it does work.
>
> What say you Chet? Bug or feature? There is no middle ground.
Sure, there is. It's not explicitly documented, so the behavior is
undefined. You can read t
On Wed, May 30, 2012 at 4:57 PM, Greg Wooledge wrote:
>
> On Wed, May 30, 2012 at 10:14:42AM -0600, Bill Gradwohl wrote:
> > What say you Chet? Bug or feature? There is no middle ground.
>
> That's unrealistic. There are plenty of things that occupy that middle
> ground -- unexpected program beha
On Wed, May 30, 2012 at 10:57 AM, Greg Wooledge wrote:
> There are plenty of things that occupy that middle
> ground -- unexpected program behaviors. The programmer can never
> anticipate *every* input sequence that users will throw at the software,
> so some of them may cause surprises.
>
> Tru
On Wed, May 30, 2012 at 10:14:42AM -0600, Bill Gradwohl wrote:
> What say you Chet? Bug or feature? There is no middle ground.
That's unrealistic. There are plenty of things that occupy that middle
ground -- unexpected program behaviors. The programmer can never
anticipate *every* input sequence
On Wed, May 30, 2012 at 6:33 AM, Greg Wooledge wrote:
>
> Hacks like this are precisely why I stress that such functions *should
> not* be written in bash. If you want to compare two arrays, use a loop,
> without wrapping a function around it. That way you have access to the
> arrays directly,
On Tue, May 29, 2012 at 09:25:02PM -0600, Bill Gradwohl wrote:
> I have no idea what the wget's are supposed to be doing, but here's a
> function that will compare 2 foreign arrays and return true 0 or false 1.
>
> compareForeignArrays(){
>## $1 and $2 are the names of the arrays to compare.
>
I have no idea what the wget's are supposed to be doing, but here's a
function that will compare 2 foreign arrays and return true 0 or false 1.
compareForeignArrays(){
## $1 and $2 are the names of the arrays to compare.
## These are characters strings.
local intermediary
local sub
See any problem here?
#!/bin/bash
# [PL] Porownuje dwie tablice, zwraca prawde/falsz.
set -x
A=( "$1" )
B=( "$2" )
EQUAL=0
if [ ${#A[@]} -eq ${#B[@]} ]; then
for id in `seq 0 2 $[ ${#A[@]} - 2 ]`; do
if [ "${A[ $id ]}" == "${B[ $id ]}" ]; then
EQUAL=1
else
EQUAL=0
break
fi
done
fi
echo $
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