On 10/10/16 9:57 AM, Stephane Chazelas wrote:
> Now, if we look at the C spec, the way +++ is parsed is down to
> tokenisation that will also go for the longest operator first.
>
> There --test+++3 would be tokenised as -- test ++ + 3 which
> would lead to a syntax error as test++ isn't an lvalue
2016-10-08 17:33:00 +0200, Conrad Hoffmann:
[...]
> $ TEST=5; echo $((--TEST+++3)) # outputs 7
>
> However, due to the documented operator precedence, I would have
> expected that expression to be equal to:
>
> $ TEST=5; echo $((--(TEST++)+3)) # outputs 8
>
> Instead, though, it seems to be
Hi,
I have recently been looking at the POSIX Shell Command Language
specification [1] and trying to understand how shells parse their input.
One thing I am currently looking at is arithmetic expansion. I did some
tests with Bash, and one thing seemed curious to me:
In the Bash Reference Manual [
