Re: Confused about how bash breaks input into words

Eric Blake a écrit : > > Another good reference is POSIX: > http://www.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_03 A less rigorous and easier reading is the Guide to Unix Shell Quoting:

Re: Confused about how bash breaks input into words

On Feb 23, 8:41 pm, Allen Halsey wrote: > Eric Blake redhat.com> writes: > > > > > But you missed that: > > > $(date +'%Y-%m-%d') > > > is an entire word (basically, an unquoted $ character consumes until the > > end of the shell substitution, command substitution, or arithmetic > > substitution,

Re: Confused about how bash breaks input into words

Eric Blake redhat.com> writes: > > But you missed that: > > $(date +'%Y-%m-%d') > > is an entire word (basically, an unquoted $ character consumes until the > end of the shell substitution, command substitution, or arithmetic > substitution, and that entire scan becomes part of the current word

Re: Confused about how bash breaks input into words

On Tue, 23 Feb 2010, Eric Blake wrote: > According to Allen Halsey on 2/23/2010 3:50 PM: > > Hi, > > > > I'm trying to understand bash's parsing model. > > > > I read in the manual that the shell "breaks the input into words and > > operators, > > obeying the quoting rules described in Quoting.

Re: Confused about how bash breaks input into words

According to Allen Halsey on 2/23/2010 3:50 PM: > Hi, > > I'm trying to understand bash's parsing model. > > I read in the manual that the shell "breaks the input into words and > operators, > obeying the quoting rules described in Quoting. These tokens are separated by > metacharacters." Anoth

Confused about how bash breaks input into words

Hi, I'm trying to understand bash's parsing model. I read in the manual that the shell "breaks the input into words and operators, obeying the quoting rules described in Quoting. These tokens are separated by metacharacters." Taking this simple example: [...@host ~] $ echo The date is $(date +'