On 10/29/11 1:21 AM, Dan Douglas wrote:
> It seems the Bash parser can't distinguish between the semicolon as a
> command separator list operator, and the arithmetic context delimiter of
> the C-style for loop. I realize this construct isn't particularly useful.
> ksh93 and zsh handle it as expecte
It seems the Bash parser can't distinguish between the semicolon as a
command separator list operator, and the arithmetic context delimiter of
the C-style for loop. I realize this construct isn't particularly useful.
ksh93 and zsh handle it as expected, but in Bash it causes a syntax error
on my sy
