ar
al for foo in v
do echo foo=$foo bar=$bar
done
$ bash ./test
foo=v bar=
$ bash --posix ./test
foo= bar=v
发件人: Chet Ramey<mailto:chet.ra...@case.edu>
发送时间: 2023年1月17日 3:41
收件人: anonymous4feedb...@outlook.com<mailto:anonymous4feedb...@outlook.com>;
bug-bash@gnu.org<mailto:b
For the follow script
alias al=' '
alias foo=bar
al for foo in v
do echo foo=$foo bar=$bar
done
bash (version 5.1.16) prints foo=v bar=, while all other shells I tested (dash,
ksh, zsh, and yash) all prints foo= bar=v.
Apparently bash substitutes foo for bar in line 3 because the previous alias al
Dear dir or madam,
For the following script:
alias a1='echo '
alias a2=a1
alias foo=bar
a2 foo
bash outputs ‘foo’, instead of ‘bar’.
GNU bash, version 5.1.16(1)-release (x86_64-pc-linux-gnu) on archlinux as
windows subsystem for linux
Thanks.
