I think that helps me understand the differences better, and what I am
seeing.
Though It doesn't seem like it is completely consistent, and not what I
expected when using a variable with specific layout. (and also breaking
change enabled by default)
example, if i change the replacement to '\a'
it
On Thu, Jun 19, 2025, at 6:10 PM, Lawrence Velázquez wrote:
> This changed in bash 5.2:
>
> There is a new shell option, `patsub_replacement'. When
> enabled, a `&' in the replacement string of the pattern
> substitution expansion is replaced by the portion of the
> string
On Thu, Jun 19, 2025, at 5:28 PM, Jeff Ketchum wrote:
> $ cat replacestring.sh
> original_string="1|2|3|4"
> replace_string=':\\'
> echo "original: ${original_string} replace:${replace_string}"
> echo "unquoted ${original_string/2/${replace_string}}"
> echo "quoted ${original_string/2/"${replace_
I noticed a strange issue with some variable replacement text getting
replaced in a weird way.
It may be intentional. I just want to understand the differences and if it
is, or if its a newer bug.
Originally i was doing this to prepend data to an array like
"${array_[@]/#/${variable}}"
I simplifie
Date:Thu, 19 Jun 2025 09:27:20 +0200
From:microsuxx
Message-ID:
| bash -e -c 'echo $(exit 1) ; wait -n ; echo survived'
You really need to stop proposing nonsense when you have no idea
what is happening, or why:
bash -ec 'true; wait -n; echo survived'
bash -e -c 'echo $(exit 1) ; wait -n ; echo survived'
On Thu, Jun 19, 2025, 9:25 AM microsuxx wrote:
> hello there ..
> to return $( and maybe <( use wait -n
>
> bash -e -c $'trap \'wait -n ; (( $? )) && exit 1\' debug ; echo $(exit 1)
> ; echo survived'
> $ u0_a427/10427 localhost 09:24:18 19.
hello there ..
to return $( and maybe <( use wait -n
bash -e -c $'trap \'wait -n ; (( $? )) && exit 1\' debug ; echo $(exit 1) ;
echo survived'
$ u0_a427/10427 localhost 09:24:18 19.06.2025
~
On Thu, Jun 19, 2025, 12:39 AM Никола Константинов Кралев <
nkkra...@uni-sofia.bg> wrote:
> ```
> u c
