Am 07.05.2012 22:46, schrieb Chet Ramey:
> On 5/3/12 5:53 AM, Ruediger Kuhlmann wrote:
>> Hi,
>>
>> please try the following bash script:
>>
>> a=x
>> del="$(echo -e "\\x7f")"
>>
>> echo "$del${a#x}" | od -ta
>> echo "$del ${a#x}" | od -ta
>> echo " $del${a#x}" | od -ta
>>
>> Using bash 3.2, the ou
On 5/3/12 5:53 AM, Ruediger Kuhlmann wrote:
> Hi,
>
> please try the following bash script:
>
> a=x
> del="$(echo -e "\\x7f")"
>
> echo "$del${a#x}" | od -ta
> echo "$del ${a#x}" | od -ta
> echo " $del${a#x}" | od -ta
>
> Using bash 3.2, the output is:
>
> 000 del nl
> 002
> 000 d
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 5/5/12 12:28 AM, Mike Frysinger wrote:
> On Friday 04 May 2012 16:17:02 Chet Ramey wrote:
>> On 5/4/12 2:53 PM, Mike Frysinger wrote:
>>> it might be a little racy (wrt checking cnt >= 10 and then doing a wait),
>>> but this is good enough for some
On 5/6/12 3:25 AM, John Kearney wrote:
> Am 06.05.2012 08:28, schrieb Mike Frysinger:
>> On Saturday 05 May 2012 23:25:26 John Kearney wrote:
>>> Am 05.05.2012 06:28, schrieb Mike Frysinger:
On Friday 04 May 2012 16:17:02 Chet Ramey wrote:
> On 5/4/12 2:53 PM, Mike Frysinger wrote:
>>
On 5/5/12 11:25 PM, John Kearney wrote:
> Is there actually a guarantee that there will be 1 SIGCHLD for every
> exited process.
The manual page says, under JOB CONTROL:
Any trap on SIGCHLD is executed for each child that exits.
> Isn't it actually a race condition?
No. waitpid() returns once
On 5/5/12 2:37 AM, Andreas Schwab wrote:
> (bash) Bash POSIX Mode::
>
> 46. The arrival of `SIGCHLD' when a trap is set on `SIGCHLD' does not
> interrupt the `wait' builtin and cause it to return immediately.
> The trap command is run once for each child that exits.
>
> (I think the
