Re: lseek with bash

2011-12-09 Thread Chet Ramey
On 12/9/11 10:12 AM, Jean-Jacques Brucker wrote: > Playing with flock to securely access to a file shared by multiple > process. I noticed there are no documented way to do an lseek on an > opened fd with bash : [...] > I have solve my problem by making this small binary (i just needed a re

Russian translation for GNU Bourne-Again SHell page

2011-12-09 Thread Jim Jerginson
Hello, we've translated to Russian your great documentation page http://tiswww.case.edu/php/chet/bash/bashtop.html Please place a link to translated article from your site: http://tiswww.case.edu/php/chet/bash/bashtop.html Text of link: http://www.portablecomponentsforall.com/edu/gnu-bourne-again-s

Re: help-bash mailing list (Was: lseek with bash)

2011-12-09 Thread Greg Wooledge
On Fri, Dec 09, 2011 at 04:32:56PM +, Stephane CHAZELAS wrote: > First time I hear about a "help-bash" mailing list. Is that new? Yes, it's new. Announced by Chet on Nov 21: http://www.mail-archive.com/bug-bash@gnu.org/msg10154.html

help-bash mailing list (Was: lseek with bash)

2011-12-09 Thread Stephane CHAZELAS
2011-12-9, 10:27(-05), Greg Wooledge: [...] > This probably belongs on help-bash rather than bug-bash, although it's a > grey area. I'm Cc-ing both. [...] First time I hear about a "help-bash" mailing list. Is that new? I saw no annoucement in bash bug (I could have missed it though), nor does it

Re: lseek with bash

2011-12-09 Thread Greg Wooledge
On Fri, Dec 09, 2011 at 04:12:15PM +0100, Jean-Jacques Brucker wrote: > I have solve my problem by making this small binary (i just needed a rewind) : > > int main(int argc,char * argv[]) { return lseek(atoi(argv[1]),0L,0); } > > But i ll be glad to use a standard and finished tool. That looks p

lseek with bash

2011-12-09 Thread Jean-Jacques Brucker
Playing with flock to securely access to a file shared by multiple process. I noticed there are no documented way to do an lseek on an opened fd with bash : #!/bin/bash exec 18<>/tmp/resource flock 18 # (...) read and analyze the resource file # ?? there is no documented way to seek or rewind in

Re: super annoying completion change

2011-12-09 Thread Chet Ramey
> On Fri, Dec 9, 2011 at 11:24, Chet Ramey wrote: > > > Bash-4.2.20 does not have `direxpand'. Did I misunderstand you? > > > > Yes. > > > > I need to learn English much harder. :) It can be an especially confusing language. :-) -- ``The lyf so short, the craft so long to lerne.'' - Chaucer

Re: super annoying completion change

2011-12-09 Thread Clark J. Wang
On Fri, Dec 9, 2011 at 11:24, Chet Ramey wrote: > On 12/8/11 9:14 PM, Clark J. Wang wrote: > > > http://lists.gnu.org/archive/html/bug-bash/2011-09/msg7.html > > contains a basic summary and includes a patch that adds a `direxpand' > > shell option to restore the 4.1 behavior. > >

Re: extglob pattern: @(/root) vs. @(root)

2011-12-09 Thread Clark J. Wang
On Fri, Dec 9, 2011 at 20:12, Stephane CHAZELAS wrote: > 2011-12-9, 16:16(+08), Clark J. Wang: > > See following: > > > > # shopt extglob > > extglob on > > # echo $BASH_VERSION > > 4.2.20(1)-release > > # ls -d /root > > /root > > # pwd > > / > > # echo @(root) > > root > > # echo @(/root

Re: extglob pattern: @(/root) vs. @(root)

2011-12-09 Thread Stephane CHAZELAS
2011-12-9, 16:16(+08), Clark J. Wang: > See following: > > # shopt extglob > extglob on > # echo $BASH_VERSION > 4.2.20(1)-release > # ls -d /root > /root > # pwd > / > # echo @(root) > root > # echo @(/root) > @(/root) <-- ??? > # echo @(/root*) > @(/root*) <-- ??? > # > > I'm confused w

Re: extglob pattern: @(/root) vs. @(root)

2011-12-09 Thread Clark J. Wang
On Fri, Dec 9, 2011 at 16:16, Clark J. Wang wrote: > See following: > > # shopt extglob > extglob on > # echo $BASH_VERSION > 4.2.20(1)-release > # ls -d /root > /root > # pwd > / > # echo @(root) > root > # echo @(/root) > @(/root) <-- ??? > # echo @(/root*) > @(/root*) <-- ??? > But

extglob pattern: @(/root) vs. @(root)

2011-12-09 Thread Clark J. Wang
See following: # shopt extglob extglob on # echo $BASH_VERSION 4.2.20(1)-release # ls -d /root /root # pwd / # echo @(root) root # echo @(/root) @(/root) <-- ??? # echo @(/root*) @(/root*) <-- ??? # I'm confused why @(/root) and @(/root*) do not work here. -- -Clark