I'm having a hard time understanding how bash propagates `-e' to a
subshell. Considering the example script below:
- shouldn't C, D and E give no output? I know `-e' isn't in effect if
the test is part of a `&&', `||' or `!', but shouldn't `-e' be *in*
effect because the `&&', `||' or `!' are de
Halim Issa wrote:
> On a non-related note - there are still rumors around that bash 3.2 has some
> problems with `running backtick commands` compared to the new $(way to do it)
> - isn't this fixed in the first few patches of 3.2, or are there still
> compatibility issues from 3.1 to 3.2, and w
Thanks for replying!
On Saturday 13 December 2008 04:38:43 Chet Ramey wrote:
> Halim Issa wrote:
> > Type "one two three four five six seven eight" press ESCape and 7 B to go
> > seven words back. This takes me right in the middle of the prompt while
> > displaying (args:7) on the prompt. Once it
