[Tutor] Dictionaries

[Selby Rowley-Cannon]

Hello,
            I am having a problem with a small application I am writing. I have 
to have the user input the key, then have the program output the value 
associated with it. A way to inform the user that the key they entered is not 
in the dictionary or somefing would be nice also.

Fank you for your help,
        -Selby
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[Tutor] Dictionary

[Selby Rowley-Cannon]

Version: 2.7

OS: Ubuntu 12.04 LTS


I am writing a small translation app for Rydish (A language that exists in the 
same way Klingon does, invented by my company for a[n] RPG).
Here is my current method of translation:

Edictionary = {'English keys':'Rydish values'}
TextEng = raw_input('Please enter your text: ')
if TextEng in Edictionary:
    print(TextEng + ' traslates to ' + Edictionary[TextEng])

But I have found that this is only going to translate one word at a time. I 
thought about a loop of somesort, but I can't seem to find one that won't still 
force the user to translate one word at a time. Can anyone tell me how to 
translate a full sentance/several sentances?
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[Tutor] (no subject)

[Selby Rowley-Cannon]

Mailing list;
        I have a small, [for the most part] functioning translation app for 
Rydish, a language created for the sole purpose of an RPG. The only problem is 
when I enter a word that has not yet been translated, I get this error:

Traceback (most recent call last):
  File "translator.py", line 25, in 
    Etranslate()
  File "translator.py", line 14, in Etranslate
    print(Edictionary[Eword])
KeyError: 'world'

Is there a way to print a user-freindly message instead of displaying a 
traceback?
Thanks,
        -Selby
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[Tutor] check against multiple variables

[Selby Rowley-Cannon]

I am using a hash table in a small randomization program. I know that 
some hash functions can be prone to collisions, so I need a way to 
detect collisions.
The 'hash value' will be stored as a variable. I do not want to check it 
against each singular hash value, as there will be many; I need a way to 
check it against all hash values at once (if possible.) Sorry for those 
who like to reference, but there is no source code as of yet. I will 
need this to be solved before I can start writing, sorry!


If you need any extra info let me know.

-Selby
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[Tutor] Script won't run for no apparent reason

[Selby Rowley Cannon]

I have written a small application to encrypt some text. The script 
looks fine to me, but it won't run and I can't figure out why. I have 
attached it, if anyone knows why it doesn't work please let me know!
#!/usr/bin/env python3

import random
values = {'a':'d', 'b':'e', 'c':'f', 'd':'g', 'e':'h', 'f':'i', 'g':'j', 'h':'k', 'i':'l', 'j':'m', 'k':'n', 'l':'o', 'm':'p', 'n':'q', 'o':'r', 'p':'s', 'q':'t', 'r':'u', 's':'v', 't':'w', 'u':'x', 'v':'y', 'w':'z', 'x':'a', 'y':'b', 'z':'c', 'A':'D', 'B':'E', 'C':'F', 'D':'G', 'E':'H', 'F':'I', 'G':'J', 'H':'K', 'I':'L', 'J':'M', 'K':'N', 'L':'O', 'M':'P', 'N':'Q', 'O':'R', 'P':'S', 'Q':'T', 'R':'U', 'S':'V', 'T':'W', 'U':'X', 'V':'Y', 'W':'Z', 'X':'A', 'Y':'B', 'Z':'C',

def encrypt():
textInputE = input('Please enter the text you wish to encrypt: ')
textInputE.list()
for Eletter in textInputE.list():
try:
print (values[Eletter])
except KeyError:
print ('Sorry, that input couldn\'t be parsed as text. Try again.')
input('Press Enter')
def decrypt():
textInputD = input('Please enter the numbertext you wish to decrypt')
textInputD.list()
for Dletter in textInputD.list():
try:
print (values[Dletter])
except KeyError:
print ('Sorry, that input couldn\'t be parsed as numbertext from our cipher. Please try again.')
input('Press Enter')

while True:
EorD = input('Encrypt or Decrypt: ')
if EorD == 'Encrypt' or EorD == 'encrypt':
encrypt()
elif EorD == 'Decrypt' or EorD == 'decrypt':
decrypt()
else:
print('Encrypt or Decrypt?')
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Re: [Tutor] Script won't run for no apparent reason

[Selby Rowley Cannon]

On 10/08/12 20:07, Joel Goldstick wrote:

On Fri, Aug 10, 2012 at 2:57 PM, Selby Rowley Cannon
 wrote:

On 10/08/12 18:17, Joel Goldstick wrote:

On Fri, Aug 10, 2012 at 1:05 PM, Selby Rowley Cannon
 wrote:

I have written a small application to encrypt some text. The script looks
fine to me, but it won't run and I can't figure out why. I have attached
it,
if anyone knows why it doesn't work please let me know!


What do you mean 'it won't run'?  Do you get an error with Traceback?

I glanced at your code, and your dictionary ends like this: , 'X':'A',
'Y':'B', 'Z':'C',

There is no closing brace

OK,

   File "./crypto.py", line 6
 def encrypt():
   ^
SyntaxError: invalid syntax


First, don't reply to me, reply to the group.  That might mean
choosing reply all.

So, your first problem is that the dictionary isn't closed.  This is
causing the error at line 6

fix that and find your next error.  It looks like there are lots of them

With such a small file you would do better to just post the code
directly.  That way if people see problems they can point them out in
the body of the reply

good luck

#!/usr/bin/env python3

import random
values = {'a':'d', 'b':'e', 'c':'f', 'd':'g', 'e':'h', 'f':'i', 'g':'j', 
'h':'k', 'i':'l', 'j':'m', 'k':'n', 'l':'o', 'm':'p', 'n':'q', 'o':'r', 
'p':'s', 'q':'t', 'r':'u', 's':'v', 't':'w', 'u':'x', 'v':'y', 'w':'z', 
'x':'a', 'y':'b', 'z':'c', 'A':'D', 'B':'E', 'C':'F', 'D':'G', 'E':'H', 
'F':'I', 'G':'J', 'H':'K', 'I':'L', 'J':'M', 'K':'N', 'L':'O', 'M':'P', 
'N':'Q', 'O':'R', 'P':'S', 'Q':'T', 'R':'U', 'S':'V', 'T':'W', 'U':'X', 
'V':'Y', 'W':'Z', 'X':'A', 'Y':'B', 'Z':'C'}

def encrypt():
textInputE = input('Please enter the text you wish to encrypt: ')
textInputE.list()
for Eletter in textInputE.list():
try:
print (values[Eletter])
except KeyError:
print ('Sorry, that input couldn\'t be parsed as text. Try 
again.')

input('Press Enter')
def decrypt():
textInputD = input('Please enter the numbertext you wish to decrypt')
textInputD.list()
for Dletter in textInputD.list():
try:
print (values[Dletter])
except KeyError:
print ('Sorry, that input couldn\'t be parsed as numbertext 
from our cipher. Please try again.')

input('Press Enter')

while True:
EorD = input('Encrypt or Decrypt: ')
if EorD == 'Encrypt' or EorD == 'encrypt':
encrypt()
elif EorD == 'Decrypt' or EorD == 'decrypt':
decrypt()
else:
print('Encrypt or Decrypt?')

Thanks, I am not quite used to this client yet. The next error is:

Traceback (most recent call last):
  File "crypto.py", line 25, in 
EorD = input('Encrypt or Decrypt: ')
  File "", line 1, in 
NameError: name 'Encrypt' is not defined

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Re: [Tutor] Script won't run for no apparent reason

[Selby Rowley Cannon]

On 10/08/12 20:53, Joel Goldstick wrote:

On Fri, Aug 10, 2012 at 3:33 PM, Selby Rowley Cannon
 wrote:

On 10/08/12 20:07, Joel Goldstick wrote:

On Fri, Aug 10, 2012 at 2:57 PM, Selby Rowley Cannon
 wrote:

On 10/08/12 18:17, Joel Goldstick wrote:

On Fri, Aug 10, 2012 at 1:05 PM, Selby Rowley Cannon
 wrote:

I have written a small application to encrypt some text. The script
looks
fine to me, but it won't run and I can't figure out why. I have
attached
it,
if anyone knows why it doesn't work please let me know!


What do you mean 'it won't run'?  Do you get an error with Traceback?

I glanced at your code, and your dictionary ends like this: , 'X':'A',
'Y':'B', 'Z':'C',

There is no closing brace

OK,

File "./crypto.py", line 6
  def encrypt():
^
SyntaxError: invalid syntax


First, don't reply to me, reply to the group.  That might mean
choosing reply all.

So, your first problem is that the dictionary isn't closed.  This is
causing the error at line 6

fix that and find your next error.  It looks like there are lots of them

With such a small file you would do better to just post the code
directly.  That way if people see problems they can point them out in
the body of the reply

good luck

#!/usr/bin/env python3

import random
values = {'a':'d', 'b':'e', 'c':'f', 'd':'g', 'e':'h', 'f':'i', 'g':'j',
'h':'k', 'i':'l', 'j':'m', 'k':'n', 'l':'o', 'm':'p', 'n':'q', 'o':'r',
'p':'s', 'q':'t', 'r':'u', 's':'v', 't':'w', 'u':'x', 'v':'y', 'w':'z',
'x':'a', 'y':'b', 'z':'c', 'A':'D', 'B':'E', 'C':'F', 'D':'G', 'E':'H',
'F':'I', 'G':'J', 'H':'K', 'I':'L', 'J':'M', 'K':'N', 'L':'O', 'M':'P',
'N':'Q', 'O':'R', 'P':'S', 'Q':'T', 'R':'U', 'S':'V', 'T':'W', 'U':'X',
'V':'Y', 'W':'Z', 'X':'A', 'Y':'B', 'Z':'C'}
def encrypt():
 textInputE = input('Please enter the text you wish to encrypt: ')
 textInputE.list()
 for Eletter in textInputE.list():
 try:
 print (values[Eletter])
 except KeyError:
 print ('Sorry, that input couldn\'t be parsed as text. Try
again.')
 input('Press Enter')
def decrypt():
 textInputD = input('Please enter the numbertext you wish to decrypt')
 textInputD.list()
 for Dletter in textInputD.list():
 try:
 print (values[Dletter])
 except KeyError:
 print ('Sorry, that input couldn\'t be parsed as numbertext from
our cipher. Please try again.')
 input('Press Enter')

while True:
 EorD = input('Encrypt or Decrypt: ')

so are you sure the line above is really what you have in your code?
check the quotes


 if EorD == 'Encrypt' or EorD == 'encrypt':
 encrypt()
 elif EorD == 'Decrypt' or EorD == 'decrypt':
 decrypt()
 else:
 print('Encrypt or Decrypt?')

Thanks, I am not quite used to this client yet. The next error is:

Traceback (most recent call last):
   File "crypto.py", line 25, in 
 EorD = input('Encrypt or Decrypt: ')
   File "", line 1, in 
NameError: name 'Encrypt' is not defined





OK, I have put it back into Python 2.7, and now I get:
Traceback (most recent call last):
  File "crypto.py", line 27, in 
encrypt()
  File "crypto.py", line 7, in encrypt
textInputE.list()
AttributeError: 'str' object has no attribute 'list'


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[Tutor] (no subject)

[Selby Rowley Cannon]

OK, I have some code, and it uses glob.glob('*.py') to find all the 
python files in the current directory.

Just thought i'd ask, would:

glob.glob('C:\*.py') (Windows), or

glob.glob('/*.py') (*nix)

find all the python files on the system? Thanks
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[Tutor] Website form data input

[Selby Rowley-Cannon]

Hello, 

    I am aiming to write a program that inputs a list of codes into an HTML 
text field, one by one, entering the next code if it is incorrect, but stopping 
when the code is correct. I've got down putting the codes into a list, and 
'for' looping though it (maybe 'while' the entered code is incorrect?) but I 
don't know how to enter text into a text field in a website.
All help greatly appreciated, 
    -Selby___
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[Tutor] LCM

[Selby Rowley Cannon]

Hey,

I've been trying to write a function to find the Lowest Common 
Multiple of two numbers, but it isn't working and I've kinda hit a dead 
end on the thought-process end of things. Anyone mind looking at it, and 
tell me what's wrong? (I hop you don't think it's too long to put in an 
email)


Code:

def lowestCommonMultiple(a, b, amount): #k
float(amount)
if a == b:
print 'You cannot find the LCM of the same number twice.'
else:
numbersList = list(range(amount))
aMultiples = []
bMultiples = []
for aNumber in numbersList:
aMultiples.append(a*aNumber)
for bNumber in numbersList:
bMultiples.append(b*bNumber)
if aMultiples[1] == bMultiples[1]:
print 'The LCM of ', a, ' and ', b, ' is ', aMultiple[1]
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Re: [Tutor] LCM

[Selby Rowley Cannon]

On 14/11/12 18:27, Dave Angel wrote:

On 11/14/2012 12:52 PM, Selby Rowley Cannon wrote:

Hey,

 I've been trying to write a function to find the Lowest Common
Multiple of two numbers, but it isn't working and I've kinda hit a
dead end on the thought-process end of things. Anyone mind looking at
it, and tell me what's wrong? (I hop you don't think it's too long to
put in an email)

Code:

def lowestCommonMultiple(a, b, amount): #k
 float(amount)
 if a == b:
 print 'You cannot find the LCM of the same number twice.'
 else:
 numbersList = list(range(amount))
 aMultiples = []
 bMultiples = []
 for aNumber in numbersList:
 aMultiples.append(a*aNumber)
 for bNumber in numbersList:
 bMultiples.append(b*bNumber)
 if aMultiples[1] == bMultiples[1]:
 print 'The LCM of ', a, ' and ', b, ' is ', aMultiple[1]

Which are you interested in, finding what's wrong with the code, or a
simpler way to actually find an LCM ?

Is this an assignment, or just part of a bigger program you're writing?


a.) Finding what's wrong with the code;
b.) Part of a bigger program.
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