[Tutor] Doubts about installing python3.1 in squeeze
Hi, I'm learning Python and I'm using Debian 6.0 (squeeze) The installed version is 2.6.6. (python -V) I have seen some recommendations for beginners to invest in version 3. I found package of Python 3.1 in repository for squeeze. I am considering installing Python 3.1 with apt-get install python3.1 But I found the site http://www.circuidipity.com/python2-and-python3.html information on how to keep the two versions using virtualenv. Also I found in the /usr/bin python2.5 and python2.6 And in /usr/lib python2.4, python2.5 and python2.6 Can I just run apt-get install python3.1 or should I do any other configuration? I'm confused. Are there any risk to install python3.1 and some programs stop working on my debian squeeze? Thanks for any tips? Markos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Doubts about installing python3.1 in squeeze
On 22-05-2014 13:22, Alex Kleider wrote: On 2014-05-22 06:17, Markos wrote: Hi, I'm learning Python and I'm using Debian 6.0 (squeeze) The installed version is 2.6.6. (python -V) I have seen some recommendations for beginners to invest in version 3. I found package of Python 3.1 in repository for squeeze. I am considering installing Python 3.1 with apt-get install python3.1 But I found the site http://www.circuidipity.com/python2-and-python3.html information on how to keep the two versions using virtualenv. Also I found in the /usr/bin python2.5 and python2.6 And in /usr/lib python2.4, python2.5 and python2.6 Can I just run apt-get install python3.1 or should I do any other configuration? I'm confused. Are there any risk to install python3.1 and some programs stop working on my debian squeeze? Thanks for any tips? Markos On Ubuntu both v2 and v3 are installed by default. Have you tried typing python3 on the command line? If you get the interpreter, it's installed. Then you just have to use a different shebang line in your code files: #!/usr/bin/env python3 I don't have a debian system close at hand to test this myself. alex ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor Dear, Thanks everyone for the tips. I tried to install python3.1 with the command apt-get install python3.1 and use the shebang #!/usr/bin/env python3 in the source code header. It works. But to use Tkinter I also had to install the package python3-tk apt-get intall python3-tk Now I have in /usr/bin python python3 python2.5 python2.6 python3.1 python is a link to python2.6 and python3 is a link to python3.1 Until now everything is working. Markos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
[Tutor] Idle - ImportError: No module named numpy
Hi, I'm beginning to study the numpy. When I open a terminal (Debian Squeeze) and run the python interpreter the command "import numpy as np" run without errors. But when I run the same command on idle3 the following error appears. >>> import numpy as np Traceback (most recent call last): File "", line 1, in import numpy as np ImportError: No module named numpy How configure idle to load the numpy module? Thanks, Markos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Idle - ImportError: No module named numpy
On 06-03-2015 21:43, boB Stepp wrote: On Fri, Mar 6, 2015 at 12:27 PM, Markos wrote: Hi, I'm beginning to study the numpy. When I open a terminal (Debian Squeeze) and run the python interpreter the command "import numpy as np" run without errors. But when I run the same command on idle3 the following error appears. import numpy as np Traceback (most recent call last): File "", line 1, in import numpy as np ImportError: No module named numpy How configure idle to load the numpy module? You don't by chance have Python 2 installed as well as Python 3, where Python 2 is associated with your terminal session? And your numpy module is for Python 2, not 3? That is my first thought, but I'm sure the experts will chime in shortly with a more definitive diagnosis. Hi boB, I installed numpy in Debian (6.0) with the command: apt-get install python-numpy I just find that this package is exclusively for python 2.5 and 2.6 The idle3 use Python 3.1.3. How to install numpy for Python 3 in order to use it with the idle? Is there any simple way? Thanks, Markos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Idle - ImportError: No module named numpy
On 10-03-2015 16:48, Oscar Benjamin wrote:
On 10 March 2015 at 13:59, Markos wrote:
I don't have the python3-pip in the repository, then I downloaded the
get-pip.py from:
https://bootstrap.pypa.io/get-pip.py
But when running the command "python3 get-pip.py" appears the error message
(end of message).
Looks like a bug in pip or in the get-pip script. What version of
python3 are you using?
You'll just need to install setuptools and pip the old-fashioned way.
First check if you already have setuptools:
$ python3
Python 3.4.0 (default, Apr 11 2014, 13:05:11)
[GCC 4.8.2] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import setuptools
>>> setuptools.__version__
'3.3'
If not you can install it from here (download the .tar.gz file near
the bottom of the page):
https://pypi.python.org/pypi/setuptools
Extract the .tar.gz file, cd into it and run
$ sudo python3 setup.py install
Then do the same for pip from here:
https://pypi.python.org/pypi/pip
Then you should be able to install things with
$ python3 -m pip install
where package_name would be e.g. numpy and you'll need to be root or use sudo.
I found a message about a bug with pip at
https://github.com/pypa/pip/issues/1093
Is it the same kind of error?
I don't think so.
Any tip?
See above.
And another doubt.
Is there any risk of numpy module to be used by python3 to conflict with the
numpy module that is already installed for python2.5 and python2.6?
No. As long as you install setuptools and pip with "python3 setup.py
install" and install numpy with "python3 -m pip install numpy" then
your Python 2.x installations will be unaffected.
Oscar
Hi Oscar,
I downloaded the file
https://pypi.python.org/packages/source/s/setuptools/setuptools-14.0.tar.gz
tar -xzvf setuptools-14.0.tar.gz
cd setuptools-14.0
python3 setup.py install
Then I downloaded the file
https://pypi.python.org/packages/source/p/pip/pip-6.0.8.tar.gz
tar -xzvf pip-6.0.8.tar.gz
cd pip-6.0.8
python3 setup.py install
And the command python3 -m pip list
pip (6.0.8)
setuptools (14.0)
But the command to install numpy gave an error message:
# python3 -m pip install numpy
Collecting numpy
Exception:
Traceback (most recent call last):
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/basecommand.py",
line 232, in main
status = self.run(options, args)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/commands/install.py",
line 339, in run
requirement_set.prepare_files(finder)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/req/req_set.py",
line 333, in prepare_files
upgrade=self.upgrade,
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/index.py",
line 305, in find_requirement
page = self._get_page(main_index_url, req)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/index.py",
line 783, in _get_page
return HTMLPage.get_page(link, req, session=self.session)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/index.py",
line 872, in get_page
"Cache-Control": "max-age=600",
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/_vendor/requests/sessions.py",
line 473, in get
return self.request('GET', url, **kwargs)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/download.py",
line 365, in request
return super(PipSession, self).request(method, url, *args, **kwargs)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/_vendor/requests/sessions.py",
line 461, in request
resp = self.send(prep, **send_kwargs)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/_vendor/requests/sessions.py",
line 573, in send
r = adapter.send(request, **kwargs)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/_vendor/cachecontrol/adapter.py",
line 43, in send
resp = super(CacheControlAdapter, self).send(request, **kw)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/_vendor/requests/adapters.py",
line 370, in send
timeout=timeout
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/_vendor/requests/packages/urllib3/connectionpool.py",
line 518, in urlopen
body=body, headers=headers)
File
"/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/_vendor/requests/packages/urllib3/connectionpool.py",
line 322, in _make_request
self._validate_conn(conn
Re: [Tutor] Idle - ImportError: No module named numpy
On 09-03-2015 21:25, Oscar Benjamin wrote:
On 9 March 2015 at 18:09, Markos wrote:
I installed numpy in Debian (6.0) with the command:
apt-get install python-numpy
I just find that this package is exclusively for python 2.5 and 2.6
The idle3 use Python 3.1.3.
How to install numpy for Python 3 in order to use it with the idle?
Is there any simple way?
Hi Markos,
I'm not sure about Squeeze but on this Ubuntu 14.04 system you can
install numpy for Python 3 by typing:
$ sudo apt-get install python3-numpy
The Python 3 version of the package is a relatively new addition to
the repositories though so it may not be available in Squeeze.
If there is no package then you can build numpy yourself. It's not too
hard to do. First make sure that you have pip installed for python3.
You can check if it's installed by typing:
$ python3 -m pip
If it says
/usr/bin/python3: No module named pip
then you don't have pip. You may be able to install pip with
$ sudo apt-get install python3-pip
If not then you can install it by downloading the get-pip.py script from here:
https://pip.pypa.io/en/latest/installing.html
Once you have that you can run it as
$ sudo python3 get-pip.py
Once pip is installed you can use it to install lots of things
including numpy. For numpy in particular though you'll need to first
install the compilers and Python 3 header files:
$ sudo apt-get install build-essential python3-dev
Now you can use pip to install numpy for python3:
$ sudo python3 -m pip install numpy
This will download numpy from PyPI and then try to compile and install
it. Compiling numpy takes a while and you will see a lot of strange
compiler messages. If it fails then just post the very last part of
the output here. It will probably mean that you need to install more
compilers or something.
If it succeeds then you should be able to import numpy e.g.:
$ python3
Python 3.4.0 (default, Apr 11 2014, 13:05:11)
[GCC 4.8.2] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import numpy
>>> numpy.cos(1)
0.54030230586813977
Oscar
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Hi.
I don't have the python3-pip in the repository, then I downloaded the
get-pip.py from:
https://bootstrap.pypa.io/get-pip.py
But when running the command "python3 get-pip.py" appears the error
message (end of message).
I found a message about a bug with pip at
https://github.com/pypa/pip/issues/1093
Is it the same kind of error?
Any tip?
And another doubt.
Is there any risk of numpy module to be used by python3 to conflict with
the numpy module that is already installed for python2.5 and python2.6?
I still don't know the structure of Python packages.
Thank you very much for your detailed explanation.
Markos
# python3 get-pip.py
Collecting pip
Exception:
Traceback (most recent call last):
File "/tmp/tmpn0At3p/pip.zip/pip/basecommand.py", line 232, in main
status = self.run(options, args)
File "/tmp/tmpn0At3p/pip.zip/pip/commands/install.py", line 339, in run
requirement_set.prepare_files(finder)
File "/tmp/tmpn0At3p/pip.zip/pip/req/req_set.py", line 333, in
prepare_files
upgrade=self.upgrade,
File "/tmp/tmpn0At3p/pip.zip/pip/index.py", line 305, in
find_requirement
page = self._get_page(main_index_url, req)
File "/tmp/tmpn0At3p/pip.zip/pip/index.py", line 783, in _get_page
return HTMLPage.get_page(link, req, session=self.session)
File "/tmp/tmpn0At3p/pip.zip/pip/index.py", line 872, in get_page
"Cache-Control": "max-age=600",
File "/tmp/tmpn0At3p/pip.zip/pip/_vendor/requests/sessions.py",
line 473, in get
return self.request('GET', url, **kwargs)
File "/tmp/tmpn0At3p/pip.zip/pip/download.py", line 365, in request
return super(PipSession, self).request(method, url, *args, **kwargs)
File "/tmp/tmpn0At3p/pip.zip/pip/_vendor/requests/sessions.py",
line 461, in request
resp = self.send(prep, **send_kwargs)
File "/tmp/tmpn0At3p/pip.zip/pip/_vendor/requests/sessions.py",
line 573, in send
r = adapter.send(request, **kwargs)
File "/tmp/tmpn0At3p/pip.zip/pip/_vendor/cachecontrol/adapter.py",
line 43, in send
resp = super(CacheControlAdapter, self).send(request, **kw)
File "/tmp/tmpn0At3p/pip.zip/pip/_vendor/requests/adapters.py",
line 370, in send
timeout=timeout
File
"/tmp/tmpn0At3p/pip.zip/pip/_vendor/requests/packages/urllib3/connectionpool.py",
line 518, in urlo
Re: [Tutor] Idle - ImportError: No module named numpy
On 13-03-2015 12:34, Oscar Benjamin wrote: On 11 March 2015 at 19:43, Markos wrote: On 10-03-2015 16:48, Oscar Benjamin wrote: Looks like a bug in pip or in the get-pip script. What version of python3 are you using? But the command to install numpy gave an error message: # python3 -m pip install numpy Collecting numpy Exception: Traceback (most recent call last): File "/usr/local/lib/python3.1/dist-packages/pip-6.0.8-py3.1.egg/pip/basecommand.py", Ah okay. You're using Python 3.1. Python 3.1 is not supported by pip, setuptools or numpy. That may explain the error messages that you get with pip. Also it explains why there is no python3-numpy package in your repositories. Essentially most major Python packages are aimed at Python 2.6/2.7 and Python 3.2 upwards but not Python 3.0 or 3.1. Does squeeze have a newer version of Python 3 (e.g. 3.2)? It may be possible to get numpy to work with python 3.1 but I would recommend either: 1) Stick to Python 2. 2) Upgrade to wheezy - I haven't checked but I assume that it has a newer version of Python 3. 3) Install Python 3.4 manually (by compiling it yourself). If you do want to try and install numpy for python 3.1 then you would download the .tar.gz from here: https://pypi.python.org/pypi/numpy Then extract it, cd in, and run "python3 setup.py install". The people who make numpy don't support Python 3.1 though which means that they don't try to guarantee that it will work so you may encounter more problems. Oscar Hi Oscar, Despite failing to install numpy for Python 3.1, this exchange of messages helped me to understand the "Python world": ^) Thank you very much for your attention. Markos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
[Tutor] difference between array([1,0,1]) and array([[1,0,1]])
Hi, I'm studying Numpy and I don't understand the difference between vector_1 = np.array( [ 1,0,1 ] ) with 1 bracket and vector_2 = np.array( [ [ 1,0,1 ] ] ) with 2 brackets The shape of vector_1 is: vector_1.shape (3,) But the shape of vector_2 is: vector_2.shape (1, 3) The transpose on vector_1 don't work: vector_1.T array([1, 0, 1]) But the transpose method in vector_2 works fine: vector_2.T array([[1], [0], [1]]) I thought that both vectors would be treated as an matrix of 1 row and 3 columns. Why this difference? Any tip? Thank you, Markos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Difference between array( [1, 0, 1] ) and array( [ [1, 0, 1] ] )
Thanks Edmondo, Stephen, Mats and Steven you for the tips, I studied linear algebra many years ago and I remember only a few rudiments. But I was trying to visualize (in a geometric way) how the numpy represents arrays, and what the geometrical meaning of the transpose operation made by numpy. I think I understood a little bit more. The number of nested brackets indicates the number of array dimensions. the vector ( [1,2] ) is one-dimensional, but the vector ( [ [1,2] ] ) is two-dimensional. v_1 = np.array( [1,2] ) > v_1.shape (2,) > v_1 v_1 > v_1 array( [1, 2] ) > v_2 = np.array( [ [1,2] ] ) > v_2.shape (1, 2) And it does not make sense to transpose a one-dimensional array. > v_1.T array( [1, 2] ) > v_2.T array( [ [1], [2] ] ) Anothe example: vector_1 = np.array( [ 1, 2, 3, 4, 5, 6, 7, 8 ] ) ^ vector_2 = np.array( [ [1, 2, 3, 4], [5, 6, 7, 8] ] ) ^ ^ vector_3 = np.array( [ [ [1,2], [3,4] ], [ [5,6], [7,8] ] ] ) ^ ^ ^ > vector_1 array([1, 2, 3, 4, 5, 6, 7, 8]) > vector_2 array( [ [1, 2, 3, 4], [5, 6, 7, 8] ] ) > vector_3 array( [ [ [1, 2], [3, 4] ], [ [5, 6], [7, 8] ] ] ) And looking for some tutorial about geometric aspects of matrices and the geometric meaning of the transpose I found that transposed is "mirrored along the diagonal" at: https://www.coranac.com/documents/geomatrix/ >vector_1.T array([1, 2, 3, 4, 5, 6, 7, 8]) > vector_2.T array( [ [1, 5], [2, 6], [3, 7], [4, 8] ] ) > vector_3.T array( [ [ [1, 5], [3, 7]], [ [2, 6], [4, 8] ] ] ) Thank you, Markos Em 21-06-2019 07:44, edmondo.giovanno...@gmail.com escreveu: Every array in numpy has a number of dimensions, "np.array" is a function that can create an array numpy given a list. when you write vector_1 = np.array([1,2,1]) you are passing a list of number to thet function array that will create a 1D array. As you are showing: vector_1.shape will return a tuple with the sizes of each dimension of the array that is: (3,) Note the comma thta indicate that is a tuple. While if you write: vector_2 = np.array([[1,2,3]]) You are passing a list of list to the function array that will instruct it to crete a 2D array, even though the size of the first dimension is 1: vector_2.shape (1,3) It is still a tuple as you can see. Try: vector_3 = np.array([[1,2,3],[4,5,6]]) And you'll see that i'll return a 2D array with a shape: vector_3.shape (2,3) As the external list has 2 elements that is two sublists each with 3 elements. The vector_2 case is just when the external list has only 1 element. I hope it is more clear now. Cherrs, Il giorno venerdì 21 giugno 2019 08:29:36 UTC+2, Markos ha scritto: Hi, I'm studying Numpy and I don't understand the difference between vector_1 = np.array( [ 1,0,1 ] ) with 1 bracket and vector_2 = np.array( [ [ 1,0,1 ] ] ) with 2 brackets The shape of vector_1 is: vector_1.shape (3,) But the shape of vector_2 is: vector_2.shape (1, 3) The transpose on vector_1 don't work: vector_1.T array([1, 0, 1]) But the transpose method in vector_2 works fine: vector_2.T array([[1], [0], [1]]) I thought that both vectors would be treated as an matrix of 1 row and 3 columns. Why this difference? Any tip? Thank you, Markos ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
