Re: [Tutor] Beginner question
>def checkCave(chosenCave):
> print('You approach the cave...')
>time.sleep(2)
> print('It is dark and spooky...')
> time.sleep(2)
>print('A large dragon jumps out in front of you! He opens his jaws
and...')
>print()
> time.sleep(2)
>friendlyCave = random.randint(1, 2)
> if chosenCave == str(friendlyCave):
> print('Gives you his treasure!')
> else:
> print('Gobbles you down in one bite!')
>playAgain = 'yes'
>while playAgain == 'yes' or playAgain == 'y':
>displayIntro()
>caveNumber = chooseCave()
>checkCave(caveNumber)
>print('Do you want to play again? (yes or no)')
>playAgain = input()
Hi,
- Here we are passing the chosen integer (1 or 2) got from chooseCave()
method to checkCave as arguement
- When called in while loop inside checkCave the following happens;
- The statements of approaching the cave and seeing the dragon are
printed with a time interval of 2 secs between each
- Randomly either 1 or 2 is generated by the randint() method of random
module in python.
- That randomly generated integer (1 0r 2) is compared with our integer
input (1 or 2)
- If they match dragon gives us gold. Or else
- We will be eaten by dragon :)
But in the code there is a flaw. input() will evaluate your user input.
i.e. If you give an integer expression it will tell the answer. And when
you provide a number it will take it as int type. See below.
>>> var = input()
1+2+3
>>> var
6
>>> var = input()
2
>>> type(var)
>>> var = input()
s
Traceback (most recent call last):
File "", line 1, in
File "", line 1, in
NameError: name 's' is not defined
>>> var = input()
So since the integer number is checked with string in Line 13, it will run
into infinite loop. If you use raw_input() instead of input() you will be
able to run the example.
Regards,
Krishnan
On Mon, Aug 12, 2013 at 10:25 PM, Jim Mooney wrote:
> On 12 August 2013 02:14, Karim Liateni wrote:
>
>> 5ÿt5ÿ6hhhyyyfrrtr
>>
>> eschneide...@comcast.net a écrit :
>>
>> >I've been learning python from the website 'inventwithpython.com', and
>> I'm on a chapter that covers the following code:
>>
>
> Just a quick note - not on the algorithm itself. If you run that in some
> IDEs, such as Wing101, all the time.sleep()s will concatenate, and all the
> prints will then print at once with no delay ;') If that happens, run it
> from the command line or try a different IDE.
>
> Jim
> --
>
> "If you don't know it's impossible, it's easier to do." --Neil Gaiman
> "The Process is not the Picture...Reality can only be proved to be
> weakly-objective. Strong objectivity is a myth." --Bernardo Kastrup
> "You cannot use logic to justify logic, so logic itself has no basis other
> than faith." --Agrippa
>
>
> ___
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Re: [Tutor] Beginner question
>But in the code there is a flaw. input() will evaluate your user input.
i.e. If you give an integer >expression it will tell the answer. And when
you provide a number it will take it as int type. See >below.
Hi,
Ignore my above statements if using Python 3. Sorry my bad. Had a doubt and
went to the site to see the version of python used. My statement above is
correct only if run in Python 2 and not in 3.
Regards,
Krishnan
On Mon, Aug 12, 2013 at 11:01 PM, Krishnan Shankar
wrote:
> >def checkCave(chosenCave):
> > print('You approach the cave...')
> >time.sleep(2)
> > print('It is dark and spooky...')
> > time.sleep(2)
> >print('A large dragon jumps out in front of you! He opens his jaws
> and...')
> >print()
> > time.sleep(2)
> >friendlyCave = random.randint(1, 2)
> > if chosenCave == str(friendlyCave):
> > print('Gives you his treasure!')
> > else:
> > print('Gobbles you down in one bite!')
> >playAgain = 'yes'
> >while playAgain == 'yes' or playAgain == 'y':
> >displayIntro()
> >caveNumber = chooseCave()
> >checkCave(caveNumber)
> >print('Do you want to play again? (yes or no)')
> >playAgain = input()
>
> Hi,
>
> - Here we are passing the chosen integer (1 or 2) got from chooseCave()
> method to checkCave as arguement
> - When called in while loop inside checkCave the following happens;
> - The statements of approaching the cave and seeing the dragon are
> printed with a time interval of 2 secs between each
> - Randomly either 1 or 2 is generated by the randint() method of
> random module in python.
> - That randomly generated integer (1 0r 2) is compared with our
> integer input (1 or 2)
> - If they match dragon gives us gold. Or else
> - We will be eaten by dragon :)
>
> But in the code there is a flaw. input() will evaluate your user input.
> i.e. If you give an integer expression it will tell the answer. And when
> you provide a number it will take it as int type. See below.
>
> >>> var = input()
> 1+2+3
> >>> var
> 6
> >>> var = input()
> 2
> >>> type(var)
>
> >>> var = input()
> s
> Traceback (most recent call last):
> File "", line 1, in
> File "", line 1, in
> NameError: name 's' is not defined
> >>> var = input()
>
> So since the integer number is checked with string in Line 13, it will run
> into infinite loop. If you use raw_input() instead of input() you will be
> able to run the example.
>
> Regards,
> Krishnan
>
>
> On Mon, Aug 12, 2013 at 10:25 PM, Jim Mooney wrote:
>
>> On 12 August 2013 02:14, Karim Liateni wrote:
>>
>>> 5ÿt5ÿ6hhhyyyfrrtr
>>>
>>> eschneide...@comcast.net a écrit :
>>>
>>> >I've been learning python from the website 'inventwithpython.com', and
>>> I'm on a chapter that covers the following code:
>>>
>>
>> Just a quick note - not on the algorithm itself. If you run that in some
>> IDEs, such as Wing101, all the time.sleep()s will concatenate, and all the
>> prints will then print at once with no delay ;') If that happens, run it
>> from the command line or try a different IDE.
>>
>> Jim
>> --
>>
>> "If you don't know it's impossible, it's easier to do." --Neil Gaiman
>> "The Process is not the Picture...Reality can only be proved to be
>> weakly-objective. Strong objectivity is a myth." --Bernardo Kastrup
>> "You cannot use logic to justify logic, so logic itself has no basis
>> other than faith." --Agrippa
>>
>>
>> ___
>> Tutor maillist - Tutor@python.org
>> To unsubscribe or change subscription options:
>> http://mail.python.org/mailman/listinfo/tutor
>>
>>
>
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Re: [Tutor] Editing values from a dictionary
Hi Bob,
>>>
In [3]: print metadata["artist"]
[u'The Incredible String Band']
<<<
Here u' and ' is not something you can strip off as it is part of python
datatype called UNICODE. Python prints a word or sentence in double or
singles quotes when it is a STRING or UNICODE in interpreter. These are
python datatypes. And even if there are any whitespaces in your data,
For example: a = [u' The Incredible String Band ']
Here there are leading and trailing spaces in the string which is inside
the LIST. Do a
a[0].strip()
Another thing above is that your string in inside a LIST so to access the
string to strip it, you need to specify the place value as i have done
above.
If you do the above you can get the string as you need it.
And if you dont need a 'u' in front of your string simply convert it to a
string with str() method like below.
>>> s = u'spam'
>>>
>>>
>>> s
u'spam'
>>> type(s)
>>> str(s)
'spam'
>>> type(str(s))
>>>
Regards,
Krishnan
On Wed, Feb 26, 2014 at 10:39 PM, Bob Williams
wrote:
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> Hi List,
>
> I have two problems, but it's possible that one solution will suffice.
> I am using a module called mutagen to extract audio metadata from
> .flac files. The output of mutagen is in the form of a dictionary, so
>
> In [1]: import mutagen.flac
>
> In [2]: metadata = mutagen.flac.Open("/home/bob/music/artists/The
> Incredible String Band/1967 The 5000 Spirits Or The Layers Of The
> Onion/08 The Hedgehog's Song.flac")
>
> In [3]: print metadata["artist"]
> [u'The Incredible String Band']
>
> I now want to pass that string to another program, but I want to strip
> off the leading [u' and the trailing ']. However, this doesn't work:
>
> In [4]: artistName = metadata["artist"][3:-2]
>
> In [5]: print artistName
> []
>
> I was expecting The Incredible String Band, not []
>
> What am I doing wrong? Or what have I misunderstood?
>
> The other problem concerns the program that receives these arguments -
> it complains (and stops with an error) if one the arguments is empty.
> For example, the flac file may not have the date information:
>
> Traceback (most recent call last):
> File "/home/bob/Documents/scripts/python/flac2mp3v2.py", line 81, in
> subprocess.call(['lame', '--add-id3v2',
> '--ignore-tag-errors', '--tt', str(metadata['title']), '--ta',
> str(metadata['artist']), '--tl', str(metadata['album']), '--ty',
> str(metadata['date']), '--tn', str(metadata['tracknumber']), '--tg',
> str(metadata['genre']), tempName1, tempName3])
> File "/usr/lib/python2.7/site-packages/mutagen/__init__.py", line
> 85, in __getitem__
> else: return self.tags[key]
> File "/usr/lib/python2.7/site-packages/mutagen/_vorbis.py", line
> 184, in __getitem__
> if not values: raise KeyError, key
> KeyError: 'date'
>
> If it's possible to edit the string value that gets passed to
> subprocess.call('lame'...) - see problem #1 above, would it also be
> possible to define a default value if the original field is empty?
>
> Bob
> - --
> Bob Williams
> System: Linux 3.11.10-7-desktop
> Distro: openSUSE 13.1 (x86_64) with KDE Development Platform: 4.12.2
> Uptime: 12:00pm up 13 days 20:00, 6 users, load average: 0.10, 0.19, 0.26
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>
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> FToAn2+AcjNKGxJKU+9nE9IdsoEqlQdd
> =JpdC
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