[Tutor] Lock down windows with python+usb
Hi All Has anyone done any script like this? Use a python script for Windows XP that will continuosly check if my USB is plugged in. So if I unplug my USB flashdrive it will fork a screensaver with password lock. Thanks for any idea/suggestion -- Asif Iqbal PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu "...it said: Install Windows XP or better...so I installed Solaris..." ___ Tutor maillist - [EMAIL PROTECTED] http://mail.python.org/mailman/listinfo/tutor
[Tutor] test
Hi All I have a very simple problem and I am looking for the simplest solution. I have a list of elements in a file. I like to find the total occurance of each element in the list like this 10 string1 7 string2 1 string3 from a list which has only string1,string2 and string3 like this string1 .. string2 ... string1 .. string3 ... ... I have a list of 3 lines and I think I have only 615 unique elements. So I like the script not to take too much memory of the system. I will be running it on Solaris 8 Thanks a lot -- Asif Iqbal PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu "..there are two kinds of people: those who work and those who take the credit...try to be in the first group;...less competition there." - Indira Gandhi ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] test
On Fri, Jun 17, 2005 at 07:41:17AM, Chad Crabtree wrote: > How about this. > >>> from random import choice > >>> alist=[choice(range(100)) for x in range(1000)] #just making a How do I do this in python? alist < /tmp/logfile The logfile has the list of entries. -- Asif Iqbal PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu "..there are two kinds of people: those who work and those who take the credit...try to be in the first group;...less competition there." - Indira Gandhi ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] Authen::ACE
Hi All Does anyone know if there is any python module similar to Authen::ACE available that I can use to authenticate against a RSA SecurID server? Also, what would be a good irc chnl where python folks hang around? Thanks -- Asif Iqbal PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu "..there are two kinds of people: those who work and those who take the credit...try to be in the first group;...less competition there." - Indira Gandhi ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] MIME parser
I am looking for a way to feed a message from stdin to a python based mime parser, detach all attachments and drop them to a dir, and then send the email to the recipient. The attachment(s) will be replaced by an URL to a link. So basically decouple the attachments (>1MB in size) and modify the body by inserting an URL in the footer. Has anyone done anything like this? -- Asif Iqbal PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] MIME parser
On Thu, Dec 11, 2008 at 11:49:16AM, Asif Iqbal wrote: > I am looking for a way to feed a message from stdin to a python based > mime parser, detach all attachments and drop them to a dir, and then > send the email to the recipient. The attachment(s) will be replaced > by an URL to a link. > > So basically decouple the attachments (>1MB in size) and modify the > body by inserting an URL in the footer. > > Has anyone done anything like this? > I am looking at email pkg. Now I need to find a way to feed the msg from stdin and then detach all attachments and update the body with urls pointing to attachments > -- Asif Iqbal Google Chat: vad...@gmail.com PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu A: Because it messes up the order in which people normally read text. Q: Why is top-posting such a bad thing? ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] XML parsing
I am trying to extract all the *template-name*s, but no success yet
Here is a sample xml file
http://tail-f.com/ns/rest";>
http://networks.com/nms";>
ALLFLEX-BLOOMINGTON
post-staging
full-mesh
ALLFLEX
http://networks.com/nms";>
advanced-plus
1000
true
true
with open('/tmp/template-metadata') as f:
import xml.etree.ElementTree as ET
root = ET.fromstring(f.read())
print len(root)
print root[0][0].text
for l in root.findall('template-metadata'):
print l
392
ALLFLEX-BLOOMINGTON
It prints the length of the tree and the first element of the first child,
but when I try to loop through to find all the 'template-name's
it does not print anything.
What am I doing wrong?
--
Asif Iqbal
PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
___
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Re: [Tutor] XML parsing
On Thu, Mar 29, 2018 at 3:56 AM, Peter Otten <__pete...@web.de> wrote:
> Asif Iqbal wrote:
>
> > I am trying to extract all the *template-name*s, but no success yet
> >
> > Here is a sample xml file
> >
> > http://tail-f.com/ns/rest";>
> > http://networks.com/nms";>
> > ALLFLEX-BLOOMINGTON
> > post-staging
> > full-mesh
> > ALLFLEX
> > http://networks.com/nms";>
> > advanced-plus
> > 1000
> > true
> > true
> >
> >
> >
> >
> > with open('/tmp/template-metadata') as f:
> > import xml.etree.ElementTree as ET
> > root = ET.fromstring(f.read())
> >
> > print len(root)
> > print root[0][0].text
> > for l in root.findall('template-metadata'):
> > print l
> >
> >
> > 392
> > ALLFLEX-BLOOMINGTON
> >
> >
> > It prints the length of the tree and the first element of the first
> child,
> > but when I try to loop through to find all the 'template-name's
> > it does not print anything.
> >
> > What am I doing wrong?
>
> You have to include the namespace:
>
> for l in root.findall('{http://networks.com/nms}template-metadata'):
>
How do I extract the 'template-name' ?
This is what I tried
for l in root.findall('{http://networks.com/nms}template-metadata'):
print l.find('template-name').text
I am following the doc
https://docs.python.org/2/library/xml.etree.elementtree.html section
19.7.1.3 findall example
I get this error attribute error 'NoneType' object has no attribute text. I
do not understand why l.find('template-name') is NoneType.
Here is complete code with output.
import xml.etree.ElementTree as ET
xmlfile='''
http://tail-f.com/ns/rest";>
http://networks.com/nms";>
ALLFLEX-BLOOMINGTON
post-staging
full-mesh
ALLFLEX
http://networks.com/nms";>
advanced-plus
1000
true
true
'''
root = ET.fromstring(xmlfile)
print root.tag
print root[0][0].text
for l in root.findall('{http://networks.com/nms}template-metadata'):
print l.find('template-name').text
collection
ALLFLEX-BLOOMINGTON
---AttributeError
Traceback (most recent call
last) in () 19 print
root[0][0].text 20 for l in
root.findall('{http://networks.com/nms}template-metadata'):---> 21
print l.find('template-name').text
AttributeError: 'NoneType' object has no attribute 'text'
...
>
>
> ___
> Tutor maillist - Tutor@python.org
> To unsubscribe or change subscription options:
> https://mail.python.org/mailman/listinfo/tutor
>
--
Asif Iqbal
PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
___
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Re: [Tutor] XML parsing
On Thu, Mar 29, 2018 at 3:41 PM, Peter Otten <__pete...@web.de> wrote:
> Asif Iqbal wrote:
>
> > On Thu, Mar 29, 2018 at 3:56 AM, Peter Otten <__pete...@web.de> wrote:
> >
> >> Asif Iqbal wrote:
> >>
> >> > I am trying to extract all the *template-name*s, but no success yet
> >> >
> >> > Here is a sample xml file
> >> >
> >> > http://tail-f.com/ns/rest";>
> >> > http://networks.com/nms";>
> >> > ALLFLEX-BLOOMINGTON
> >> > post-staging
> >> > full-mesh
> >> > ALLFLEX
> >> > http://networks.com/nms";>
> >> > advanced-plus
> >> > 1000
> >> > true
> >> > true
> >> >
> >> >
> >> >
> >> >
> >> > with open('/tmp/template-metadata') as f:
> >> > import xml.etree.ElementTree as ET
> >> > root = ET.fromstring(f.read())
> >> >
> >> > print len(root)
> >> > print root[0][0].text
> >> > for l in root.findall('template-metadata'):
> >> > print l
> >> >
> >> >
> >> > 392
> >> > ALLFLEX-BLOOMINGTON
> >> >
> >> >
> >> > It prints the length of the tree and the first element of the first
> >> child,
> >> > but when I try to loop through to find all the 'template-name's
> >> > it does not print anything.
> >> >
> >> > What am I doing wrong?
> >>
> >> You have to include the namespace:
> >>
> >> for l in root.findall('{http://networks.com/nms}template-metadata'):
> >>
> >
> > How do I extract the 'template-name' ?
>
> I hoped you'd get the idea.
>
> > This is what I tried
> >
> > for l in root.findall('{http://networks.com/nms}template-metadata'):
>
> Rinse and repeat:
>
> > print l.find('template-name').text
>
> should be
>
> print l.find('{http://networks.com/nms}template-name').text
>
> >
> > I am following the doc
> > https://docs.python.org/2/library/xml.etree.elementtree.html section
> > 19.7.1.3 findall example
> >
> > I get this error attribute error 'NoneType' object has no attribute text.
> > I do not understand why l.find('template-name') is NoneType.
>
> Take the time to read
>
> https://docs.python.org/2/library/xml.etree.elementtree.
> html#parsing-xml-with-namespaces
Thanks for the links and hints.
I got it working now
I used ns = { 'nms' : 'http://networks.com/nms
<http://networks.com/nms%7Dtemplate-name').text>' }
And then l.find('nms:template-name', ns)
I also want to extract the namespace and I see this gets me the namespace
str(root[0]).split('{')[1].split('}')[0]
Is there a better way to extract the name space?
>
>
> > Here is complete code with output.
> >
> >
> > import xml.etree.ElementTree as ET
> >
> > xmlfile='''
> > http://tail-f.com/ns/rest";>
> > http://networks.com/nms";>
> > ALLFLEX-BLOOMINGTON
> > post-staging
> > full-mesh
> > ALLFLEX
> > http://networks.com/nms";>
> > advanced-plus
> > 1000
> > true
> > true
> > '''
> >
> > root = ET.fromstring(xmlfile)
> > print root.tag
> > print root[0][0].text
> > for l in root.findall('{http://networks.com/nms}template-metadata'):
> > print l.find('template-name').text
> >
> > collection
> > ALLFLEX-BLOOMINGTON
> >
> >
>
> ---
> AttributeError
> >Traceback (most recent call
> > last) in () 19 print
> > root[0][0].text 20 for l in
> > root.findall('{http://networks.com/nms}template-metadata'):---> 21
> > print l.find('template-name').text
> > AttributeError: 'NoneType' object has no attribute 'text'
>
>
> ___
> Tutor maillist - Tutor@python.org
> To unsubscribe or change subscription options:
> https://mail.python.org/mailman/listinfo/tutor
>
--
Asif Iqbal
PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
___
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Re: [Tutor] XML parsing
On Thu, Mar 29, 2018 at 9:40 PM, Asif Iqbal wrote:
>
>
> On Thu, Mar 29, 2018 at 3:41 PM, Peter Otten <__pete...@web.de> wrote:
>
>> Asif Iqbal wrote:
>>
>> > On Thu, Mar 29, 2018 at 3:56 AM, Peter Otten <__pete...@web.de> wrote:
>> >
>> >> Asif Iqbal wrote:
>> >>
>> >> > I am trying to extract all the *template-name*s, but no success yet
>> >> >
>> >> > Here is a sample xml file
>> >> >
>> >> > http://tail-f.com/ns/rest";>
>> >> > http://networks.com/nms";>
>> >> > ALLFLEX-BLOOMINGTON
>> >> > post-staging
>> >> > full-mesh
>> >> > ALLFLEX
>> >> > http://networks.com/nms";>
>> >> > advanced-plus
>> >> > 1000
>> >> > true
>> >> > true
>> >> >
>> >> >
>> >> >
>> >> >
>> >> > with open('/tmp/template-metadata') as f:
>> >> > import xml.etree.ElementTree as ET
>> >> > root = ET.fromstring(f.read())
>> >> >
>> >> > print len(root)
>> >> > print root[0][0].text
>> >> > for l in root.findall('template-metadata'):
>> >> > print l
>> >> >
>> >> >
>> >> > 392
>> >> > ALLFLEX-BLOOMINGTON
>> >> >
>> >> >
>> >> > It prints the length of the tree and the first element of the first
>> >> child,
>> >> > but when I try to loop through to find all the 'template-name's
>> >> > it does not print anything.
>> >> >
>> >> > What am I doing wrong?
>> >>
>> >> You have to include the namespace:
>> >>
>> >> for l in root.findall('{http://networks.com/nms}template-metadata'):
>> >>
>> >
>> > How do I extract the 'template-name' ?
>>
>> I hoped you'd get the idea.
>>
>> > This is what I tried
>> >
>> > for l in root.findall('{http://networks.com/nms}template-metadata'):
>>
>> Rinse and repeat:
>>
>> > print l.find('template-name').text
>>
>> should be
>>
>> print l.find('{http://networks.com/nms}template-name').text
>>
>> >
>> > I am following the doc
>> > https://docs.python.org/2/library/xml.etree.elementtree.html section
>> > 19.7.1.3 findall example
>> >
>> > I get this error attribute error 'NoneType' object has no attribute
>> text.
>> > I do not understand why l.find('template-name') is NoneType.
>>
>> Take the time to read
>>
>> https://docs.python.org/2/library/xml.etree.elementtree.html
>> #parsing-xml-with-namespaces
>
>
> Thanks for the links and hints.
>
> I got it working now
>
> I used ns = { 'nms' : 'http://networks.com/nms
> <http://networks.com/nms%7Dtemplate-name').text>' }
>
> And then l.find('nms:template-name', ns)
>
> I also want to extract the namespace and I see this gets me the namespace
>
> str(root[0]).split('{')[1].split('}')[0]
>
> Is there a better way to extract the name space?
>
>
>
This worked
ns = { 'nms' : root[0].tag.split('}')[0].split('{')[1] }
for l in root.findall('nms:template-metadata', ns):
print l.find('nms:template-name', ns).text
Although I think manually creating the ns dictionary looks cleaner :-)
>
>>
>>
>> > Here is complete code with output.
>> >
>> >
>> > import xml.etree.ElementTree as ET
>> >
>> > xmlfile='''
>> > http://tail-f.com/ns/rest";>
>> > http://networks.com/nms";>
>> > ALLFLEX-BLOOMINGTON
>> > post-staging
>> > full-mesh
>> > ALLFLEX
>> > http://networks.com/nms";>
>> > advanced-plus
>> > 1000
>> > true
>> > true
>> > '''
>> >
>> > root = ET.fromstring(xmlfile)
>> > print root.tag
>> > print root[0][0].text
>> > for l in root.findall('{http://networks.com/nms}template-metadata'):
>> > print l.find('template-name').text
>> >
>> > collection
>> > ALLFLEX-BLOOMINGTON
>> >
>> >
>>
>> ---
>> AttributeError
>> >Traceback (most recent call
>> > last) in () 19 print
>> > root[0][0].text 20 for l in
>> > root.findall('{http://networks.com/nms}template-metadata'):---> 21
>> > print l.find('template-name').text
>> > AttributeError: 'NoneType' object has no attribute 'text'
>>
>>
>> ___
>> Tutor maillist - Tutor@python.org
>> To unsubscribe or change subscription options:
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>>
>
>
>
> --
> Asif Iqbal
> PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu
> A: Because it messes up the order in which people normally read text.
> Q: Why is top-posting such a bad thing?
>
>
--
Asif Iqbal
PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
___
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[Tutor] Adding a new row to the dataframe with datetime as index
Hi, I am trying to add a new row to a new date in the dataframe like below df.loc['2018-01-24'] = [0,1,2,3,4,5] And I am getting the following error ValueError: cannot set using a list-like indexer with a different length than the value I do have the right number of columns and I can lookup a row by the date df.loc['2018-01-23'] df.shape (8034, 6) df.index DatetimeIndex(['2018-01-23', '2018-01-22', '2018-01-19', '2018-01-18', '2018-01-17', '2018-01-16', '2018-01-12', '2018-01-11', '2018-01-10', '2018-01-09', ... '1986-03-25', '1986-03-24', '1986-03-21', '1986-03-20', '1986-03-19', '1986-03-18', '1986-03-17', '1986-03-14', '1986-03-13', '2018-01-24'], dtype='datetime64[ns]', name='date', length=8034, freq=None) Any idea how to add a new row to a new date? -- Asif Iqbal PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu A: Because it messes up the order in which people normally read text. Q: Why is top-posting such a bad thing? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Adding a new row to the dataframe with datetime as index
On Mon, May 21, 2018 at 9:28 AM, Peter Otten <__pete...@web.de> wrote:
> Asif Iqbal wrote:
>
> > Hi,
> >
> > I am trying to add a new row to a new date in the dataframe like below
> >
> >df.loc['2018-01-24'] = [0,1,2,3,4,5]
> >
> > And I am getting the following error
> >
> > ValueError: cannot set using a list-like indexer with a different
> length
> > than the value
> >
> > I do have the right number of columns and I can lookup a row by the date
> >
> > df.loc['2018-01-23']
> >
> > df.shape
> > (8034, 6)
> >
> > df.index
> > DatetimeIndex(['2018-01-23', '2018-01-22', '2018-01-19', '2018-01-18',
> >'2018-01-17', '2018-01-16', '2018-01-12', '2018-01-11',
> >'2018-01-10', '2018-01-09',
> >...
> >'1986-03-25', '1986-03-24', '1986-03-21', '1986-03-20',
> >'1986-03-19', '1986-03-18', '1986-03-17', '1986-03-14',
> >'1986-03-13', '2018-01-24'],
> > dtype='datetime64[ns]', name='date', length=8034,
> freq=None)
> >
> > Any idea how to add a new row to a new date?
>
> My experiments indicate that there may be multiple values with the same
> key:
>
> > >>> import pandas as pd
> >>> df = pd.DataFrame([[1,2], [3,4], [5,6], [7,8]], index=["a", "b", "a",
> "a"])
> >>> df.loc["a"]
>0 1
> a 1 2
> a 5 6
> a 7 8
>
> [3 rows x 2 columns]
> >>> df.loc["a"] = [10, 20]
> Traceback (most recent call last):
> File "", line 1, in
> File "/usr/lib/python3/dist-packages/pandas/core/indexing.py", line 98,
> in
> __setitem__
> self._setitem_with_indexer(indexer, value)
> File "/usr/lib/python3/dist-packages/pandas/core/indexing.py", line
> 422,
> in _setitem_with_indexer
> self.obj._data = self.obj._data.setitem(indexer, value)
> File "/usr/lib/python3/dist-packages/pandas/core/internals.py", line
> 2396,
> in setitem
> return self.apply('setitem', *args, **kwargs)
> File "/usr/lib/python3/dist-packages/pandas/core/internals.py", line
> 2376,
> in apply
> applied = getattr(blk, f)(*args, **kwargs)
> File "/usr/lib/python3/dist-packages/pandas/core/internals.py", line
> 615,
> in setitem
> raise ValueError("cannot set using a list-like indexer "
> ValueError: cannot set using a list-like indexer with a different length
> than the value
>
> If found two ways to resolve this,
>
> (1) the obvious, ensure that the lengths are the same:
>
> >>> df.loc["a"] = [[10, 20], [30, 40], [50, 60]]
> >>> df
> 0 1
> a 10 20
> b 3 4
> a 30 40
> a 50 60
>
> (2) pass the key as a tuple:
>
> >>> df.loc["a",] = [1000, 2000]
> >>> df
> 0 1
> a 1000 2000
> b 3 4
> a 1000 2000
> a 1000 2000
>
> [4 rows x 2 columns]
>
> I suspect that you want neither, and instead avoid duplicate keys.
I want to overwrite the row
print ( df.loc['2018-01-24'] )
2018-01-24 0.0 1.0 2.0 3.0 4.0 NaN
df.loc['2018-01-24'] = [0,1,2,3,4,5]
ValueError: cannot set using a list-like indexer with a different length
than the value
>
> ___
> Tutor maillist - Tutor@python.org
> To unsubscribe or change subscription options:
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>
--
Asif Iqbal
PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
___
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Re: [Tutor] Adding a new row to the dataframe with datetime as index
On Mon, May 21, 2018 at 4:59 PM, Peter Otten <__pete...@web.de> wrote:
> Asif Iqbal wrote:
>
> > On Mon, May 21, 2018 at 9:28 AM, Peter Otten <__pete...@web.de> wrote:
> >
> >> Asif Iqbal wrote:
> >>
> >> > Hi,
> >> >
> >> > I am trying to add a new row to a new date in the dataframe like below
> >> >
> >> >df.loc['2018-01-24'] = [0,1,2,3,4,5]
> >> >
> >> > And I am getting the following error
> >> >
> >> > ValueError: cannot set using a list-like indexer with a different
> >> length
> >> > than the value
> >> >
> >> > I do have the right number of columns and I can lookup a row by the
> >> > date
> >> >
> >> > df.loc['2018-01-23']
> >> >
> >> > df.shape
> >> > (8034, 6)
> >> >
> >> > df.index
> >> > DatetimeIndex(['2018-01-23', '2018-01-22', '2018-01-19',
> >> > '2018-01-18',
> >> >'2018-01-17', '2018-01-16', '2018-01-12', '2018-01-11',
> >> >'2018-01-10', '2018-01-09',
> >> >...
> >> >'1986-03-25', '1986-03-24', '1986-03-21', '1986-03-20',
> >> >'1986-03-19', '1986-03-18', '1986-03-17', '1986-03-14',
> >> >'1986-03-13', '2018-01-24'],
> >> > dtype='datetime64[ns]', name='date', length=8034,
> >> freq=None)
> >> >
> >> > Any idea how to add a new row to a new date?
> >>
> >> My experiments indicate that there may be multiple values with the same
> >> key:
> >>
> >> > >>> import pandas as pd
> >> >>> df = pd.DataFrame([[1,2], [3,4], [5,6], [7,8]], index=["a", "b",
> "a",
> >> "a"])
> >> >>> df.loc["a"]
> >>0 1
> >> a 1 2
> >> a 5 6
> >> a 7 8
> >>
> >> [3 rows x 2 columns]
> >> >>> df.loc["a"] = [10, 20]
> >> Traceback (most recent call last):
> >> File "", line 1, in
> >> File "/usr/lib/python3/dist-packages/pandas/core/indexing.py", line
> 98,
> >> in
> >> __setitem__
> >> self._setitem_with_indexer(indexer, value)
> >> File "/usr/lib/python3/dist-packages/pandas/core/indexing.py", line
> >> 422,
> >> in _setitem_with_indexer
> >> self.obj._data = self.obj._data.setitem(indexer, value)
> >> File "/usr/lib/python3/dist-packages/pandas/core/internals.py", line
> >> 2396,
> >> in setitem
> >> return self.apply('setitem', *args, **kwargs)
> >> File "/usr/lib/python3/dist-packages/pandas/core/internals.py", line
> >> 2376,
> >> in apply
> >> applied = getattr(blk, f)(*args, **kwargs)
> >> File "/usr/lib/python3/dist-packages/pandas/core/internals.py", line
> >> 615,
> >> in setitem
> >> raise ValueError("cannot set using a list-like indexer "
> >> ValueError: cannot set using a list-like indexer with a different length
> >> than the value
> >>
> >> If found two ways to resolve this,
> >>
> >> (1) the obvious, ensure that the lengths are the same:
> >>
> >> >>> df.loc["a"] = [[10, 20], [30, 40], [50, 60]]
> >> >>> df
> >> 0 1
> >> a 10 20
> >> b 3 4
> >> a 30 40
> >> a 50 60
> >>
> >> (2) pass the key as a tuple:
> >>
> >> >>> df.loc["a",] = [1000, 2000]
> >> >>> df
> >> 0 1
> >> a 1000 2000
> >> b 3 4
> >> a 1000 2000
> >> a 1000 2000
> >>
> >> [4 rows x 2 columns]
> >>
> >> I suspect that you want neither, and instead avoid duplicate keys.
> >
> >
> >
> > I want to overwrite the row
> >
> > print ( df.loc['2018-01-24'] )
> > 2018-01-24 0.0 1.0 2.0 3.0 4.0 NaN
> >
> >
> > df.loc['2018-01-24'] = [0,1,2,3,4,5]
> > ValueError: cannot set using a list-like indexer with a different
> length
> > than the value
>
> Can you post a self-contained example, i. e. a small script that also
> creates a -- hopefully small -- DataFrame and then triggers the ValueError?
>
>
It is working after I ran a df = df.sort_index()
I was looping through new dates and feeding predicted data to new row for
next day, but I was going in the wrong direction.
--
Asif Iqbal
PGP Key: 0xE62693C5 KeyServer: pgp.mit.edu
A: Because it messes up the order in which people normally read text.
Q: Why is top-posting such a bad thing?
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