Re: [Tutor] issues with urllib and loading a webpage
On Wed, 24 Aug 2011, 00:03:23 CEST, Robert Sjoblom wrote: > > > Are you using Python 3 and urllib, and not using httplib2? Because I > > > honestly can't get urllib.request.urlopen to work with > > > http://www.boursorama.com/ -- I only get b'' from there. > > > > Yes, Python 3.2 which version one are you using? I tried both with > > debug and without. > > Python 3.2.1 64 bit on win 32. This is really quite weird. You are running 64bit on a 32bit operating system, did you meant to say 32bit python on win64? If you actually do have 64bit python installed remove it and install the 32bit version. > There > should be something there, because the headers alone doesn't account > for the 7kb that's received. How large is the page when dowloading from the browser? Is it comparable in size? Greets Sander___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] cPickle and shjelving
Hi,
I am new to python. I am having slight issue in using the cPickle and shelving
function.
Here is what i want the program need to do:
Open an file with employees in it with relevant information like: employee
number, surname and department. I also need to add an employee with the
relevant information without rewriting the current data.
I have tried the code but not completely sure what i am doing wrong.
Here is the code that i tried:
# Defines
pickles["employee_num"]
pickle_file = shelve.open("empl.dat")
print "Add new Employee"
employee_num = raw_input("\nEmployee number: ")
surname = raw_input("Surname: ")
name = raw_input("Name: ")
department = raw_input("Department: ")
#Storing DATA #
cPickles.dump(employee_num, emp1.dat)
print key, "-",pickles[key]
pickles.sync () # Makes sure date is written
Can you please help me in solving this issue?
Kind regards
Warren Jones
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Re: [Tutor] cPickle and shjelving
On Wed, Aug 24, 2011 at 11:26 AM, Warren P. Jones wrote:
> Hi,
>
> I am new to python. I am having slight issue in using the cPickle and
> shelving function.
>
> Here is what i want the program need to do:
>
> Open an file with employees in it with relevant information like: employee
> number, surname and department. I also need to add an employee with the
> relevant information without rewriting the current data.
>
> I have tried the code but not completely sure what i am doing wrong.
>
> Here is the code that i tried:
>
> # Defines
> pickles["employee_num"]
>
> pickle_file = shelve.open("empl.dat")
> print "Add new Employee"
> employee_num = raw_input("\nEmployee number: ")
> surname = raw_input("Surname: ")
> name = raw_input("Name: ")
> department = raw_input("Department: ")
>
>
>
> # Storing DATA #
>
>
>
> cPickles.dump(employee_num, emp1.dat)
> print key, "-",pickles[key]
> pickles.sync () # Makes sure date is written
>
> Can you please help me in solving this issue?
>
> Kind regards
>
> Warren Jones
>
That code makes very little sense. The indentation is wrong, and some
variables are never declared. Is that the full code? Also, shelve
already uses cPickle internally, so you don't need to use it
separately. Once you open a shelf, you can use it as a regular
dictionary object afterward:
shelf = shelve.open("empl.dat")
employee_num = raw_input("\nEmployee number: ")
shelf[employee_num] = {
"surname": raw_input("Surname: "),
"name": raw_input("Name: "),
"department": raw_input("Department: ")
}
shelf.close()
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[Tutor] Tutorials on csv module??
Hi everyone, can anyone point me to a good tutorial on using the csv module? also, is there a module that can help me check data in a excel file other than the csv module? thanks a lot khaild ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Tutorials on csv module??
Khalid Al-Ghamdi wrote: Hi everyone, can anyone point me to a good tutorial on using the csv module? Search engines are a wonderful thing. http://duckduckgo.com/?q=python+csv+tutorial also, is there a module that can help me check data in a excel file other than the csv module? http://duckduckgo.com/?q=python+excel http://duckduckgo.com/?q=python+xls Try the xlwt and xlrd libraries. http://www.python-excel.org/ -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] eval func with floating...
> > If the user ever sees an AssertionError, your code is buggy. > Well you saw that I caught the AssertionError, so the user wouldn't technically see it. For the other stuff, I didn't know the etiquette for assertion statements. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Speech
how do you unzip a gz on windows? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Speech
On 24/08/11 18:09, Christopher King wrote: how do you unzip a gz on windows? Pretty much any zip tool (Qzip, Winzip etc) will handle gz files too. -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Speech
On Tue, Aug 23, 2011 at 8:46 PM, Alex Hall wrote: > Depending on what you want, you could try accessible_output. It requires platform_utils. Anything else? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Syntax error with if statement
Hello, I haven't been programming for a while and today I am working on something and have encountered an error I cannot figure out. Here is my code: thisFile = column[6] if thisFile == "/Images/My%20Face.JPG" CallCount += 1 print CallCount And here is the error message: ray@RaysComputer:~$ python /home/ray/EmailCount/CountEmails.py File "/home/ray/EmailCount/CountEmails.py", line 41 if thisFile == "/Images/My%20Face.JPG" ^ SyntaxError: invalid syntax Any help you can be will be much appreciated. Later, Ray Parrish -- The Unknown Lead Player, Ray Parrish http://www.facebook.com/pages/The-Unknown-Lead-Player/123388551041130?sk=wall Linux dpkg Software Report script set.. http://www.rayslinks.com/LinuxdpkgSoftwareReport.html Ray's Links, a variety of links to usefull things, and articles by Ray. http://www.rayslinks.com Writings of "The" Schizophrenic, what it's like to be a schizo, and other things, including my poetry. http://www.writingsoftheschizophrenic.com ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Syntax error with if statement
On Wed, Aug 24, 2011 at 7:40 PM, Ray Parrish wrote: > Hello, > > I haven't been programming for a while and today I am working on something > and have encountered an error I cannot figure out. > > Here is my code: > > thisFile = column[6] > if thisFile == "/Images/My%20Face.JPG" > CallCount += 1 > print CallCount > > And here is the error message: > > ray@RaysComputer:~$ python /home/ray/EmailCount/**CountEmails.py > File "/home/ray/EmailCount/**CountEmails.py", line 41 >if thisFile == "/Images/My%20Face.JPG" > ^ > SyntaxError: invalid syntax > > Any help you can be will be much appreciated. > There has to be a : at the end of an if statement, or more generally, any statement that is to be followed by an indented block. -- André Engels, andreeng...@gmail.com ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Python Speech
On 08/24/2011 10:17 AM, Alan Gauld wrote: On 24/08/11 18:09, Christopher King wrote: how do you unzip a gz on windows? Pretty much any zip tool (Qzip, Winzip etc) will handle gz files too. 7 zip works great on Windows for most formats. http://www.7-zip.org/ Jeff --- Jeff Johnson j...@dcsoftware.com ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] help with a class
Hello, I have a class that has an attribute that is a dict which I
fill with more dicts. I've created a function to return those
dictionaries if a key is provide, otherwise, it returns the 'default'
dictionary.
I have the following methods (see below), it seems the update_options
method is fine, but I'm not sure about the override_options method...
and for that matter, I'm not sure this is the best approach overall...
any comments, critiques?
Thank you,
john
class Runner(object):
""" Initiate with an optional dictionary of settings.
Defaults are set in the options dictionary, which can be overridden.
"""
# Simplest default:
default_options = {
'file' : '../data/input.dat',
'wavelength' : '310.0 310.0'
}
def __init__(self, **kwargs):
if 'options' not in kwargs:
self.options = copy(self.default_options)
self.run_queue = {}
def _get_from_queue(self, queue_key):
""" internal method to set options """
if queue_key:
if queue_key not in self.run_queue:
raise ValueError('queue_key: {0} not in
queue'.format(queue_key))
else:
return self.run_queue[queue_key]
else:
return self.options
def update_options(self, options, queue_key=None):
""" update the options dictionary using a dict """
assert isinstance(options, dict), "update options requires a dict"
old_options = self._get_from_queue(queue_key)
old_options.update(options)
def overide_options(self, options, queue_key=None):
""" completely overide the options dict """
assert isinstance(options, dict), "override options requires a dict"
old_options = self._get_from_queue(queue_key)
old_options = options
--
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Re: [Tutor] help with a class
On Wed, Aug 24, 2011 at 8:34 PM, John wrote: > Hello, I have a class that has an attribute that is a dict which I > fill with more dicts. I've created a function to return those > dictionaries if a key is provide, otherwise, it returns the 'default' > dictionary. > > I have the following methods (see below), it seems the update_options > method is fine, but I'm not sure about the override_options method... > and for that matter, I'm not sure this is the best approach overall... > any comments, critiques? > You've identified the problem point correctly, override_options will not work as expected. What it does is: 1) retrieve a dict through _get_from_queue() 2) point the name old_options toward that dict 3) point the name old_options toward a different dict (the one that options points to) as you can see, the dict that is inside self.run_queue isn't actually changed just by making old_options point towards the new dict. What you need to do is actually assign the new dict to the place in the queue, like so: self.run_queue[queue_key] = options of course, this will also just create a new entry in the dict if there wasn't one previously, which isn't exactly an 'override.' So if you want that behavior, check for it and raise an error by yourself. One other thing, inside _get_from_queue(). If a key isn't present in a dictionary, you generally raise a KeyError, not a ValueError. A ValueError is for when a function argument is of the correct type, but has an inappropriate value, and the error isn't more accurately described by another exception like an IndexError. For example, math.sqrt(-1) raises a ValueError because negative numbers don't make sense for square roots, even though the argument is of the correct type (yes, the math module doesn't have support for imaginary numbers built in, even though the language does ಠ_ಠ There is cmath though). ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] help with a class
Thank you. I've corrected the KeyError, and changed the function to: def overide_options(self, options, run_id=None): """ completely overide the options dict """ assert isinstance(options, dict), "override options requires a dict" if run_id in self.run_queue: self.run_queue[run_id] = options else: self.options = options ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] help with a class
I was under the impression that asserts are more for testing than for
production code (especially since they can be removed when running from python
from command line). Instead I removed the assert and replaced it to raise an
error.
def overide_options(self, options, run_id=None):
""" completely overide the options dict """
if not isinstance(options, dict):
raise TypeError("override options requires a dict")
if run_id in self.run_queue:
self.run_queue[run_id] = options
else:
self.options = options
Do you really care if it is a dict versus defaultdict or something else that is
dict-like? This will fail if I pass in a dict-like class (i.e. if I wrote dict
from scratch) that does not inherit from dict.
Ramit
Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
712 Main Street | Houston, TX 77002
work phone: 713 - 216 - 5423
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Re: [Tutor] help with a class
On 24/08/11 21:03, Prasad, Ramit wrote:
I was under the impression that asserts are more for testing
> than for production code
That's true.
def overide_options(self, options, run_id=None):
if not isinstance(options, dict):
raise TypeError("override options requires a dict")
This is good if you want to keep the check in for production.
But using an assert here while testing then removing it from production
would be a valid use too. The typecheck is not required for the function
to work if you are confident of the data being passed in. assert checks
the data while you are gaining that confidence.
So either approach is valid.
It all depends on how variable your input data is going to be.
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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Re: [Tutor] Python Speech
I got the speech module to work actually, except for input. Only say works. Here's a traceback on speech.input. Traceback (most recent call last): File "C:\Python26\test.py", line 6, in print speech.input() File "C:\Python26\speech.py", line 162, in input listener = listenforanything(response) File "C:\Python26\speech.py", line 193, in listenforanything return _startlistening(None, callback) File "C:\Python26\speech.py", line 222, in _startlistening context = _recognizer.CreateRecoContext() File "C:\Python26\lib\site-packages\win32com\gen_py\C866CA3A-32F7-11D2-9602-00 C04F8EE628x0x5x0.py", line 2457, in CreateRecoContext ret = self._oleobj_.InvokeTypes(10, LCID, 1, (9, 0), (),) com_error: (-2147352567, 'Exception occurred.', (0, None, None, None, 0, -214722 1164), None) ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Confirmation if command worked
Hi all,
I have the following code that uses pexpect to execute a system command. My
problem is, I don't know how to identify if the command was successfully
executed.
The code works as it is to execute the SCP command, but it executes
regardless if the SCP session can actually connect to something.
Thanks
def doScp(files):
logger.log("Files to get: " + `files`)
fNames = ' '.join(files)
cmd = 'scp %s %s@%s:%s%s' % (fNames,
SCP_USERNAME,
SCP_HOST,
SCP_IMG_FILE_DIR,
SCP_IMG_FILE_PATH)
logger.log("Sending: " + cmd)
child = pexpect.spawn(cmd)
i = child.expect(['assword:', 'yes/no'], timeout=30)
if i == 0:
child.sendline(SCP_PASSWD)
elif i == 1:
child.sendline("yes")
child.expect("assword:", timeout=30)
child.sendline(SCP_PASSWD)
data = child.read()
if data != None:
success = True
else:
success = False
child.close()
logger.log("Files sent to SCP host")
return success
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Re: [Tutor] Confirmation if command worked
On 2011/08/25 07:51 AM, Johan Geldenhuys wrote:
Hi all,
I have the following code that uses pexpect to execute a system command. My
problem is, I don't know how to identify if the command was successfully
executed.
The code works as it is to execute the SCP command, but it executes
regardless if the SCP session can actually connect to something.
Thanks
def doScp(files):
logger.log("Files to get: " + `files`)
fNames = ' '.join(files)
cmd = 'scp %s %s@%s:%s%s' % (fNames,
SCP_USERNAME,
SCP_HOST,
SCP_IMG_FILE_DIR,
SCP_IMG_FILE_PATH)
logger.log("Sending: " + cmd)
child = pexpect.spawn(cmd)
i = child.expect(['assword:', 'yes/no'], timeout=30)
if i == 0:
child.sendline(SCP_PASSWD)
elif i == 1:
child.sendline("yes")
child.expect("assword:", timeout=30)
child.sendline(SCP_PASSWD)
data = child.read()
if data != None:
success = True
else:
success = False
child.close()
logger.log("Files sent to SCP host")
return success
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Once you call child.close() the exit and signal status will be stored in
.exitstatus and .signalstatus, for a normal exit of the program
.exitstatus will store the return code from SCP as per [1] [2] [3] and
.signalstatus will be None. If SCP was terminated with a signal then
.exitstatus will be None and .signalstatus will contain the signal
value. Info found in the docs [4].
So the changes to your code will be:
data = child.read()
child.close()
if child.exitstatus and child.exitstatus == 0:
success = True
else:
success = False
I'll leave putting in handling of failed error codes and abnormal
termination to you.
[1] http://support.attachmate.com/techdocs/2116.html
[2] http://support.attachmate.com/techdocs/2487.html
[3] http://support.attachmate.com/techdocs/2285.html
[4] http://pexpect.sourceforge.net/pexpect.html
--
Christian Witts
Python Developer
//
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Re: [Tutor] Confirmation if command worked
Hi Christian,
Thanks for that. I'll give it a shot and see if I can catch the error.
Lekker dag
Johan
From: Christian Witts [mailto:cwi...@compuscan.co.za]
Sent: Thursday, 25 August 2011 4:25 PM
To: Johan Geldenhuys
Cc: tutor@python.org
Subject: Re: [Tutor] Confirmation if command worked
On 2011/08/25 07:51 AM, Johan Geldenhuys wrote:
Hi all,
I have the following code that uses pexpect to execute a system command. My
problem is, I don't know how to identify if the command was successfully
executed.
The code works as it is to execute the SCP command, but it executes
regardless if the SCP session can actually connect to something.
Thanks
def doScp(files):
logger.log("Files to get: " + `files`)
fNames = ' '.join(files)
cmd = 'scp %s %s@%s:%s%s' % (fNames,
SCP_USERNAME,
SCP_HOST,
SCP_IMG_FILE_DIR,
SCP_IMG_FILE_PATH)
logger.log("Sending: " + cmd)
child = pexpect.spawn(cmd)
i = child.expect(['assword:', 'yes/no'], timeout=30)
if i == 0:
child.sendline(SCP_PASSWD)
elif i == 1:
child.sendline("yes")
child.expect("assword:", timeout=30)
child.sendline(SCP_PASSWD)
data = child.read()
if data != None:
success = True
else:
success = False
child.close()
logger.log("Files sent to SCP host")
return success
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Once you call child.close() the exit and signal status will be stored in
.exitstatus and .signalstatus, for a normal exit of the program .exitstatus
will store the return code from SCP as per [1] [2] [3] and .signalstatus
will be None. If SCP was terminated with a signal then .exitstatus will be
None and .signalstatus will contain the signal value. Info found in the
docs [4].
So the changes to your code will be:
data = child.read()
child.close()
if child.exitstatus and child.exitstatus == 0:
success = True
else:
success = False
I'll leave putting in handling of failed error codes and abnormal
termination to you.
[1] http://support.attachmate.com/techdocs/2116.html
[2] http://support.attachmate.com/techdocs/2487.html
[3] http://support.attachmate.com/techdocs/2285.html
[4] http://pexpect.sourceforge.net/pexpect.html
--
Christian Witts
Python Developer
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