[Tutor] Good Book

[Ryan]

Dear All Pythonist,

I'm strarting learn python programming and I have been found many resources
on it but I have a problem. I don't know, what is the best complete book for
new learner like me.

I need your recommendation, thanks before . . .

-- 
It is no more than the conspiracy of 0 and 1
[decrypthor]
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Re: [Tutor] Good Book

[Peter Lavelle]

There's a free ebook aimed at beginners here:http://inventwithpython.com/

Regards

Peter Lavelle


On 18/07/11 09:26, Ryan wrote:

Dear All Pythonist,

I'm strarting learn python programming and I have been found many 
resources on it but I have a problem. I don't know, what is the best 
complete book for new learner like me.


I need your recommendation, thanks before . . .

--
It is no more than the conspiracy of 0 and 1
[decrypthor]


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--
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Twitter: http://twitter.com/pmjlavelle

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Re: [Tutor] Good Book

[Neo Exodus]

Ok, thank you All . . .

On Mon, Jul 18, 2011 at 3:36 PM, Peter Lavelle  wrote:

> **
> There's a free ebook aimed at beginners here:http://inventwithpython.com/
>
> Regards
>
> Peter Lavelle
>
>
>
> On 18/07/11 09:26, Ryan wrote:
>
> Dear All Pythonist,
>
>  I'm strarting learn python programming and I have been found many
> resources on it but I have a problem. I don't know, what is the best
> complete book for new learner like me.
>
>  I need your recommendation, thanks before . . .
>
> --
> It is no more than the conspiracy of 0 and 1
> [decrypthor]
>
>
> ___
> Tutor maillist  -  Tutor@python.org
>
> To unsubscribe or change subscription 
> options:http://mail.python.org/mailman/listinfo/tutor
>
>
>
> --
> LinkedIn Profile: http://linkedin.com/in/pmjlavelle
> Twitter: http://twitter.com/pmjlavelle
>
>


-- 
It is no more than the conspiracy of 0 and 1
[decrypthor]
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Re: [Tutor] Good Book

[Alan Gauld]

Ryan wrote:


I'm strarting learn python programming and I have been found many resources
on it but I have a problem. I don't know, what is the best complete book for
new learner like me.


There are lots of books, both paper and electronic.
It depends on eactly what yopu want.

Can you already program in another language? If so,
the standard Python tutorial may be sufficient? If
not, one of the non-programmers tutorials
(like mine :-) will be better.

Personally I wouldn't recommed buyoing a paper book
until after you have learned the basics. Then you can
decide if you want a general reference (Python in a
Nutshell for example) or a specialist text like
Python Network Programming, say.

The Python.org site has many tutorials, in all
manner of styles, it just depends what kind of
tutorial you like.

Ａｌａｎ　Ｇ

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Re: [Tutor] Good Book

[sefa yıldız]

i think, this  is good
book for you. (this  is
pdf version )
and also a few sources:
http://www.freenetpages.co.uk/hp/alan.gauld/
http://diveintopython.org/toc/index.html
http://www.mindview.net/Books/TIPyhttp://www.mindview.net/Books/TIPythonthon
http://directory.google.com/Top/Computers/Programming/Languages/Python/FAQs,_Help,_and_Tutorials/

2011/7/18 Ryan 

> Dear All Pythonist,
>
> I'm strarting learn python programming and I have been found many resources
> on it but I have a problem. I don't know, what is the best complete book for
> new learner like me.
>
> I need your recommendation, thanks before . . .
>
> --
> It is no more than the conspiracy of 0 and 1
> [decrypthor]
>
>
> ___
> Tutor maillist  -  Tutor@python.org
> To unsubscribe or change subscription options:
> http://mail.python.org/mailman/listinfo/tutor
>
>
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Re: [Tutor] Good Book

[Lisi]

On Monday 18 July 2011 09:26:51 Ryan wrote:
> Dear All Pythonist,
>
> I'm strarting learn python programming and I have been found many resources
> on it but I have a problem. I don't know, what is the best complete book
> for new learner like me.
>
> I need your recommendation, thanks before . . .

I am using Learn Python The Hard Way by Zed A Shaw;

http://learnpythonthehardway.org/

It is basic - assumes no knowledge of programming at all and is easy to 
follow.  But as a beginning beginner myself, I find that I do most of my 
actual learning from the marvellous people on this list, with help also from 
my local Linux User Group.  The book provides the exercises and structure.

But, as has been said, your choice will depend on your own style.

Lisi
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Re: [Tutor] Good Book

[Surya P.K. Kasturi]

Actually you have a lot of books that have been quoted in www.python.org.
One of them is ThinkPython book at www.thinkpython.org. Its really good.
You'll also find exercises at the end of units.


On Mon, Jul 18, 2011 at 1:56 PM, Ryan  wrote:

> Dear All Pythonist,
>
> I'm strarting learn python programming and I have been found many resources
> on it but I have a problem. I don't know, what is the best complete book for
> new learner like me.
>
> I need your recommendation, thanks before . . .
>
> --
> It is no more than the conspiracy of 0 and 1
> [decrypthor]
>
>
> ___
> Tutor maillist  -  Tutor@python.org
> To unsubscribe or change subscription options:
> http://mail.python.org/mailman/listinfo/tutor
>
>
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[Tutor] getting error while solving a series that estimates the value of pi

[surya k]

Hi,

The problem is to estimate the value of pi using the following series.
 *1 / pi  = (( 2 * sqrt(2) )/ 9801 )  * SIGMA of k[ (4k)! (1103 + 26390*k) /
(k!^ 4 ) * 396^(4k)  ]*
*where k is [0, infinity)*
* Problem is located at : ThinkPython Book, www.thinkpython.org
   *Pg 89, Exercise 7.5, Think Python Book. *
*
*
the series should be considered till the last term of the sigma must be <
1e-15
I have written the below code :

*# program estimates the value of pi*
*# Ramanujan's series... *
*import math*
*
*
*def fact(n) : # def of factorial function.*
*if n > 0 :*
*   return n * fact(n-1)*
*if n == 0 :*
*   return 1*
*
*
*k = 0*
*tot = 0*
*temp1 = 0*
*while k >= 0 and temp1 == 0 :*
*
*
*  a = ( 2 * math.sqrt(2) ) / 9801 # first term before sigma *
*  nu = fact (4*k) * (1103 + (26390*k) )  # numerator of series*
*  de = pow( fact(k), 4 ) * pow ( 396, 4*k )  # denominator of series*
*  *
*  if de / nu > 1e-15 : *
*temp = nu / de*
*tot = tot + temp*
*temp1 = 0 *
*k = k + 1 *
*  elif de / nu  == 1e-15 :*
* series = a * tot  *
* k = k + 1*
* temp1 = 0*
*  elif de / nu < 1e-15 :*
* print series*
* temp1 = 1*


I am getting the following error : which is completely surprising!

*Traceback (most recent call last):*
*  File "pi.py", line 30, in *
*print series*
*NameError: name 'series' is not defined*

*
*
Thus I have removed name 'series' and replaced with  *a*tot, *
now I am getting this error

*Traceback (most recent call last):*
*  File "pi.py", line 30, in *
*print 1 / (a * tot)*
*ZeroDivisionError: float divisio*n



Thus I changed the first highlighted lines to

 *nu = float (fact (4*k) * (1103 + (26390*k) ) )*
*  de = float (pow( fact(k), 4 ) * pow ( 396, 4*k )) *


now I am getting

* Traceback (most recent call last):*
*  File "pi.py", line 18, in *
*de = float (pow( fact(k), 4 ) * pow ( 396, 4*k ) )*
*OverflowError: long int too large to convert to float*

*help me out of this problem, how could I fix this*
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Re: [Tutor] getting error while solving a series that estimates the value of pi

[Andre Engels]

On Mon, Jul 18, 2011 at 6:10 PM, surya k  wrote:

> Hi,
>
> The problem is to estimate the value of pi using the following series.
>  *1 / pi  = (( 2 * sqrt(2) )/ 9801 )  * SIGMA of k[ (4k)! (1103 + 26390*k)
> / (k!^ 4 ) * 396^(4k)  ]*
> *where k is [0, infinity)*
> * Problem is located at : ThinkPython Book, www.thinkpython.org
>*Pg 89, Exercise 7.5, Think Python Book. *
> *
> *
> the series should be considered till the last term of the sigma must be <
> 1e-15
> I have written the below code :
>
> *# program estimates the value of pi*
> *# Ramanujan's series... *
> *import math*
> *
> *
> *def fact(n) : # def of factorial function.*
> *if n > 0 :*
> *   return n * fact(n-1)*
> *if n == 0 :*
> *   return 1*
> *
> *
> *k = 0*
> *tot = 0*
> *temp1 = 0*
> *while k >= 0 and temp1 == 0 :*
> *
> *
> *  a = ( 2 * math.sqrt(2) ) / 9801 # first term before sigma *
> *  nu = fact (4*k) * (1103 + (26390*k) )  # numerator of series*
> *  de = pow( fact(k), 4 ) * pow ( 396, 4*k )  # denominator of series*
> *  *
> *  if de / nu > 1e-15 : *
> *temp = nu / de*
> *tot = tot + temp*
> *temp1 = 0 *
> *k = k + 1 *
> *  elif de / nu  == 1e-15 :*
> * series = a * tot  *
> * k = k + 1*
> * temp1 = 0*
> *  elif de / nu < 1e-15 :*
> * print series*
> * temp1 = 1*
>
>
> I am getting the following error : which is completely surprising!
>
> *Traceback (most recent call last):*
> *  File "pi.py", line 30, in *
> *print series*
> *NameError: name 'series' is not defined*
>
> *
> *
> Thus I have removed name 'series' and replaced with  *a*tot, *
> now I am getting this error
>
> *Traceback (most recent call last):*
> *  File "pi.py", line 30, in *
> *print 1 / (a * tot)*
> *ZeroDivisionError: float divisio*n
>
>
>
> Thus I changed the first highlighted lines to
>
>  *nu = float (fact (4*k) * (1103 + (26390*k) ) )*
> *  de = float (pow( fact(k), 4 ) * pow ( 396, 4*k )) *
>
>
> now I am getting
>
> * Traceback (most recent call last):*
> *  File "pi.py", line 18, in *
> *de = float (pow( fact(k), 4 ) * pow ( 396, 4*k ) )*
> *OverflowError: long int too large to convert to float*
>
> *help me out of this problem, how could I fix this*
>
>
You have the definitions of numerator and denominator switched.

-- 
André Engels, andreeng...@gmail.com
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Re: [Tutor] getting error while solving a series that estimates the value of pi

[Alan Gauld]

surya k wrote:


*k = 0*
*tot = 0*
*temp1 = 0*
*while k >= 0 and temp1 == 0 :*
*  a = ( 2 * math.sqrt(2) ) / 9801 # first term before sigma *
*  nu = fact (4*k) * (1103 + (26390*k) )  # numerator of series*
*  de = pow( fact(k), 4 ) * pow ( 396, 4*k )  # denominator of series*
*  *
*  if de / nu > 1e-15 : *
*temp = nu / de*
*tot = tot + temp*
*temp1 = 0 *
*k = k + 1 *
*  elif de / nu  == 1e-15 :*
* series = a * tot  *


Note that this is the only place you ever define series


* k = k + 1*
* temp1 = 0*
*  elif de / nu < 1e-15 :*
* print series*


So if you ever get here without de/nu having previously been *exactly* 
1e-15 (which is pretty likely IMHO) you will get a name error.



* temp1 = 1*


I am getting the following error : which is completely surprising!

*Traceback (most recent call last):*
*  File "pi.py", line 30, in *
*print series*
*NameError: name 'series' is not defined*


Doesn't surprise me at all...


Thus I have removed name 'series' and replaced with  *a*tot, *
now I am getting this error


This is known as "poke 'n hope" debugging.
Better to work out why you got the previous error
message and fix it there. print statements are
your friend

HTH,

Alan G,
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Re: [Tutor] getting error while solving a series that estimates the value of pi

[James Reynolds]

On Mon, Jul 18, 2011 at 12:10 PM, surya k  wrote:

> Hi,
>
> The problem is to estimate the value of pi using the following series.
>  *1 / pi  = (( 2 * sqrt(2) )/ 9801 )  * SIGMA of k[ (4k)! (1103 + 26390*k)
> / (k!^ 4 ) * 396^(4k)  ]*
> *where k is [0, infinity)*
> * Problem is located at : ThinkPython Book, www.thinkpython.org
>*Pg 89, Exercise 7.5, Think Python Book. *
> *
> *
> the series should be considered till the last term of the sigma must be <
> 1e-15
> I have written the below code :
>
> *# program estimates the value of pi*
> *# Ramanujan's series... *
> *import math*
> *
> *
> *def fact(n) : # def of factorial function.*
> *if n > 0 :*
> *   return n * fact(n-1)*
> *if n == 0 :*
> *   return 1*
> *
> *
> *k = 0*
> *tot = 0*
> *temp1 = 0*
> *while k >= 0 and temp1 == 0 :*
> *
> *
> *  a = ( 2 * math.sqrt(2) ) / 9801 # first term before sigma *
> *  nu = fact (4*k) * (1103 + (26390*k) )  # numerator of series*
> *  de = pow( fact(k), 4 ) * pow ( 396, 4*k )  # denominator of series*
> *  *
> *  if de / nu > 1e-15 : *
> *temp = nu / de*
> *tot = tot + temp*
> *temp1 = 0 *
> *k = k + 1 *
> *  elif de / nu  == 1e-15 :*
> * series = a * tot  *
> * k = k + 1*
> * temp1 = 0*
> *  elif de / nu < 1e-15 :*
> * print series*
> * temp1 = 1*
>
>
> I am getting the following error : which is completely surprising!
>
> *Traceback (most recent call last):*
> *  File "pi.py", line 30, in *
> *print series*
> *NameError: name 'series' is not defined*
>
> *
> *
> Thus I have removed name 'series' and replaced with  *a*tot, *
> now I am getting this error
>
> *Traceback (most recent call last):*
> *  File "pi.py", line 30, in *
> *print 1 / (a * tot)*
> *ZeroDivisionError: float divisio*n
>
>
>
> Thus I changed the first highlighted lines to
>
>  *nu = float (fact (4*k) * (1103 + (26390*k) ) )*
> *  de = float (pow( fact(k), 4 ) * pow ( 396, 4*k )) *
>
>
> now I am getting
>
> * Traceback (most recent call last):*
> *  File "pi.py", line 18, in *
> *de = float (pow( fact(k), 4 ) * pow ( 396, 4*k ) )*
> *OverflowError: long int too large to convert to float*
>
> *help me out of this problem, how could I fix this*
>
> ___
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>
>


I am getting the following error : which is completely surprising!


You only define "series" when nu/de == XXX. Just don't print series outside
of where it is defined, or print it outside of the while loop if you can be
assured it is defined when the while loop ends.

Even so, you would still end up with the overflow error, because you have de
/ nu and I'm assuming you want nu / de. As an aside, you might want to
consider creating a variable above all the if statements called nude = nu /
de and replace all of the nu / de 's to nude. This way you only divide once
and not (potentially) three times per loop.
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Re: [Tutor] getting error while solving a series that estimates the value of pi

[surya k]

Let me write the code again..
Thanks for your help.

On Mon, Jul 18, 2011 at 10:38 PM, James Reynolds  wrote:

>
>
> On Mon, Jul 18, 2011 at 12:10 PM, surya k  wrote:
>
>> Hi,
>>
>> The problem is to estimate the value of pi using the following series.
>>  *1 / pi  = (( 2 * sqrt(2) )/ 9801 )  * SIGMA of k[ (4k)! (1103 +
>> 26390*k) / (k!^ 4 ) * 396^(4k)  ]*
>> *where k is [0, infinity)*
>> * Problem is located at : ThinkPython Book, www.thinkpython.org
>>*Pg 89, Exercise 7.5, Think Python Book. *
>> *
>> *
>> the series should be considered till the last term of the sigma must be <
>> 1e-15
>> I have written the below code :
>>
>> *# program estimates the value of pi*
>> *# Ramanujan's series... *
>> *import math*
>> *
>> *
>> *def fact(n) : # def of factorial function.*
>> *if n > 0 :*
>> *   return n * fact(n-1)*
>> *if n == 0 :*
>> *   return 1*
>> *
>> *
>> *k = 0*
>> *tot = 0*
>> *temp1 = 0*
>> *while k >= 0 and temp1 == 0 :*
>> *
>> *
>> *  a = ( 2 * math.sqrt(2) ) / 9801 # first term before sigma *
>> *  nu = fact (4*k) * (1103 + (26390*k) )  # numerator of series*
>> *  de = pow( fact(k), 4 ) * pow ( 396, 4*k )  # denominator of series
>> *
>> *  *
>> *  if de / nu > 1e-15 : *
>> *temp = nu / de*
>> *tot = tot + temp*
>> *temp1 = 0 *
>> *k = k + 1 *
>> *  elif de / nu  == 1e-15 :*
>> * series = a * tot  *
>> * k = k + 1*
>> * temp1 = 0*
>> *  elif de / nu < 1e-15 :*
>> * print series*
>> * temp1 = 1*
>>
>>
>> I am getting the following error : which is completely surprising!
>>
>> *Traceback (most recent call last):*
>> *  File "pi.py", line 30, in *
>> *print series*
>> *NameError: name 'series' is not defined*
>>
>> *
>> *
>> Thus I have removed name 'series' and replaced with  *a*tot, *
>> now I am getting this error
>>
>> *Traceback (most recent call last):*
>> *  File "pi.py", line 30, in *
>> *print 1 / (a * tot)*
>> *ZeroDivisionError: float divisio*n
>>
>>
>>
>> Thus I changed the first highlighted lines to
>>
>>  *nu = float (fact (4*k) * (1103 + (26390*k) ) )*
>> *  de = float (pow( fact(k), 4 ) * pow ( 396, 4*k )) *
>>
>>
>> now I am getting
>>
>> * Traceback (most recent call last):*
>> *  File "pi.py", line 18, in *
>> *de = float (pow( fact(k), 4 ) * pow ( 396, 4*k ) )*
>> *OverflowError: long int too large to convert to float*
>>
>> *help me out of this problem, how could I fix this*
>>
>> ___
>> Tutor maillist  -  Tutor@python.org
>> To unsubscribe or change subscription options:
>> http://mail.python.org/mailman/listinfo/tutor
>>
>>
>
>
> I am getting the following error : which is completely surprising!
>
>
> You only define "series" when nu/de == XXX. Just don't print series outside
> of where it is defined, or print it outside of the while loop if you can be
> assured it is defined when the while loop ends.
>
> Even so, you would still end up with the overflow error, because you have
> de / nu and I'm assuming you want nu / de. As an aside, you might want to
> consider creating a variable above all the if statements called nude = nu /
> de and replace all of the nu / de 's to nude. This way you only divide once
> and not (potentially) three times per loop.
>
>
>
>
>
>
>
>
>
>
>
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