Re: [Tutor] Need some help on output
I am beginner...I want to know best book to start with when it comes with python programming ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Need some help on output
That depends on what your motivation is for learning python. I'd start
with a few hello world tutorial online. like print "hello world"/
python 3.0 print("hello world"), and on that not, decide on the
version you want to use on your system first.
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Re: [Tutor] How to extract data from text to excel?
bug in the previous code so the final code should be:
import xlwt
"""Reads robert.txt
This is the final script that writes by incrementing each row but maintain
one column"""
# Create workbook and worksheet
wbk = xlwt.Workbook()
sheet = wbk.add_sheet('python')
row = 0 # row counter
f = open('robert.txt')
for line in f:
L = line.strip()
print L
for c in L:
print c
sheet.write(row,0,c)
row += 1
wbk.save('reformatted.data.xls')
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[Tutor] Book Request [Was: Re: Need some help on output]
"Gaurav Malhotra" wrote I am beginner... Welcome. But when posting messages please start a new thread do not use an existing one. Otherwise your message is likely to be missed by anyone not reading the previous subject. I want to know best book to start with when it comes with python programming Books/tutorials are very subjective. The style of tutorial that I like may not suit you. That having been said: Are you a beginner to Python? Or a beginner to programming? There are beginners pages for both categories on the python.org web site that list online tutorials. Choose a few and try them out, they are all free. One thing you will need to decide is whether to learn the latest Python Version 3 or to use the older Python Version 2. They are not compatible and thee is more widespread support for V2, but V3 iscatching up. For now I would recommend a complete beginner go with Version 3 but if you already know another language then go with Version 2 (you will learn faster than a beginner and so may run into some current limitations of V3) Once you find a tutorial that suits your style then stick to it. Do the examples don't just read them. Post any questions or problems you encounter to this mailing list. Tell us the Python version, the tutorial you use and the Operating system. Include full error messages in posts, they may not look helpful to you but they are very helpful to us! :-). Enjoy programming in Python. -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help! (solution)
I know that the question has long been answered (and probably due today), but I
solved it and it was great exercise for me (as I'm not in college at the moment
and I need assignments like these to gauge my skills). I'll probably build a
gui
for it tomorrow, just so I can practice at that. I wish I had a comp sci lab...
(T_T) but I digress
But anyways Andrew here is an alternative way to solve the problem (even if it
is a long and round about method). And to anyone else who is reading beside
Andrew, if something about my code could be better, please tell me, as this was
just as much a learning experience for me as it is for Andrew. I need
constructive criticism at the moment so I don't develop bad habits.
def production_time():
creation_time = 127
time_till_rest = 18161
items = raw_input("How many items will be produced?\n> ")
item_time = int(items) * creation_time
rest_times = item_time/time_till_rest
print rest_times
if rest_times > 0:
total = item_time + (313 * rest_times) #313 is 5 min and 13 secs in
second form
else: total = item_time
time = sec_to_standard(total)
print "It would take %d days %d hours %d minutes and %d seconds to produce
that many items" %(time[0], time[1], time[2], time[3])
def sec_to_standard(seconds):
day = 86400 #secs
hour = 3600 #secs
mins = 60#seconds
creation_time = 127 #secs
time_till_rest = 18161 #secs
days = 0
hours = 0
minutes = 0
secs = 0
if seconds > day:
while seconds > day:
print "doing days"
seconds = seconds - day
days += 1
if seconds > hour:
while seconds > hour:
print "doing hours"
seconds = seconds - hour
hours += 1
if hours >= 24:
days += 1
hours -= 24
if seconds > mins:
while seconds > mins:
print "doing minutes"
seconds = seconds - mins
minutes += 1
if minutes > 60:
hours += 1
minutes -= 60
secs = seconds
return days, hours, minutes, secs
production_time()
What is it about you... that intrigues me so?
From: Andrew Bouchot
To: tutor@python.org
Sent: Thu, March 3, 2011 4:28:33 PM
Subject: [Tutor] Help!
okay so this is my comp sci lab
Problem: ProductionTime.py It takes exactly 2 minutes and 7 second to produce
an
item. Unfortunately, after 143 items are produced, the fabricator must cool off
for 5 minutes and 13 seconds before it can continue. Write a program that will
calculate the amount of time required to manufacture a given number of items.
Output: Output the amount of time D days HH:MM:SS Sample Input : numItems =1340
Represents the numbers items to be manufactured Sample Output : 2 days 00:03:17
this is the coding i have written for it!
numitems= int(raw_input("Enter the number of items needed to be manufactured:"))
seconds=numitems*127
m, s = divmod(seconds, 60)
h, m = divmod(m, 60)
print "%d:%02d:%02d" % (h, m, s)
but how would i add the 5 min and 13 seconds after 143 items have been
produced???
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[Tutor] Fwd: Re: Help! (solution)
Put the timing code for one itemt in a while loop and have the variable for
elapsed time incremented by the amount of time the fabricator has to cool
every time the modulus of the loop counter / 127 is 0 AND the count is above
0.
production = 0
time = 127 # seconds
timer = 0
rest = 313
run = input("Enter your run total: ")
while production != run:
timer = timer + time
if run % production = 0:
timer = timer + rest
print "It took %i seconds to produce %i items." % (timer, run)
d = 24*60*60
h = 60*60
m = 60
D = timer / d # how many days
Dsec = timer % d # seconds left after deducting the days
H = Dsec / h # how many hours
Hsec = Dsec % h # seconds left after deducting hours.
M = Hsec / m # how many minutes
Msec = Hsec % m # seconds left after deducting minutes
print "Production time for %i items: %i Days, %i:%i:%i" % (run, D, H, M,
Msec)
# my 2 cents
-- Forwarded message --
From: "michael scott"
Date: Mar 4, 2011 7:17 PM
Subject: Re: [Tutor] Help! (solution)
To:
I know that the question has long been answered (and probably due today),
but I
solved it and it was great exercise for me (as I'm not in college at the
moment
and I need assignments like these to gauge my skills). I'll probably build a
gui
for it tomorrow, just so I can practice at that. I wish I had a comp sci
lab...
(T_T) but I digress
But anyways Andrew here is an alternative way to solve the problem (even if
it
is a long and round about method). And to anyone else who is reading beside
Andrew, if something about my code could be better, please tell me, as this
was
just as much a learning experience for me as it is for Andrew. I need
constructive criticism at the moment so I don't develop bad habits.
def production_time():
creation_time = 127
time_till_rest = 18161
items = raw_input("How many items will be produced?\n> ")
item_time = int(items) * creation_time
rest_times = item_time/time_till_rest
print rest_times
if rest_times > 0:
total = item_time + (313 * rest_times) #313 is 5 min and 13 secs in
second form
else: total = item_time
time = sec_to_standard(total)
print "It would take %d days %d hours %d minutes and %d seconds to produce
that many items" %(time[0], time[1], time[2], time[3])
def sec_to_standard(seconds):
day = 86400 #secs
hour = 3600 #secs
mins = 60#seconds
creation_time = 127 #secs
time_till_rest = 18161 #secs
days = 0
hours = 0
minutes = 0
secs = 0
if seconds > day:
while seconds > day:
print "doing days"
seconds = seconds - day
days += 1
if seconds > hour:
while seconds > hour:
print "doing hours"
seconds = seconds - hour
hours += 1
if hours >= 24:
days += 1
hours -= 24
if seconds > mins:
while seconds > mins:
print "doing minutes"
seconds = seconds - mins
minutes += 1
if minutes > 60:
hours += 1
minutes -= 60
secs = seconds
return days, hours, minutes, secs
production_time()
What is it about you... that intrigues me so?
From: Andrew Bouchot
To: tutor@python.org
Sent: Thu, March 3, 2011 4:28:33 PM
Subject: [Tutor] Help!
okay so this is my comp sci lab
Problem: ProductionTime.py It takes exactly 2 minutes and 7 second to
produce an
item. Unfortunately, after 143 items are produced, the fabricator must cool
off
for 5 minutes and 13 seconds before it can continue. Write a program that
will
calculate the amount of time required to manufacture a given number of
items.
Output: Output the amount of time D days HH:MM:SS Sample Input : numItems
=1340
Represents the numbers items to be manufactured Sample Output : 2 days
00:03:17
this is the coding i have written for it!
numitems= int(raw_input("Enter the number of items needed to be
manufactured:"))
seconds=numitems*127
m, s = divmod(seconds, 60)
h, m = divmod(m, 60)
print "%d:%02d:%02d" % (h, m, s)
but how would i add the 5 min and 13 seconds after 143 items have been
produced???
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[Tutor] Help - want to display a number with two decimal places
HelloI have created the following code but would like the program to include two decimal places in the amounts displayed to the user. How can I add this?My code:# Ask user to enter purchase pricepurchasePrice = input ('Enter purchase amount and then press the enter key $')
# Tax ratesstateTaxRate = 0.04countrySalesTaxRate = 0.02
# Process taxes for purchase price
stateSalesTax = purchasePrice * stateTaxRatecountrySalesTax = purchasePrice * countrySalesTaxRate
# Process total of taxestotalSalesTax = stateSalesTax + countrySalesTax
# Process total sale pricetotalSalePrice = totalSalesTax + purchasePrice
# Display the dataprint '%-18s %9d' % ('Purchase Price',purchasePrice)print '%-18s %9d' % ('State Sales Tax',astateSalesTax)print '%-18s %9d' % ('Country Sales Tax',countrySalesTax)print '%-18s %9d' % ('Total Sales tax',totalSalesTax)print '%-18s %9d' % ('Total Sale Price',totalSalePrice)Thank you in advance for your help.Lea___
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[Tutor] Shared web host and setting the python environment...
List, Background: I'm on a linux based shared web host. They cater to PHP, not python. (There's no third party python modules even installed!) So I installed a virtual python in my home directory, plus easy_install and a bunch of modules. Great! The Problem: Unfortunately, the web server uses the system python, not my virtual python, or my modules. (It does execute my scripts as my uid though.) I need modify the environment of every one of my python scripts, perhaps appending to sys.path, so that my third party modules in my home directory can be found. I have zero control over the web server process or its environment. Possible Solutions I thought of: One way to do this would be to edit 'sys.path' at the top of every python script. (Sounds ugly.) Another would be to import the 'user' module and go that route. (Fine, but it's depricated. What replaces it?) A third idea would be to re-direct all requests via mod_rewrite to a single python file or shell script, which sets the environment and calls my python scripts as a sub-process. (Slow, which is fine, but some security concerns here.) Given my situation, what's the best way to accomplish this? (Aside from a new hosting company or a virtual private server.) Any suggestions appreciated. Thanks! -Modulok- ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help - want to display a number with two decimal places
On 3/4/11, lea-par...@bigpond.com wrote:
> Hello
>
> I have created the following code but would like the program to include two
> decimal places in the amounts displayed to the user. How can I add this?
>
> My code:
>
>
> # Ask user to enter purchase price
> purchasePrice = input ('Enter purchase amount and then press the enter key
> $')
>
> # Tax rates
> stateTaxRate = 0.04
> countrySalesTaxRate = 0.02
>
> # Process taxes for purchase price
>
> stateSalesTax = purchasePrice * stateTaxRate
> countrySalesTax = purchasePrice * countrySalesTaxRate
>
> # Process total of taxes
> totalSalesTax = stateSalesTax + countrySalesTax
>
> # Process total sale price
> totalSalePrice = totalSalesTax + purchasePrice
>
> # Display the data
> print '%-18s %9d' % ('Purchase Price',purchasePrice)
> print '%-18s %9d' % ('State Sales Tax',astateSalesTax)
> print '%-18s %9d' % ('Country Sales Tax',countrySalesTax)
> print '%-18s %9d' % ('Total Sales tax',totalSalesTax)
> print '%-18s %9d' % ('Total Sale Price',totalSalePrice)
>
Lea,
Notice that 'd' in your string substitution means integers, not
floats. Any decimal places will be truncated when using 'd'. For
floats use 'f' instead. You an also specify a precision, such as
'%.2f' shows two decimal places.
However, to make all of your numbers line up nicely, regardless of how
long they are, you need to look into advanced string formatting via
the builtin string method 'format()'. It takes a little practice to
understand and use, but the results are exactly what you want.
(See: http://docs.python.org/library/stdtypes.html#str.format)
Here's an example you could put at the bottom of your code to see it in action:
print "{0:<18} {1:>18.2f}".format("Country Sales Tax", countrySalesTax)
print "{0:<18} {1:>18.2f}".format("Purchase Price", purchasePrice)
# First prints the first argument (the 0th index) to 'format(),
# left aligned '<', and 18 characters wide, whitespace padded.
# Then prints the second argument, (the 1st index) right aligned,
# also 18 characters wide, but the second argument is specified to
# be a float 'f', that has a precision of 2 decimal places, '.2'.
-Modulok-
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[Tutor] Error while using calendar module in Python 2.7
I ran the following code in python 2.6 and then in python 2.7 (using calendar module) to manipulate dates and times The following code works fine in Python 2.6 but throws up an error in Python 2.7. Can anyone please say why? CODE: import datetime import calendar while monday.weekday() != calendar.MONDAY: monday -= oneday oneweek = datetime.timedelta(days=7) nextweek = today + oneweek print next week Error: Traceback (most recent call last): File "C:\Python27\Foursoft\calendar.py", line 33, in while friday.weekday() != calendar.FRIDAY: AttributeError: 'module' object has no attribute 'FRIDAY' ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Error while using calendar module in Python 2.7
Could you paste the whle code, because I get: >>> import datetime >>> import calendar >>> >>> >>> >>> while monday.weekday() != calendar.MONDAY: ... File "", line 2 ^ IndentationError: expected an indented block >>> monday -= oneday File "", line 1 monday -= oneday ^ IndentationError: unexpected indent >>> >>> oneweek = datetime.timedelta(days=7) >>> >>> nextweek = today + oneweek Traceback (most recent call last): File "", line 1, in NameError: name 'today' is not defined >>> >>> print next week ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Error while using calendar module in Python 2.7
>>> >>> while monday.weekday() != calendar.MONDAY: ... monday -= oneday ... oneweek = datetime.timedelta(days=7) ... nextweek = today + oneweek ... print "next week" ... Traceback (most recent call last): File "", line 1, in NameError: name 'monday' is not defined >>> This means that calender doesn't have an Monday as something you can access. Look at how you use datetime.timedelta(days=7). If you type help (datetime), you can see that timedelta is a function you can access from datetime. However your utilization of calendar doesn't align with the other. Look at the difference in each using the help function(datetime.timedelta and calendar.MONDAY). Also the error you show is a little confusing, because it looks like you were trying calendar.FRIDAY instead of calendar.MONDAY at that point. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Error while using calendar module in Python 2.7
Sorry David The correctly indented code with the while loop is while friday.weekday() != calendar.MONDAY: MONDAY -= oneday oneweek = datetime.timedelta(days=7) nextweek = today + oneweek nextyear = today.replace(year=today.year+1) print "Today (year-month-day) =", today print "Most recent Monday =", monday Is there any change in the calendar module from Python 2.6 to 2.7. This example works fine in Python 2.6 but throws up an error in 2.7 On Sat, Mar 5, 2011 at 12:58 PM, David Hutto wrote: > Could you paste the whle code, because I get: > > >>> import datetime > >>> import calendar > >>> > >>> > >>> > >>> while monday.weekday() != calendar.MONDAY: > ... > File "", line 2 > >^ > IndentationError: expected an indented block > >>> monday -= oneday > File "", line 1 >monday -= oneday >^ > IndentationError: unexpected indent > >>> > >>> oneweek = datetime.timedelta(days=7) > >>> > >>> nextweek = today + oneweek > Traceback (most recent call last): > File "", line 1, in > NameError: name 'today' is not defined > >>> > >>> print next week > -- The inherent vice of capitalism is the unequal sharing of blessings; the inherent virtue of socialism is the equal sharing of miseries. ~ Winston Churchill ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Error while using calendar module in Python 2.7
Please consider this corrected example The correctly indented code with the while loop is while monday.weekday() != calendar.MONDAY: MONDAY -= oneday oneweek = datetime.timedelta(days=7) nextweek = today + oneweek nextyear = today.replace(year=today.year+1) print "Today (year-month-day) =", today print "Most recent Monday =", monday On Sat, Mar 5, 2011 at 1:20 PM, ranjan das wrote: > Sorry David > > > > > > > Is there any change in the calendar module from Python 2.6 to 2.7. > > This example works fine in Python 2.6 but throws up an error in 2.7 > > > > On Sat, Mar 5, 2011 at 12:58 PM, David Hutto wrote: > >> Could you paste the whle code, because I get: >> >> >>> import datetime >> >>> import calendar >> >>> >> >>> >> >>> >> >>> while monday.weekday() != calendar.MONDAY: >> ... >> File "", line 2 >> >>^ >> IndentationError: expected an indented block >> >>> monday -= oneday >> File "", line 1 >>monday -= oneday >>^ >> IndentationError: unexpected indent >> >>> >> >>> oneweek = datetime.timedelta(days=7) >> >>> >> >>> nextweek = today + oneweek >> Traceback (most recent call last): >> File "", line 1, in >> NameError: name 'today' is not defined >> >>> >> >>> print next week >> > > > > -- > The inherent vice of capitalism is the unequal sharing of blessings; the > inherent virtue of socialism is the equal sharing of miseries. > > ~ Winston Churchill > -- The inherent vice of capitalism is the unequal sharing of blessings; the inherent virtue of socialism is the equal sharing of miseries. ~ Winston Churchill ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
