[Tutor] Splitting a string
hi all, i have a function which returns a string. for eg: X='101110'. i want to search for 0 and highlight the location. i am thinking of defining X as a list. but how can i split 101110 as there are no spaces in between? i'm thinking if i can put it into a list: X=['1','0','1','1','1','0'], then i can use index to point out the locations of the 0. pls advise. i'm using Python2.5 and WinXP. thanks tcl ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Splitting a string
On 8 February 2011 16:20, tee chwee liong wrote:
> hi all,
>
> >i have a function which returns a string. for eg: X='101110'. i want to
> search for 0 and highlight the location.
> i> am thinking of defining X as a list. but how can i split 101110 as there
> are no spaces in between? i'm thinking if i can put it into a list:
> >X=['1','0','1','1','1','0'], then i can use index to point out the
> locations of the 0. pls advise.
> i>'m using Python2.5 and WinXP.
>
> >thanks
> >tcl
>
> You can use x.find("0"), but this will only give you the first position.
How about our friend 'enumerate'?:
for index, i in enumerate(x):
if i == "0":
print index
Cheers
--
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Re: [Tutor] Splitting a string
On 08/02/2011 11:20, tee chwee liong wrote: hi all, i have a function which returns a string. for eg: X='101110'. i want to search for 0 and highlight the location. i am thinking of defining X as a list. but how can i split 101110 as there are no spaces in between? i'm thinking if i can put it into a list: X=['1','0','1','1','1','0'], then i can use index to point out the locations of the 0. pls advise. i'm using Python2.5 and WinXP. thanks tcl ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor In Python strings are lists of characters so you can use indexes already. You can look at the .find() function to return you index numbers for the location of your search criteria, it only returns the first within your parameters, but you can create your own function utilising it to return all occurrences. -- Kind Regards, Christian Witts ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] zipfile error message
Eric Stevens wrote:
Hi:
I am relatively new to Python and have been recently trying to experiment
with its zipfile capabilities. However, everytime I try to open a zip (
using method zipfile.ZipFile(open('zipfile.zip','r')) ) I continue to get an
error message that states:error: unpack requires a string argument of length
46. Would anyone be able to help me figure out what is wrong? I am currently
running Python 2.7 on Windows (not sure if that matters). Thank you.
When posting error messages, please copy and paste the *entire* error
message. Do not retype it, paraphrase it, or summarize it.
But in this case, I can guess the error. You're opening the zip file in
text mode:
open('zipfile.zip','r')
which will cause corruption of binary files. Zip files are binary and
must be either opened in binary mode:
open('zipfile.zip','rb')
or better still, just pass the file name to ZipFile and let it open it:
zipfile.ZipFile('zipfile.zip','r')
--
Steven
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Re: [Tutor] Splitting a string
tee chwee liong wrote:
hi all,
i have a function which returns a string. for eg: X='101110'. i want
to search for 0 and highlight the location. i am thinking of defining
X as a list. but how can i split 101110 as there are no spaces in
between? i'm thinking if i can put it into a list:
X=['1','0','1','1','1','0'], then i can use index to point out the
locations of the 0. pls advise. i'm using Python2.5 and WinXP.
Strings are indexable, and have a find method:
>>> s = "abcd"
>>> s.find('c')
2
>>> s[2]
'c'
To get a list, just ask for one:
>>> list("abcd")
['a', 'b', 'c', 'd']
--
Steven
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Re: [Tutor] Splitting a string
> To get a list, just ask for one:
>
list("abcd")
> ['a', 'b', 'c', 'd']
>
or., and this isn't to argue with anyone;), you could:
>>> x = 'abcd'
>>> y = []
>>> for letter in x:
... y.append(letter)
...
>>> print y
['a', 'b', 'c', 'd']
which explains that the list is derived from the string.
x is 'abcd', and list is the list seperated at the characters, and can
be split further with string
'tags'.
>
>
> --
> Steven
>
> ___
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--
According to theoretical physics, the division of spatial intervals as
the universe evolves gives rise to the fact that in another timeline,
your interdimensional counterpart received helpful advice from me...so
be eternally pleased for them.
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Re: [Tutor] vim as a python editor
On 8 February 2011 04:44, Alexander Fairley wrote: > Some high profile ruby hackers have put together a pretty snazzy set of > vim/gvim configs together on github at > > https://github.com/carlhuda/janus > > Thank you, but I think this only works on OSX? I use Ubuntu and if I understand your link correctly, gvim has the equivalent functionality. > On the topic of configuring Capslock to be an escape key, it's because > that's where the "meta" key used to be on old school unix keyboards, and so > it makes you double plus unix if you reconfigure things that way(also has > the plus of rendering emacs a lot more usable). > Sorry, I don't know what 'meta' key and 'double plus' means. What I've now done, using Preferences > Keyboard, is to swap the functionality of the Esc and Caps Lock keys. This helps me because I'm a fairly competent touch typist. Every time I need to press Esc on a default keyboard, I have to lift my left hand from the asdf home keys to get at it. This 'breaks the flow' and gets quite annoying after a while. > > On Fri, Jan 7, 2011 at 7:22 PM, Steven D'Aprano wrote: > >> Alan Gauld wrote: >> >>> "Paul Griffiths" wrote >>> I've learned that: ... - re-configuring the Caps Lock to be an extra Esc saves time >>> >>> Huh? How do you use that? Its a new one on me. Why would two escape keys >>> be useful? >>> >> >> What if you want to escape the escape, so that (say) esc-C is the same as >> just C? >> >> >> Not-very-helpfully y'rs, >> >> -- >> Steven >> >> >> ___ >> Tutor maillist - Tutor@python.org >> To unsubscribe or change subscription options: >> http://mail.python.org/mailman/listinfo/tutor >> > > ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Converting From Unicode to ASCII!!
Nevins Duret wrote: A good friend of mine locked herself out of her computer and forgot her password. I pretty much scoured the internet as a resource only to hit a brick wall. I tried using ophcrack version 2.3.1 in order to obtain the password and felt completely at home being that it was Linux, but then towards the end it failed and the output of this file which seems to contain the Users and passwords but in Unicode format: Administrator:500::31d6cfe0d16ae931b73c59d7e0c089c 0::: Guest:501::31d6cfe0d16ae931b73c59d7e0c089c0::: SUPPORT_388945a0:1002::881037e0b6909b04b6900f7c806 dca6e::: HelpAssistant:1004:b209ce7e3ff7aea1131906e9f5df481 9:d83f663c50bcd5815ccb94f9e38a9a4b::: Beverly:1005:6395b1acd69aaad3b435b51404ee:992a c78ffb08204c592c6e47b916f85d::: I see no Unicode there. It looks like plain ASCII. Are you sure you understand how to use ophcrack? Perhaps you should be asking on a ophcrack mailing list (if they have one). And it didn't complete as a result of this error message: Tables found: /mnt/hdc/tables/xp_free_small Found one partition that contains hashes: /mnt/hda1/WINDOWS/system32/config Starting Ophcrack QIconvCodec::convertFromUnicode: using ASCII for conversion, iconv_open failed QIconvCodec::convertToUnicode: using ASCII for conversion, iconv_open failed /home/tux/launch.sh: line 100: 1044 Killed ABLES_INLINE -w $FOUND/ -n $numcpu -o /tmp/ophcrack.txt $opts Press a key to exit:: Looks to me like a bug in ophcrack, although I could be wrong. Now , I remember reading somewhere that Python is very good for converting Unicode data into ASCII and admittedly know nothing about this: Before asking any more questions about converting Unicode to ASCII, I think you need to read this article: http://www.joelonsoftware.com/articles/Unicode.html You can't just "convert" Unicode to ASCII -- what would you expect to get if you convert (say) "πΣՋوຜ₦ℵ↷"? For starters, you need to know what encoding(s) are being used. Is there a work around in Python where I can simply import the file like and convert it to readable string using A for loop. Import *which* file? What does ophcrack consider "readable"? How do you know that you're not making the problem worse? No, don't go down this track. You'll probably end up making your friend's computer completely unusable without a complete re-build. My advice is to start with Microsoft's instructions: http://support.microsoft.com/kb/321305 and if they aren't helpful, then try using a Linux live cd to reset the password. You can find instructions on the internet, such as: http://www.ehow.com/how_6532691_change-xp-password-linux.html http://www.psychocats.net/ubuntucat/resetwindowspassword/ -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Splitting a string
hi all,
thanks for the advice. i modified my code to be:
c=('01101')
i=-1
try:
while 1:
i=c.index('0',i+1)
print "Lane fail",i
except ValueError:
print "All Lanes PASS"
pass
when i run, the result is:
>>>
Lane fail 0
Lane fail 3
All Lanes PASS
Question: How do i prevent the code from executing the except ValueError part.
it seems to be checking bit by bit and when is see 1 it will execute the except
part.
i just want the results to be:
>>>
Lane fail 0
Lane fail 3
thanks
tcl76 ___
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Re: [Tutor] Splitting a string
Don't use the try and except, use a if else. I'm not as good as an explainer as the pros, but I can make enough sense if you respond back with a useful set of examples you've tried. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Splitting a string
On 08/02/2011 15:04, tee chwee liong wrote:
hi all,
thanks for the advice. i modified my code to be:
c=('01101')
i=-1
try:
while 1:
i=c.index('0',i+1)
print "Lane fail",i
except ValueError:
print "All Lanes PASS"
pass
when i run, the result is:
>>>
Lane fail 0
Lane fail 3
All Lanes PASS
Question: How do i prevent the code from executing the except
ValueError part. it seems to be checking bit by bit and when is see 1
it will execute the except part.
i just want the results to be:
>>>
Lane fail 0
Lane fail 3
thanks
tcl76
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`while i < len(c)` instead of `while 1`
--
Kind Regards,
Christian Witts
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Re: [Tutor] Splitting a string
On Tue, Feb 8, 2011 at 8:36 AM, Christian Witts wrote:
> On 08/02/2011 15:04, tee chwee liong wrote:
>>
>> hi all,
>>
>> thanks for the advice. i modified my code to be:
>>
>> c=('01101')
>> i=-1
>> try:
>> while 1:
>> i=c.index('0',i+1)
>> print "Lane fail",i
>> except ValueError:
>> print "All Lanes PASS"
>> pass
>>
>> when i run, the result is:
>>
>> >>>
>> Lane fail 0
>> Lane fail 3
>> All Lanes PASS
>>
>> Question: How do i prevent the code from executing the except ValueError
>> part. it seems to be checking bit by bit and when is see 1 it will execute
>> the except part.
>> i just want the results to be:
>> >>>
>> Lane fail 0
>> Lane fail 3
>>
>>
>> thanks
>> tcl76
>>
>>
>> ___
>> Tutor maillist - Tutor@python.org
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>>
>
> `while i < len(c)` instead of `while 1`
You remind me of me...like it was yesterday. Explanations with no
thought. Unimpressive isn't it?
>
> --
> Kind Regards,
> Christian Witts
>
>
>
--
According to theoretical physics, the division of spatial intervals as
the universe evolves gives rise to the fact that in another timeline,
your interdimensional counterpart received helpful advice from me...so
be eternally pleased for them.
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Re: [Tutor] Splitting a string
On 08/02/2011 15:38, David Hutto wrote:
On Tue, Feb 8, 2011 at 8:36 AM, Christian Witts wrote:
On 08/02/2011 15:04, tee chwee liong wrote:
hi all,
thanks for the advice. i modified my code to be:
c=('01101')
i=-1
try:
while 1:
i=c.index('0',i+1)
print "Lane fail",i
except ValueError:
print "All Lanes PASS"
pass
when i run, the result is:
Lane fail 0
Lane fail 3
All Lanes PASS
Question: How do i prevent the code from executing the except ValueError
part. it seems to be checking bit by bit and when is see 1 it will execute
the except part.
i just want the results to be:
Lane fail 0
Lane fail 3
thanks
tcl76
`while i< len(c)` instead of `while 1`
You remind me of me...like it was yesterday. Explanations with no
thought. Unimpressive isn't it?
While the index is smaller than the length of the string do your
processing. It reads like that. But thank you for your commentary.
--
Kind Regards,
Christian Witts
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Re: [Tutor] Splitting a string
Christian Witts wrote:
> On 08/02/2011 15:04, tee chwee liong wrote:
>> hi all,
>>
>> thanks for the advice. i modified my code to be:
>>
>> c=('01101')
>> i=-1
>> try:
>> while 1:
>> i=c.index('0',i+1)
>> print "Lane fail",i
>> except ValueError:
>> print "All Lanes PASS"
>> pass
>>
>> when i run, the result is:
>>
>> >>>
>> Lane fail 0
>> Lane fail 3
>> All Lanes PASS
>>
>> Question: How do i prevent the code from executing the except
>> ValueError part. it seems to be checking bit by bit and when is see 1
>> it will execute the except part.
>> i just want the results to be:
>> >>>
>> Lane fail 0
>> Lane fail 3
> `while i < len(c)` instead of `while 1`
You have an off-by-one bug. But even if you fix that you'll still enter the
except suite if the string c doesn't end with a "0". You need to keep track
of the failed lanes, e. g.:
for c in "011010", "111", "000", "", "1", "0", "001":
print c.center(20, "-")
i = -1
all_passed = True
try:
while True:
i = c.index('0', i+1)
print "Lane fail", i
all_passed = False
except ValueError:
pass
if all_passed:
print "All Lanes PASS"
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Re: [Tutor] Splitting a string
On Tue, Feb 8, 2011 at 2:47 PM, Christian Witts
>>> `while i< len(c)` instead of `while 1`
>>>
>>
>> You remind me of me...like it was yesterday. Explanations with no
>> thought. Unimpressive isn't it?
>>
>
> While the index is smaller than the length of the string do your processing.
> It reads like that. But thank you for your commentary.
>
The goal of this list is not to criticize, David, but to help. Why not
provide some explanations yourself?
EIther way, even with this correction a ValueError is still raised at
least *once* if the string doesn't end with a 0, so it won't actually
help a bit. A quick fix is to set some variable if you find a 0, then
check on that variable after the loop (See Peter's example).
Now, find is nice if you care about finding one instance, but if you
need to find *all* instances you'll have to check the entire string
anyway, and find becomes a rather cumbersome tool. Interestingly,
enumerate was suggested all the way at the beginning of the thread,
and I think it's the best answer:
zeroes = ["lane fail {0}".format(i) for i, val in enumerate(c) if val == '0']
print '\n'.join(zeroes) if zeroes else "All Lanes pass"
Ok, That looks a little advanced, but strip away all that syntactic
sugar and you arrive at basically this:
zeroes = []
for index, value in enumerate(c):
if value == '0':
zeroes.append(index)
if zeroes:
for x in zeroes:
print "lane fail", x
else:
print "all lanes pass"
Since we have to scan the whole string anyway, this is equally
efficient as using find (theoretically!!! if you care about
performance, *measure*).
Hugo
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[Tutor] CrackTheInterview
Visit http://www.cracktheinterview.org/ for more interview preparation tips and interview experiences of various people ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] zipfile error message
On Mon, 7 Feb 2011, Eric Stevens wrote:
Hi:
I am relatively new to Python and have been recently trying to experiment
with its zipfile capabilities. However, everytime I try to open a zip (
using method zipfile.ZipFile(open('zipfile.zip','r')) ) I continue to get an
error message that states:error: unpack requires a string argument of length
46. Would anyone be able to help me figure out what is wrong? I am currently
running Python 2.7 on Windows (not sure if that matters). Thank you.
zip files are not ascii text, so in order to send it to the zipfile you
need to open it with the 'rb' flag to indicate you want to read in binary
mode.
HTH,
Wayne
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[Tutor] Apologies, mea culpa
Sorry folks, I meant to hit discard on this one but clicked Accept by mistake. Alan G. List moderator ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Splitting a string
"tee chwee liong" wrote i have a function which returns a string. for eg: X='101110'. i want to search for 0 and highlight the location. I'm not sure what you mean by highlight the location. Is it a GUI? Are you colour coding the characters? i am thinking of defining X as a list. You shouldn't need to, you can treat the string as a sequence directly indexes = [i for i, c in enumerate(X) if char == '0'] Will give you the list of indexes you need. How you use that to highlight the zeros will depend on your UI I guess. HTH, -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Splitting a string
> I'm not sure what you mean by highlight the location. > Is it a GUI? Are you colour coding the characters? > hi, no it is not GUI. i just want to know where is the location of the 0 in the returned string. For eg: 10111, i want to say 0 is at lane 3 (calculating location from right to left). thanks___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Splitting a string
> `while i < len(c)` instead of `while 1` > hi, i modified codes to be i>> Lane fail 0 Lane fail 3 All Lanes PASS >>> ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Splitting a string
"tee chwee liong" wrote
###
c=('01101')
i=-1
try:
while i print "Lane fail",i
except ValueError:
print "All Lanes PASS"
pass
#
The first thing is that you never increment i so the
while condition is never going to terminate, so its
probably just as well you get the exception.
The next thing is that you get the exception whenever
index() can't find a zero. So the exception does not
mean *ALL* lanes pass, it means all the lanes from
the last zero pass. You really want the exception
to stop the search. But it won't indicate all pass
unless it happens the first time...
Using your logic it is easier written as a for loop:
s='01101'
found = False
for i,c in enumerate(s):
if c == '0':
print 'Lane fail',i
found = True
if not Found: print 'All lanes PASS'
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk/
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Re: [Tutor] Splitting a string
hi all, the code works: s='00101' found = False for i,c in enumerate(s): if c == '0': print 'Lane fail',i found = True if not found: print 'All lanes PASS # Result: >>> Lane fail 0 Lane fail 1 Lane fail 3 >>> the enumerate is checking from left to right. is it possible check from right to left? for eg:s='00101' Will give below result: Lane fail 1 Lane fail 3 Lane fail 4 thanks tcl ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
