Re: [Tutor] Help with OCR
"Sriram Jaju" wrote I'm new to python. I'm doing a project on OCR (Optical Character Recognition), I've heard a lot about Python so i want to know whether i can use python for OCR. That depends a lot on the environment. What OS will you be using? What are you doing exactly? Are you actually reading the characters optically or are you taking a feed from an OCR device? Are you processing a scanned image? If yes what are the tool require for that?. It depends on the above indformation. My another doubt is that, can i use python for programming microcontrollers Not normally, but if you can find a program that can program the microcontroller you might be able to drive it from Python. Or if the micro has an interface that can be driven from, for example, a serial port you may be able to do something. We can't give specific answers without a lot more specific information. -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help with OCR
"Shashwat Anand" wrote My another doubt is that, can i use python for programming microcontrollers You bet. Really? How would he go about that? I've not seen (or even heard of) Python used in that role before. Alan G ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Help with OCR
I'm using windows7. I'm doing a robotic project in which a robot has to take instruction from images which are taken by camera. image consists of characters like 'START', 'STOP' etc. On Mon, Feb 7, 2011 at 2:25 PM, Alan Gauld wrote: > "Sriram Jaju" wrote > > I'm new to python. I'm doing a project on OCR (Optical Character >> Recognition), I've heard a lot about Python so i want to know whether i >> can >> use python for OCR. >> > > That depends a lot on the environment. What OS will you be using? > What are you doing exactly? Are you actually reading the characters > optically or are you taking a feed from an OCR device? Are you > processing a scanned image? > > > If yes what are the tool require for that?. >> > > It depends on the above indformation. > > > My another doubt is that, can i use python for programming >> microcontrollers >> > > Not normally, but if you can find a program that can program > the microcontroller you might be able to drive it from Python. > Or if the micro has an interface that can be driven from, for example, > a serial port you may be able to do something. > > We can't give specific answers without a lot more specific information. > > -- > Alan Gauld > Author of the Learn to Program web site > http://www.alan-g.me.uk/ > > > > ___ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > -- Xcited 2 be AliveSriram ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] nested loops
I am trying to write a function...(it's kind of like a long way to do BLAST but only comparing 2 sequences) I have 3 loops nested...Within those loops, I obtain a "best fit score" so to speak. I can get the program to run...but the loops run all the way to the end. I can't figure out how to print the best score found...and the alignment that went with it. (therefore, my results will only be correct if my last alignment is the highest scoring one--which it usually isn't) To try to clear this up... The part of my pseudocode that I'm having trouble putting into actual code in python is: "if that alignment has the best score seen so far save the score and that alignment" ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
On Mon, 7 Feb 2011, Ashley F wrote: To try to clear this up... The part of my pseudocode that I'm having trouble putting into actual code in python is: "if that alignment has the best score seen so far save the score and that alignment" Tip: It's helpful to send code, like perhaps the triple loop, that illustrates your problem. highscore = 0 alignment = somealignment for x in something: for y in somethingelse: for z in evenmoresomething: if x+y+z > highscore: highscore = x+y+z alignment = newalignment Is that something to the effect of what you're looking for? HTH, Wayne___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
On 02/07/2011 10:33 AM, Ashley F wrote: I am trying to write a function...(it's kind of like a long way to do BLAST but only comparing 2 sequences) I have 3 loops nested...Within those loops, I obtain a "best fit score" so to speak. I can get the program to run...but the loops run all the way to the end. I can't figure out how to print the best score found...and the alignment that went with it. (therefore, my results will only be correct if my last alignment is the highest scoring one--which it usually isn't) To try to clear this up... The part of my pseudocode that I'm having trouble putting into actual code in python is: "if that alignment has the best score seen so far save the score and that alignment" It would be much easier for people to help you if you would include the actual code you have written. We have no way to tell you are running to the end or not; we certainly have nothing showing 'a best fit' algorithm. If we can see the actual code we can at least show you where you might want to look for current and/or potential problems. Also, what OS are you using? What version of Python are you using? Robert Berman ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
"Wayne Werner" wrote You probably want to add a sentinel to break out of the outer loops too: found = False highscore = 0 alignment = somealignment for x in something and not found: for y in somethingelse and not found: for z in evenmoresomething: if x+y+z > highscore: highscore = x+y+z alignment = newalignment found = True break HTH, -- Alan Gauld Author of the Learn to Program web site http://www.alan-g.me.uk/ ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] function help
ok...here's the function I've written so far.
def padWithGaps(seq):
for letter in seq:
letter="-"
line=len(seq)
dashline=line*letter
return dashline
def replace(someString,position,letter):
first=someString[0:position]
second=letter
third=someString[position+1:len(someString)]
newString=first+second+third
return newString
##findScore("MPFVS","MS-V-") would return a score of 2
def findScore(first,second):
count=0
for position in range(0,len(first)):
if first[position]==second[position]:
count=count+1
position=position+1
return count
#shorter is a 3 amino acid sequence
##longer is any length sequence greater than 3
###i=first amino acid; j=second amino acid; k=third amino acid
def findAlignment(shorter,longer):
for i in range(0,len(longer)-2):
for j in range(1,len(longer)-1):
for k in range(2,len(longer)):
dashline=padWithGaps(longer)
nextLine=replace(dashline,i,shorter[0])
nextNext=replace(nextLine,j,shorter[1])
alignment=replace(nextNext,k,shorter[2])
score=findScore(longer,alignment)
don't know what to do here
print longer
print alignment
print "Score = " + str(score)
I don't know what to do at the end of my loop but what I'm trying to do in
pseudocode is:
"if that alignment has the best score seen so far
save the score and the alignment
print the best score and the best alignment"
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Re: [Tutor] nested loops
Alan Gauld wrote:- > "Wayne Werner" wrote > found = False > > highscore = 0 > > alignment = somealignment > > for x in something and not found: > > for y in somethingelse and not found: > > for z in evenmoresomething: > > if x+y+z > highscore: > > highscore = x+y+z > > alignment = newalignment > found = True > break > > HTH, That's going to exit first time through, isn't it? -- Michael This mail was sent via Mail-SeCure System. This footnote confirms that this email message has been scanned by PineApp Mail-SeCure for the presence of malicious code, vandals & computer viruses. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] PyS60 request
Hello Everybody, I am working on a little project centered on PyS60, developing applications for symbian phones. Before I start asking questions pertaining to that, I would like to first clarify if it is appropriate to post such questions here. If it is a yes, then, my subsequent mails would be conveying my questions and if it is a no, kindly accept my unreserved apologies. There are no intentions to abuse the principles of this group. Thanks. -- Elegbede Muhammed Oladipupo OCA +2348077682428 +2347042171716 www.dudupay.com Mobile Banking Solutions | Transaction Processing | Enterprise Application Development ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] function help
I'm not sure of the answer to your question, because i'm not sure I
understand it. Perhaps you could rephrase it?
But, there is some other stuff I noticed though:
def padWithGaps(seq):
for letter in seq:
letter="-"
line=len(seq)
dashline=line*letter
return dashline
This function is fairly inefficient. Let's say you pass the function a
sequence three items long something like a_list = ['a','b','c']. Your
telling Python to create a dashed line three dashes long
three separate times. So, you do it for the 'a' part of the sequence, the
'b' and the 'c'. You can condense this to something like:
def padWithGaps(seq):
lent = len(seq)
return lent*'-'
And you really don't need to have a separate function for that, as you can
just do it on the fly
Another thing, whenever your taking a slice of a list and the first argument
is 0, you can just omit that. For example, from my list a_list example above
a_list[0:2] is equivalent to a_list[:2]
As for the rest of them, what you could do is pass each function data that
you would expect to be passed under normal operation (assuming this is
possible of course) and instead of using return use print instead and see if
the results are what you expect.
What I mean is, let's say I pass the results from the padWithGaps (the
results of which I call dashline to be consistent) to the next function:
def replace(someString,position,letter):
first=someString[0:position]
second=letter
third=someString[position+1:len(someString)]
newString=first+second+third
return newString
So, I can do something like z = replace(dashline,0,'a') and then print z.
What the results should be is "a--".
def findScore(first,second):
count=0
for position in range(0,len(first)):
if first[position]==second[position]:
count=count+1
position=position+1
return count
With this function here, there is a few things you can do to optimize and
clean up clutter as well. I only point this out because it pays huge
dividends in the long run (or it has for me at least). The first thing
though is that you don't need to have the line position=position+1. Python
will go to the next item in the list "position" whether you tell it to or
not. So below is the same thing but without the position +=1 line:
def findScore(first,second):
count=0
for position in range(0,len(first)):
if first[position]==second[position]:
count=count+1
return count
The other thing I would suggest is to use enumerate. Enumerate is your
friend. And the last thing I would suggest is whenever you want to do
something like a = a+1, you can just do a +=1.
> def findScore2(first,second):
count=0
for i, position in enumerate(first):
if position==second[i]:
count+=1
return count
enumerate returns both the next item in the list and the position of that
item in the list (in this case, I called that variable i). So you will find
that if you run findScore2 you will have the same results as findScore. Or
at least you should ;)
On Mon, Feb 7, 2011 at 11:45 AM, Ashley F wrote:
> ok...here's the function I've written so far.
>
> def padWithGaps(seq):
> for letter in seq:
>letter="-"
>line=len(seq)
>dashline=line*letter
> return dashline
>
> def replace(someString,position,letter):
> first=someString[0:position]
> second=letter
> third=someString[position+1:len(someString)]
> newString=first+second+third
> return newString
>
> ##findScore("MPFVS","MS-V-") would return a score of 2
> def findScore(first,second):
> count=0
> for position in range(0,len(first)):
> if first[position]==second[position]:
> count=count+1
> position=position+1
> return count
>
> #shorter is a 3 amino acid sequence
> ##longer is any length sequence greater than 3
> ###i=first amino acid; j=second amino acid; k=third amino acid
> def findAlignment(shorter,longer):
> for i in range(0,len(longer)-2):
> for j in range(1,len(longer)-1):
> for k in range(2,len(longer)):
>dashline=padWithGaps(longer)
>nextLine=replace(dashline,i,shorter[0])
>nextNext=replace(nextLine,j,shorter[1])
>alignment=replace(nextNext,k,shorter[2])
>score=findScore(longer,alignment)
>don't know what to do here
> print longer
> print alignment
> print "Score = " + str(score)
>
> I don't know what to do at the end of my loop but what I'm trying to do in
> pseudocode is:
> "if that alignment has the best score seen so far
> save the score and the alignment
> print the best score and the best alignment"
>
>
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> ht
[Tutor] JES Jython
Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] JES Jython
On 2/7/2011 2:45 PM, Eun Koo wrote: Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? Maybe. You might say more about the problem. What is JES and how does it relate to Python? -- Bob Gailer 919-636-4239 Chapel Hill NC ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] JES Jython
Eun Koo, 07.02.2011 20:45: Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? If you can provide enough information for us to understand what your problem is, we may be able to help you. It's a matter of politeness to help us help you. The more work we have to put into figuring out what you want (or even what your words are supposed to mean), the less likely it is that someone will do that and help you out. Stefan ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
Alan Gauld wrote: "Wayne Werner" wrote You probably want to add a sentinel to break out of the outer loops too: I don't think you want to break out of *any* of the loops. Otherwise you will skip testing combinations. In your example, the first time you set highscore and alignment, you break out of all three loops and only test the first triple x,y,z. > found = False highscore = 0 alignment = somealignment for x in something and not found: for y in somethingelse and not found: for z in evenmoresomething: if x+y+z > highscore: highscore = x+y+z alignment = newalignment found = True break That's the equivalent of a return in the innermost loop. If you're looking for the *first* matching highscore, that's fine, but not if you want the biggest. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] PyS60 request
Dipo Elegbede wrote: Hello Everybody, I am working on a little project centered on PyS60, developing applications for symbian phones. Before I start asking questions pertaining to that, I would like to first clarify if it is appropriate to post such questions here. This is a mailing list about learning Python the programming language. If your question is about Python itself, then it doesn't matter if you are using PyS60, CPython, IronPython, PyPy, or any other implementation of Python. If your question is specifically about PyS60, then you are welcome to ask, but chances are high that there will not be anyone here who knows anything about PyS60. You might be better off trying the main Python mailing list, python-l...@python.org, or if you prefer Usenet, comp.lang.python. Or you can look here for a mailing list specifically about Python on the Symbian: http://www.python.org/community/lists/ -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] JES Jython
Eun Koo wrote: Hi I have a problem in JES getting a solution to a function. Is there a way you guys can help? Probably not. This is a mailing list about learning the language Python, not specific to JES (whatever that is!) under Jython. If JES has a support forum dedicated to it, you should try there. Otherwise, try a Jython mailing list. You might try the main Python mailing list, python-l...@python.org, also available on Usenet as comp.lang.python. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] function help
Ashley F wrote: ok...here's the function I've written so far. def padWithGaps(seq): for letter in seq: letter="-" line=len(seq) dashline=line*letter return dashline I don't think that's a useful function. It seems to do a HUGE amount of work that just keeps getting thrown away. Let's say seq = "GACT", this function will do the following: letter = "G" letter = "-" line = 4 # len of seq dashline = "" letter = "A" letter = "-" line = 4 dashline = "" letter = "C" letter = "-" line = 4 dashline = "" letter = "T" letter = "-" line = 4 dashline = "" It does everything four times. Now imagine that seq is a million characters long instead of four! This will do the job *much* faster: def padWithGaps(seq): return "-" * len(seq) *Much* faster, much easier to read. [...] I don't know what to do at the end of my loop but what I'm trying to do in pseudocode is: "if that alignment has the best score seen so far save the score and the alignment print the best score and the best alignment" You need to store the current best score and the current best alignment. Then each time around the innermost loop, you need to calculate the score and alignment (as you already do), and compare them to the best seen so far. If they are worse or equal, you don't need to do anything, just go on to the next loop as normal. But if they are better, then you need to update the best score and alignment, and print them. if score > best_score: best_score = score best_alignment = alignment print 'best seen so far is', score, alignment Does that help? Try writing the code, and if you still can't get it working, ask again. -- Steven ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] nested loops
"Steven D'Aprano" wrote I don't think you want to break out of *any* of the loops. Otherwise you will skip testing combinations. In that case I misread the OP. I thought he specifically wanted to avoid testing all the options and exit when he reached his target. In your example, the first time you set highscore and alignment, you break out of all three loops Yep, thats what I thought was being asked for. It seems I mistook the intent. reading too quickly I suspect. Alan G ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] Converting From Unicode to ASCII!!
Hello all, Don't know if I'll be bashed on this forum for doing this, but I will assure you I have the best intentions and simply want to apply a real world problem and how to go about solving it using python3.1. Here is my predicament. A good friend of mine locked herself out of her computer and forgot her password. I pretty much scoured the internet as a resource only to hit a brick wall. I tried using ophcrack version 2.3.1 in order to obtain the password and felt completely at home being that it was Linux, but then towards the end it failed and the output of this file which seems to contain the Users and passwords but in Unicode format: Administrator:500::31d6cfe0d16ae931b73c59d7e0c089c 0::: Guest:501::31d6cfe0d16ae931b73c59d7e0c089c0::: SUPPORT_388945a0:1002::881037e0b6909b04b6900f7c806 dca6e::: HelpAssistant:1004:b209ce7e3ff7aea1131906e9f5df481 9:d83f663c50bcd5815ccb94f9e38a9a4b::: Beverly:1005:6395b1acd69aaad3b435b51404ee:992a c78ffb08204c592c6e47b916f85d::: And it didn't complete as a result of this error message: Tables found: /mnt/hdc/tables/xp_free_small Found one partition that contains hashes: /mnt/hda1/WINDOWS/system32/config Starting Ophcrack QIconvCodec::convertFromUnicode: using ASCII for conversion, iconv_open failed QIconvCodec::convertToUnicode: using ASCII for conversion, iconv_open failed /home/tux/launch.sh: line 100: 1044 Killed ABLES_INLINE -w $FOUND/ -n $numcpu -o /tmp/ophcrack.txt $opts Press a key to exit:: Now , I remember reading somewhere that Python is very good for converting Unicode data into ASCII and admittedly know nothing about this: Is there a work around in Python where I can simply import the file like and convert it to readable string using A for loop. Any help on this would be greatly appreciated. So far, I'm reading up on this topic at this url: http://docs.python.org/howto/unicode.html Best Regards, Nevins Duret ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] vim as a python editor
Some high profile ruby hackers have put together a pretty snazzy set of vim/gvim configs together on github at https://github.com/carlhuda/janus On the topic of configuring Capslock to be an escape key, it's because that's where the "meta" key used to be on old school unix keyboards, and so it makes you double plus unix if you reconfigure things that way(also has the plus of rendering emacs a lot more usable). On Fri, Jan 7, 2011 at 7:22 PM, Steven D'Aprano wrote: > Alan Gauld wrote: > >> "Paul Griffiths" wrote >> >>> I've learned that: >>> ... >>> - re-configuring the Caps Lock to be an extra Esc saves time >>> >> >> Huh? How do you use that? Its a new one on me. Why would two escape keys >> be useful? >> > > What if you want to escape the escape, so that (say) esc-C is the same as > just C? > > > Not-very-helpfully y'rs, > > -- > Steven > > > ___ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Converting From Unicode to ASCII!!
On Mon, Feb 7, 2011 at 10:15 PM, Nevins Duret wrote: > Hello all, > > > > Don’t know if I’ll be bashed on this forum for doing this, > but I will assure you I have the best intentions and > > simply want to apply a real world problem and how to go about solving it > using python3.1. Here is my predicament. > > A good friend of mine locked herself out of her computer and forgot her > password. I pretty much scoured the internet as > > a resource only to hit a brick wall. I tried using ophcrack version 2.3.1 > in order to obtain the password and felt completely at home > > being that it was Linux, but then towards the end it failed and the output > of this file which seems to contain the Users and passwords The linux forums might be better. Or you could use: http://www.google.com/search?client=ubuntu&channel=fs&q=linux+lost+password+brute+force&ie=utf-8&oe=utf-8 > > but in Unicode format: > > > > Administrator:500::31d6cfe0d16ae931b73c59d7e0c089c 0::: > Guest:501::31d6cfe0d16ae931b73c59d7e0c089c0::: > SUPPORT_388945a0:1002::881037e0b6909b04b6900f7c806 dca6e::: > HelpAssistant:1004:b209ce7e3ff7aea1131906e9f5df481 > 9:d83f663c50bcd5815ccb94f9e38a9a4b::: > Beverly:1005:6395b1acd69aaad3b435b51404ee:992a > c78ffb08204c592c6e47b916f85d::: > > > > And it didn’t complete as a result of this error message: > > > > Tables found: > /mnt/hdc/tables/xp_free_small > > Found one partition that contains hashes: > /mnt/hda1/WINDOWS/system32/config > > Starting Ophcrack > QIconvCodec::convertFromUnicode: using ASCII for conversion, iconv_open > failed > QIconvCodec::convertToUnicode: using ASCII for conversion, iconv_open failed > /home/tux/launch.sh: line 100: 1044 Killed > ABLES_INLINE -w $FOUND/ -n $numcpu -o /tmp/ophcrack.txt $opts > Press a key to exit:: > > > > Now , I remember reading somewhere that Python is very good for converting > Unicode > > data into ASCII and admittedly know nothing about this: > > > > Is there a work around in Python where I can simply import the file like and > convert it to readable string using > > A for loop. > > > > Any help on this would be greatly appreciated. So far, I’m reading up on > this topic at this url: > > http://docs.python.org/howto/unicode.html > > > > Best Regards, > > > > Nevins Duret > > > > ___ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > > -- The lawyer in me says argue...even if you're wrong. The scientist in me... says shut up, listen, and then argue. But the lawyer won on appeal, so now I have to argue due to a court order. Furthermore, if you could be a scientific celebrity, would you want einstein sitting around with you on saturday morning, while you're sitting in your undies, watching Underdog?...Or better yet, would Einstein want you to violate his Underdog time? Can you imagine Einstein sitting around in his underware? Thinking about the relativity between his pubic nardsac, and his Fruit of the Looms, while knocking a few Dorito's crumbs off his inner brilliant white thighs, and hailing E = mc**2, and licking the orangy, delicious, Doritoey crust that layered his genetically rippled fingertips? But then again, J. Edgar Hoover would want his pantyhose intertwined within the equation. However, I digress, momentarily. But Einstein gave freely, for humanity, not for gain, other than personal freedom. An equation that benefited all, and yet gain is a personal product. Also, if you can answer it, is gravity anymore than interplanetary static cling? ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Converting From Unicode to ASCII!!
Also, If you can install a second version, then you should be able to mount the other version you're locked out of, then recover your files, and reinstall. ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Converting From Unicode to ASCII!!
And I forgot, that you don't have to install another version, but just boot from the live disk, and mount the partition. But from looking, you should be able to recover with linux utilities. Look here: http://aplawrence.com/Linux/lostlinuxpassword.htmlhttp://aplawrence.com/Linux/lostlinuxpassword.html ___ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
[Tutor] zipfile error message
Hi:
I am relatively new to Python and have been recently trying to experiment
with its zipfile capabilities. However, everytime I try to open a zip (
using method zipfile.ZipFile(open('zipfile.zip','r')) ) I continue to get an
error message that states:error: unpack requires a string argument of length
46. Would anyone be able to help me figure out what is wrong? I am currently
running Python 2.7 on Windows (not sure if that matters). Thank you.
Eric
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