[Tutor] Using Easygui in Python v3
I'm currently updating my tutorial to cover Python V3. I thought it miight be good to include some stuff on EasyGUI for the user input topic and on checking the web site it said Easygui was compatible with Python v3. However after downloading and installing I get a "No module named StringIO" error under Python v3. Before I start digging deeper I thought I'd ask if anyone else had the same problem and knows of a fix? -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/l2p/ ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Using Easygui in Python v3
"Alan Gauld" wrote user input topic and on checking the web site it said Easygui was compatible with Python v3. However after downloading and installing I get a "No module named StringIO" error under Python v3. OK, Not much digging required. StringIO has moved to io.StringIO in v3 So changing the version check code to: if runningPython3: from tkinter import * import tkinter.filedialog as tk_FileDialog from io import StringIO else: from Tkinter import * import tkFileDialog as tk_FileDialog import StringIO and deleting the original import StringIO line seems to work... If someone else could carry out a more exhaustive test than my basic EnterBox then I'll notify the easygui team. Alan G. ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] Accessing a list inside a class...
I feel like I'm missing something simple, but I have now spent hours
googling for an answer. I think I must not be searching for the right terms,
or else this is something I'm not supposed to be doing - but it seems
straightforward to me.
Here's my test code (condensed from the actual much longer code I'm adapting
from functions to objects - I'm new to OOP, but I'm trying J ):
___
class TestObject:
def __init__(self):
# options and arguments from commandline-->OptionParser
self.opt = ""
self.args = []
def load_cfg(self):
# read+parse commandlnie
self._parse_commandline()
def load_ini(self):
# I'm trying to get at 'inifile' from the commandline... #
print self.opt['inifile']
def _parse_commandline(self):
parser = OptionParser()
parser.add_option("-i", dest = "inifile", help = "specify an ini
file to load")
(self.opt, self.args) = parser.parse_args()
if __name__ == '__main__':
# parses command-line argumenmts
from optparse import OptionParser
test = TestObject()
test.load_cfg()
test.load_ini()
___
In the middle is a comment with five hashes to show you the crux of my
problem.
If I eliminate "['inifile']", I can print the list.
How in the world can I get just the 'inifile' element?
Ideally, of course, I'm not printing this - I'm going to access it from
outside the class, or even inside the class.
The error I get when running the above code:
Traceback (most recent call last):
File "listinclass.py", line 34, in
test.load_ini()
File "listinclass.py", line 17, in load_ini
print self.opt['inifile']
AttributeError: Values instance has no attribute '__getitem__'
I've googled for "list in a class" and pretty much every variant I can think
of, and I just can't seem to find a single example of someone trying to get
to an element of a list stored in a class. so I apologize for asking a
basic/simple question, but I just can't find it.
Many thanks for your consideration.
___
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Re: [Tutor] Accessing a list inside a class...
With the small font size and lots of blank lines I find this hard to read!
When I look at the optparse documentation I guess you want
print self.opt.inifile
Alexander Daychilde (Gmail) wrote:
I feel like I’m missing something simple, but I have now spent hours
googling for an answer. I think I must not be searching for the right
terms, or else this is something I’m not supposed to be doing – but it
seems straightforward to me…
Here’s my test code (condensed from the actual much longer code I’m
adapting from functions to objects – I’m new to OOP, but I’m trying J ):
___
class TestObject:
def __init__(self):
# options and arguments from commandline-->OptionParser
self.opt = ""
self.args = []
def load_cfg(self):
# read+parse commandlnie
self._parse_commandline()
def load_ini(self):
# I'm trying to get at 'inifile' from the commandline... #
print self.opt['inifile']
def _parse_commandline(self):
parser = OptionParser()
parser.add_option("-i", dest = "inifile", help = "specify an ini file
to load")
(self.opt, self.args) = parser.parse_args()
if __name__ == '__main__':
# parses command-line argumenmts
from optparse import OptionParser
test = TestObject()
test.load_cfg()
test.load_ini()
___
In the middle is a comment with five hashes to show you the crux of my
problem…
If I eliminate “[‘inifile’]”, I can print the list.
How in the world can I get just the ‘inifile’ element?
Ideally, of course, I’m not printing this – I’m going to access it
from outside the class, or even inside the class…
The error I get when running the above code:
Traceback (most recent call last):
File "listinclass.py", line 34, in
test.load_ini()
File "listinclass.py", line 17, in load_ini
print self.opt['inifile']
AttributeError: Values instance has no attribute '__getitem__'
I’ve googled for “list in a class” and pretty much every variant I can
think of, and I just can’t seem to find a single example of someone
trying to get to an element of a list stored in a class… so I
apologize for asking a basic/simple question, but I just can’t find it.
Many thanks for your consideration…
___
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--
Bob Gailer
Chapel Hill NC
919-636-4239
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Re: [Tutor] Accessing a list inside a class...
Le Thu, 9 Apr 2009 08:47:59 -0700, "Alexander Daychilde (Gmail)" s'exprima ainsi: > The error I get when running the above code: > > Traceback (most recent call last): > > File "listinclass.py", line 34, in > > test.load_ini() > > File "listinclass.py", line 17, in load_ini > > print self.opt['inifile'] > > AttributeError: Values instance has no attribute '__getitem__' This means the following: * You're trying to access an item inside something called self.opt by using a key: 'inifile'. * self.opt should then be able to return you an item from a key, in other words it should be an object that behaves like a dictionary, right? * The "magic" method the allows this behaviour is called __getitem__ (the same as for list indexing, actually). So that python looks for this method in the class of self.opt, that happens to be Values, and tells you... Sure, not very clear! > I've googled for "list in a class" and pretty much every variant I can think > of, and I just can't seem to find a single example of someone trying to get > to an element of a list stored in a class. so I apologize for asking a > basic/simple question, but I just can't find it. The issue has nothing to do with the fact the self.opt happens to be an attribute. Denis -- la vita e estrany ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Accessing a list inside a class...
Alexander Daychilde (Gmail) wrote:
class TestObject:
def __init__(self):
# options and arguments from commandline-->OptionParser
self.opt = ""
here, self.opt is initialized as a string...
self.args = []
def load_cfg(self):
# read+parse commandlnie
self._parse_commandline()
def load_ini(self):
# I'm trying to get at 'inifile' from the commandline... #
print self.opt['inifile']
... and here you're accessing it as a dict
def _parse_commandline(self):
parser = OptionParser()
parser.add_option("-i", dest = "inifile", help = "specify an ini
file to load")
(self.opt, self.args) = parser.parse_args()
... and here it's changed to whatever is returned by parser.parse_args
if __name__ == '__main__':
# parses command-line argumenmts
from optparse import OptionParser
test = TestObject()
... so when __init__ has complete, test.opt will be a string
test.load_cfg()
... and after this it's whatever is returned by parser.parse_args
try print test.opt to see what was returned -- that'll probably help
clear things up. If it's really a list type, you don't access those
with keys, so self.opt['inifile'] would fail.
test.load_ini()
HTH,
Emile
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[Tutor] Finding all IP addresses associated with a host
I'm very new to python, and my google-fu has failed to locate an answer to the following: How can I find all of the (ipv4) addresses that are currently up on a host? I realize I can call ifconfig and then munge the output with awk, but that seems messy, and before I tried that I though I would ask around. To give a bit more information, I'm writing a script that will use the ip address assigned to the wifi interface to determine location (this is on a Mac) and then mount network drives appropriate to the location. If anyone has a better idea how to do this, I'd be happy to hear them. Thanks in advance! Scott Newton ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Finding all IP addresses associated with a host
Scott Newton wrote: I'm very new to python, and my google-fu has failed to locate an answer to the following: How can I find all of the (ipv4) addresses that are currently up on a host? In google I searched for "python what's my ip" and about the fourth entry down found a link that led me to http://pypi.python.org/pypi/netifaces/0.3 How far does that get you? HTH, Emile I realize I can call ifconfig and then munge the output with awk, but that seems messy, and before I tried that I though I would ask around. To give a bit more information, I'm writing a script that will use the ip address assigned to the wifi interface to determine location (this is on a Mac) and then mount network drives appropriate to the location. If anyone has a better idea how to do this, I'd be happy to hear them. Thanks in advance! Scott Newton ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] BeautifulSoup confusion
I am not a programmer by trade but I've been using Python for 10+ years, usually for text file conversion and protocol analysis. I'm having a problem with Beautiful Soup. I can get it to scrape off all the href links on a web page but I am having problems selecting specific URI's from the output supplied by Beautiful Soup. What exactly is it returning to me and what command would I use to find that out? Do I have to take each line it give me and put it into a list before I can, for example, get only certain URI's containing a certain string or use the results to get the web page that the URI is referring to? The pseudo code for what I am trying to do: Get all URI's from web page that contain string "env.html" Open the web page it is referring to. Scrape selected information off of that page. I'm have problem with step #1. I can get all URI's but I can't see to get re.compile to work right. If I could get it to give me the URI only without tags or link description, that would be ideal. Thanks for your help. Steve Lyskawa ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] BeautifulSoup confusion
On Thu, Apr 9, 2009 at 7:27 PM, Steve Lyskawa wrote:
> I'm having a
> problem with Beautiful Soup. I can get it to scrape off all the href links
> on a web page but I am having problems selecting specific URI's from the
> output supplied by Beautiful Soup.
> What exactly is it returning to me and what command would I use to find that
> out?
Generally it gives you Tag and NavigableString objects, or lists of
same. To find out what something is, print its type:
print type(x)
> Do I have to take each line it give me and put it into a list before I
> can, for example, get only certain URI's containing a certain string or use
> the results to get the web page that the URI is referring to?
> The pseudo code for what I am trying to do:
> Get all URI's from web page that contain string "env.html"
> Open the web page it is referring to.
> Scrape selected information off of that page.
If you want to get all URI's at once, then that would imply creating a
list. You could also process URI's one-at-a-time.
> I'm have problem with step #1. I can get all URI's but I can't see to get
> re.compile to work right. If I could get it to give me the URI only without
> tags or link description, that would be ideal.
Something like this should get you started:
soup = BeautifulSoup()
for anchor in soup.findAll('a', href=re.compile(r'env\.html')):
print anchor['href']
That says, find all tags whose 'href' attribute matches the regex
'env\.html'. The Tag object will be assigned to the anchor variable.
Then the value of the 'href' attribute is printed.
I find it very helpful with BS to experiment at the command line. It
often takes a few tries to understand what it is giving you and how to
get exactly what you want.
Kent
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[Tutor] What is Dani Web?
Title: Signature.html See . It seems to a set of forum for a lot of software, including Python. I don't see any explanation of Dani and how it formed. -- Wayne Watson (Watson Adventures, Prop., Nevada City, CA) (121.01 Deg. W, 39.26 Deg. N) GMT-8 hr std. time) "In arithemtic as in politics, the importance of one is determined by the number of zeros behind it." -- Anon ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] Finding all IP addresses associated with a host
Thanks, not sure how I missed that one. -Scott On Thu, Apr 9, 2009 at 7:25 PM, Emile van Sebille wrote: > Scott Newton wrote: > >> I'm very new to python, and my google-fu has failed to locate an answer to >> the following: >> >> How can I find all of the (ipv4) addresses that are currently up on a >> host? >> > > > In google I searched for "python what's my ip" and about the fourth entry > down found a link that led me to http://pypi.python.org/pypi/netifaces/0.3 > > How far does that get you? > > HTH, > > Emile > > > > >> I realize I can call ifconfig and then munge the output with awk, but that >> seems messy, and before I tried that I though I would ask around. >> >> To give a bit more information, I'm writing a script that will use the ip >> address assigned to the wifi interface to determine location (this is on a >> Mac) and then mount network drives appropriate to the location. If anyone >> has a better idea how to do this, I'd be happy to hear them. >> >> Thanks in advance! >> >> Scott Newton >> >> >> >> >> ___ >> Tutor maillist - Tutor@python.org >> http://mail.python.org/mailman/listinfo/tutor >> > > ___ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor > ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
[Tutor] How to write server which listens to specific port
Dear All, Greetings I have developed an application in Python 2.4.2, TurboGears 1.0, cherryPy 2.3.1. Now, I have to develop a server, which listens to a specific port (104) and save the file to a specific location (/tmp/myDir) on RHEL 4/5. Guide me how to do that. what all packages I have to use. Thanks in anticipation. Shiv _ The new Windows Live Messenger. You don’t want to miss this. http://www.microsoft.com/india/windows/windowslive/messenger.aspx___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] BeautifulSoup confusion
Steve Lyskawa wrote: > I am not a programmer by trade but I've been using Python for 10+ years, > usually for text file conversion and protocol analysis. I'm having a > problem with Beautiful Soup. I can get it to scrape off all the href links > on a web page but I am having problems selecting specific URI's from the > output supplied by Beautiful Soup. > What exactly is it returning to me and what command would I use to find that > out? Do I have to take each line it give me and put it into a list before I > can, for example, get only certain URI's containing a certain string or use > the results to get the web page that the URI is referring to? > > The pseudo code for what I am trying to do: > > Get all URI's from web page that contain string "env.html" > Open the web page it is referring to. > Scrape selected information off of that page. That's very easy to do with lxml.html, which offers an iterlinks() method on elements to iterate over all links in a document (not only a-href, but also in stylesheets, for example). It can parse directly from a URL, so you don't need to go through urllib and friends, and it can make links in a document absolute before iterating over them, so that relative links will work for you are doing. http://codespeak.net/lxml/lxmlhtml.html#working-with-links Also, you should use the urlparse module to split the URL (in case it contains parameters etc.) and check only the path section. Stefan ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
Re: [Tutor] problem in replacing regex
Hey Moos/Denis/Kent, Thanks a lot for your replies and suggestions. Actually the value which I had given was separated by \n\r. I now realized that this cannot be done with one regular expression as there is one limit in negative look behind that it requires fixed width. I guess This limit is there up to python 2.7 version. So actually though I don't want, but I had to do it using splitting :( But thanks a lot for your help, this has given me better understanding the regex. Thanks you all thank you so much. Regards, Kumar On Thu, Apr 9, 2009 at 3:35 AM, Moos Heintzen wrote: > Hi, > > You can do the substitution in many ways. > > You can first search for bare account numbers and substitute them with > urls. Then substitute urls into tags. > > To substitute account numbers that aren't in urls, you simply > substitutes account numbers if they don't start with a "/", as you > have been trying to do. > > re.sub() can accept a function instead of a string. The function > receives the match object and returns a replacement. This way you can > do extra processing to matches. > > import re > > text = """https://hello.com/accid/12345-12 > > 12345-12 > > http://sadfsdf.com/asdf/asdf/asdf/12345-12 > > start12345-12end > > this won't be replaced > start/123-45end > """ > > def sub_num(m): >if m.group(1) == '/': >return m.group(0) >else: ># put url here >return m.group(1) + 'http://example.com/' + m.group(2) > > >>> print re.sub(r'(\D)(\d+-\d+)', sub_num , text) > https://hello.com/accid/12345-12 > > http://example.com/12345-12 > > http://sadfsdf.com/asdf/asdf/asdf/12345-12 > > starthttp://example.com/12345-12end > > this won't be replaced > start/123-45end > > >>> _ > > This is assuming there isn't any tags in the input, so you should > do this before substituting urls into tags. > > > I have super cow powers! > > Moos > ___ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
