[R] Choleski and Choleski with pivoting of matrix fails

2009-11-21 Thread simona.racio...@libero.it
Hi Everyone,

I need to take the square root of the following matrix:

[,1]   [,2][,3]
[1,]  0.5401984 -0.3998675 -1.3785897
[2,] -0.3998675  1.0561872  0.8158639
[3,] -1.3785897  0.8158639  1.6073119

I tried Choleski which fails. I then tried Choleski with pivoting, but 
unfortunately the square root I get is not valid. I also tried eigen 
decomposition but i did no get far.

Any clue on how to do it?!

Thanks,
Simon

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[R] R: chol( neg.def.matrix ) WAS: Re: Choleski and Choleski with pivoting of matrix fails

2009-11-23 Thread simona.racio...@libero.it
Thanks Chuck!
It works! But Once I have the square root of this matrix, how do I convert it 
to a real (not imaginary) matrix which has the same property? Is that 
possible?

Best,
Simon

>Messaggio originale
>Da: cbe...@tajo.ucsd.edu
>Data: 21-nov-2009 18.11
>A: "simona.racio...@libero.it"
>Cc: 
>Ogg: chol( neg.def.matrix ) WAS: Re: [R] Choleski and Choleski with pivoting 
of matrix fails
>
>On Sat, 21 Nov 2009, simona.racio...@libero.it wrote:
>
>> Hi Everyone,
>>
>> I need to take the square root of the following matrix:
>>
>>[,1]   [,2][,3]
>> [1,]  0.5401984 -0.3998675 -1.3785897
>> [2,] -0.3998675  1.0561872  0.8158639
>> [3,] -1.3785897  0.8158639  1.6073119
>>
>> I tried Choleski which fails. I then tried Choleski with pivoting, but
>> unfortunately the square root I get is not valid. I also tried eigen
>> decomposition but i did no get far.
>>
>> Any clue on how to do it?!
>
>
>If you want to take the square root of a negative definite matrix, you 
>could use
>
>   sqrtm( neg.def.mat )
>
>from the expm package on rforge:
>
>   http://r-forge.r-project.org/projects/expm/
>
>HTH,
>
>Chuck
>
>
>>
>> Thanks,
>> Simon
>>
>> __
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.
html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>Charles C. Berry(858) 534-2098
> Dept of Family/Preventive 
Medicine
>E mailto:cbe...@tajo.ucsd.edu  UC San Diego
>http://famprevmed.ucsd.edu/faculty/cberry/  La Jolla, San Diego 92093-0901
>
>
>

__
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[R] R: Re: chol( neg.def.matrix ) WAS: Re: Choleski and Choleski with pivoting of matrix fails

2009-11-23 Thread simona.racio...@libero.it
It works! But Once I have the square root of this matrix, how do I convert it 
to a real (not imaginary) matrix which has the same property? Is that 
possible?

Best,
Simon

>Messaggio originale
>Da: p.dalga...@biostat.ku.dk
>Data: 21-nov-2009 18.56
>A: "Charles C. Berry"
>Cc: "simona.racio...@libero.it", 
>Ogg: Re: [R] chol( neg.def.matrix ) WAS: Re: Choleski and Choleski with 
pivoting of matrix fails
>
>Charles C. Berry wrote:
>> On Sat, 21 Nov 2009, simona.racio...@libero.it wrote:
>> 
>>> Hi Everyone,
>>>
>>> I need to take the square root of the following matrix:
>>>
>>>[,1]   [,2][,3]
>>> [1,]  0.5401984 -0.3998675 -1.3785897
>>> [2,] -0.3998675  1.0561872  0.8158639
>>> [3,] -1.3785897  0.8158639  1.6073119
>>>
>>> I tried Choleski which fails. I then tried Choleski with pivoting, but
>>> unfortunately the square root I get is not valid. I also tried eigen
>>> decomposition but i did no get far.
>>>
>>> Any clue on how to do it?!
>> 
>> 
>> If you want to take the square root of a negative definite matrix, you 
>> could use
>> 
>> sqrtm( neg.def.mat )
>> 
>> from the expm package on rforge:
>> 
>> http://r-forge.r-project.org/projects/expm/
>
>But that matrix is not negative definite! It has 2 positive and one 
>negative eigenvalue. It is non-positive definite.
>
>It is fairly easy in any case to get a matrix square root from the eigen 
>decomposition:
>
> > v%*%diag(sqrt(d+0i))%*%t(v)
>   [,1]  [,2]  [,3]
>[1,]  0.5164499+0.4152591i -0.1247682-0.0562317i -0.7257079+0.3051868i
>[2,] -0.1247682-0.0562317i  0.9618445+0.0076145i  0.3469916-0.0413264i
>[3,] -0.7257079+0.3051868i  0.3469916-0.0413264i  1.0513849+0.2242912i
> > ch <- v%*%diag(sqrt(d+0i))%*%t(v)
> > t(ch)%*% ch
>   [,1]  [,2]  [,3]
>[1,]  0.5401984+0i -0.3998675-0i -1.3785897-0i
>[2,] -0.3998675-0i  1.0561872+0i  0.8158639-0i
>[3,] -1.3785897-0i  0.8158639-0i  1.6073119-0i
>
>A triangular square root is, er, more difficult, but hardly impossible.
>
>-- 
>O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
>   c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
>  (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
>~~ - (p.dalga...@biostat.ku.dk)  FAX: (+45) 35327907
>

__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] R: Re: R: Re: chol( neg.def.matrix ) WAS: Re: Choleski and Choleski with pivoting of matrix fails

2009-11-25 Thread simona.racio...@libero.it
Dear Peter,
thank you very much for your answer.

My problem is that I need to calculate the following quantity:

solve(chol(A)%*%Y)

Y is a 3*3 diagonal matrix and A is a 3*3 matrix. Unfortunately one 
eigenvalue of A is negative. I can anyway take the square root of A but when I 
multiply it by Y, the imaginary part of the square root of A is dropped, and I 
do not get the right answer.

I tried to exploit the diagonal structure of Y by using 2*2 matrices for A 
and Y. In this way the problem mentioned above disappears (since all 
eigenvalues of A are positive) and when I perform the calculation above I get 
approximately the right answer. The approximation is quite good. However it is 
an approximation.

Any suggestion?
Thank you very much!
Simon




>Messaggio originale
>Da: p.dalga...@biostat.ku.dk
>Data: 23-nov-2009 14.09
>A: "simona.racio...@libero.it"
>Cc: "Charles C. Berry", 
>Ogg: Re: R: Re: [R] chol( neg.def.matrix ) WAS: Re: Choleski and Choleski 
with pivoting of matrix fails
>
>simona.racio...@libero.it wrote:
>> It works! But Once I have the square root of this matrix, how do I convert 
it 
>> to a real (not imaginary) matrix which has the same property? Is that 
>> possible?
>
>No. That is theoretically impossible.
>
>If A = B'B, then x'Ax = ||Bx||^2 >= 0
>
>for any x, which implies in particular that all eigenvalues of A should
>be nonnegative.
>
>> 
>> Best,
>> Simon
>> 
>>> Messaggio originale
>>> Da: p.dalga...@biostat.ku.dk
>>> Data: 21-nov-2009 18.56
>>> A: "Charles C. Berry"
>>> Cc: "simona.racio...@libero.it", > project.org>
>>> Ogg: Re: [R] chol( neg.def.matrix ) WAS: Re: Choleski and Choleski with 
>> pivoting of matrix fails
>>> Charles C. Berry wrote:
>>>> On Sat, 21 Nov 2009, simona.racio...@libero.it wrote:
>>>>
>>>>> Hi Everyone,
>>>>>
>>>>> I need to take the square root of the following matrix:
>>>>>
>>>>>[,1]   [,2][,3]
>>>>> [1,]  0.5401984 -0.3998675 -1.3785897
>>>>> [2,] -0.3998675  1.0561872  0.8158639
>>>>> [3,] -1.3785897  0.8158639  1.6073119
>>>>>
>>>>> I tried Choleski which fails. I then tried Choleski with pivoting, but
>>>>> unfortunately the square root I get is not valid. I also tried eigen
>>>>> decomposition but i did no get far.
>>>>>
>>>>> Any clue on how to do it?!
>>>>
>>>> If you want to take the square root of a negative definite matrix, you 
>>>> could use
>>>>
>>>> sqrtm( neg.def.mat )
>>>>
>>>> from the expm package on rforge:
>>>>
>>>> http://r-forge.r-project.org/projects/expm/
>>> But that matrix is not negative definite! It has 2 positive and one 
>>> negative eigenvalue. It is non-positive definite.
>>>
>>> It is fairly easy in any case to get a matrix square root from the 
eigen 
>>> decomposition:
>>>
>>>> v%*%diag(sqrt(d+0i))%*%t(v)
>>>   [,1]  [,2]  [,3]
>>> [1,]  0.5164499+0.4152591i -0.1247682-0.0562317i -0.7257079+0.3051868i
>>> [2,] -0.1247682-0.0562317i  0.9618445+0.0076145i  0.3469916-0.0413264i
>>> [3,] -0.7257079+0.3051868i  0.3469916-0.0413264i  1.0513849+0.2242912i
>>>> ch <- v%*%diag(sqrt(d+0i))%*%t(v)
>>>> t(ch)%*% ch
>>>   [,1]  [,2]  [,3]
>>> [1,]  0.5401984+0i -0.3998675-0i -1.3785897-0i
>>> [2,] -0.3998675-0i  1.0561872+0i  0.8158639-0i
>>> [3,] -1.3785897-0i  0.8158639-0i  1.6073119-0i
>>>
>>> A triangular square root is, er, more difficult, but hardly impossible.
>>>
>>> -- 
>>>O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
>>>   c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
>>>  (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
>>> ~~ - (p.dalga...@biostat.ku.dk)  FAX: (+45) 35327907
>>>
>> 
>> 
>
>
>-- 
>   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
>  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
> (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
>~~ - (p.dalga...@biostat.ku.dk)  FAX: (+45) 35327907
>
>

__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


[R] R: RE: R: Re: R: Re: chol( neg.def.matrix ) WAS: Re: Choleski and Choleski with pivoting of matrix fails

2009-11-26 Thread simona.racio...@libero.it
Thanks for your message!
Actually it works quite well for me too.

If I then take the trace of the final result below, I end up with a number 
made up of both a real and an imaginary part. This does not probably mean much 
if the trace of the matrix below givens me info about the degrees of freedom of 
a model...

Simona 

>Messaggio originale
>Da: rvarad...@jhmi.edu
>Data: 25-nov-2009 18.55
>A: , 
>Cc: 
>Ogg: RE: [R] R: Re: R: Re: chol( neg.def.matrix ) WAS: Re: Choleski and 
Choleski with pivoting of matrix fails
>
>I do not understand what the problem is, as it works just fine for me:
>
>A <- matrix(c(0.5401984,-0.3998675,-1.3785897,-0.3998675,1.0561872,  
>0.8158639,-1.3785897, 0.8158639, 1.6073119), 3, 3, byrow=TRUE)
>
>eA <- eigen(A)
>
>chA <-  eA$vec %*% diag(sqrt(eA$val+0i)) %*% t(eA$vec)
>
>all.equal(A, Re(chA %*% t(chA)))
>
>Y <- diag(c(1,2,3))
>
>solve(chA %*% Y)
>
>Ravi.
>

>---
>
>Ravi Varadhan, Ph.D.
>
>Assistant Professor, The Center on Aging and Health
>
>Division of Geriatric Medicine and Gerontology 
>
>Johns Hopkins University
>
>Ph: (410) 502-2619
>
>Fax: (410) 614-9625
>
>Email: rvarad...@jhmi.edu
>
>Webpage:  http://www.jhsph.
edu/agingandhealth/People/Faculty_personal_pages/Varadhan.html
>
> 
>

>----
>
>-Original Message-
>From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On 
Behalf Of simona.racio...@libero.it
>Sent: Wednesday, November 25, 2009 9:59 AM
>To: p.dalga...@biostat.ku.dk
>Cc: r-help@r-project.org
>Subject: [R] R: Re: R: Re: chol( neg.def.matrix ) WAS: Re: Choleski and 
Choleski with pivoting of matrix fails
>
>Dear Peter,
>thank you very much for your answer.
>
>My problem is that I need to calculate the following quantity:
>
>solve(chol(A)%*%Y)
>
>Y is a 3*3 diagonal matrix and A is a 3*3 matrix. Unfortunately one 
>eigenvalue of A is negative. I can anyway take the square root of A but when 
I 
>multiply it by Y, the imaginary part of the square root of A is dropped, and 
I 
>do not get the right answer.
>
>I tried to exploit the diagonal structure of Y by using 2*2 matrices for A 
>and Y. In this way the problem mentioned above disappears (since all 
>eigenvalues of A are positive) and when I perform the calculation above I 
get 
>approximately the right answer. The approximation is quite good. However it 
is 
>an approximation.
>
>Any suggestion?
>Thank you very much!
>Simon
>
>
>
>
>>Messaggio originale
>>Da: p.dalga...@biostat.ku.dk
>>Data: 23-nov-2009 14.09
>>A: "simona.racio...@libero.it"
>>Cc: "Charles C. Berry", 
>>Ogg: Re: R: Re: [R] chol( neg.def.matrix ) WAS: Re: Choleski and Choleski 
>with pivoting of matrix fails
>>
>>simona.racio...@libero.it wrote:
>>> It works! But Once I have the square root of this matrix, how do I 
convert 
>it 
>>> to a real (not imaginary) matrix which has the same property? Is that 
>>> possible?
>>
>>No. That is theoretically impossible.
>>
>>If A = B'B, then x'Ax = ||Bx||^2 >= 0
>>
>>for any x, which implies in particular that all eigenvalues of A should
>>be nonnegative.
>>
>>> 
>>> Best,
>>> Simon
>>> 
>>>> Messaggio originale
>>>> Da: p.dalga...@biostat.ku.dk
>>>> Data: 21-nov-2009 18.56
>>>> A: "Charles C. Berry"
>>>> Cc: "simona.racio...@libero.it", >> project.org>
>>>> Ogg: Re: [R] chol( neg.def.matrix ) WAS: Re: Choleski and Choleski 
with 
>>> pivoting of matrix fails
>>>> Charles C. Berry wrote:
>>>>> On Sat, 21 Nov 2009, simona.racio...@libero.it wrote:
>>>>>
>>>>>> Hi Everyone,
>>>>>>
>>>>>> I need to take the square root of the following matrix:
>>>>>>
>>>>>>[,1]   [,2][,3]
>>>>>> [1,]  0.5401984 -0.3998675 -1.3785897
>>>>>> [2,] -0.3998675  1.0561872  0.8158639
>>>>>> [3,] -1.3785897  0.8158639  1.6073119
>>>>>>
>>>>>> I tried Choleski which fails. I then tried Choleski with pivoting, 
but
>>>>>> unfortunately the square root I get is not valid. I also tried eigen
>>>>>> decomposition but i did no get far.
>>>>>>
>>>>>>