[Rd] .net and R

[Yuan Jian]

Hi,
  is it possible to call R functions from visual studio .net such as c#?
   
   

   
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[Rd] && and ||

[Yuan Jian]

Hello there,
   
  I got a small problem about logical calculation:
  we can get a sequene from a+b as below:
   
  > a<-c(1,2)
> b<-c(3,4)
> a+b
[1] 4 6
   
  but when the sequences are logical. (I want to get (True,False) && (True, 
True) ==> (True, False), but when I do as below.
> e<-c(T,T)
> f<-c(F,T)
> e
[1] TRUE TRUE
> f
[1] FALSE  TRUE
> g<-e && f
  **g becomes one logical value only
> g
[1] FALSE
> 
what should I do when I want to get a sequence for operate && or ||?
   
  kind regards
  Yu
   


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Re: [Rd] && and ||

[Yuan Jian]

Berwin A Turlach <[EMAIL PROTECTED]> wrote:   G'day Yu,

On Sun, 13 Apr 2008 23:48:33 -0700 (PDT)
Yuan Jian wrote:

> what should I do when I want to get a sequence for operate && or ||?

Read `help("&&")' and then use & and |. :)

HTH.

Cheers,

Berwin

=== Full address =
Berwin A Turlach Tel.: +65 6515 4416 (secr)
Dept of Statistics and Applied Probability +65 6515 6650 (self)
Faculty of Science FAX : +65 6872 3919 
National University of Singapore 
6 Science Drive 2, Blk S16, Level 7 e-mail: [EMAIL PROTECTED]
Singapore 117546 http://www.stat.nus.edu.sg/~statba



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[Rd] matrix

[Yuan Jian]

Hello,
  I have a matrix, I want to change value to 0 when a element in the matrix has 
less than 10.
  do you know how to do it without using loops?
   
   
   

   
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Re: [Rd] matrix

[Yuan Jian]

thanks,
   
  can I ask another basic question?
  I have a matrix (1 X 6). 1 rows and 6 columns.
  I want to remove rows that have sd(col1, col2,col3) <1 or sd(col4,col5,col6) 
<1.
  what is the simple way?
   
  Yu
  
Duncan Murdoch <[EMAIL PROTECTED]> wrote:
  On 16/04/2008 7:33 PM, Yuan Jian wrote:
> Hello,
> I have a matrix, I want to change value to 0 when a element in the matrix has 
> less than 10.
> do you know how to do it without using loops?

A[A < 10] <- 0

Remember that matrices are just vectors with dimensions, so you can 
index one like a vector.

Duncan Murdoch


   
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