Re: UnicodeEncodeError - a bit out of my element...

[liupeng]

I cut from Sam Python Phrasebook
"Converting Unicode to Local Strings"

import string locStr = "El " 
uniStr = u"Ni\u00F1o" 
print uniStr.encode('utf-8') 
print uniStr.encode('utf-16') 
print uniStr.encode('iso-8859-1') 
#Combine local and unicode results 
#in new unicode string 
newStr = locStr+uniStr 
print newStr.encode('iso-8859-1') 
#ascii will error because character '\xF1' 
#is out of range 
asciiStr = newStr.encode('iso-8859-1') 
asciiStr =asciiStr.translate(\ 
string.maketrans('\xF1','n'), '') 
print asciiStr.encode('ascii') 
print newStr.encode('ascii')

unicode_str.py 

Niño 
ÿN|I|ñ|o 
Niño 
El Niño 
El Nino 
Traceback (most recent call last): 
  File "C:\books\python\CH2\code\unicode_str.py", 
line 19, in ? 
print newStr.encode('ascii') 
UnicodeEncodeError: 'ascii' codec can't encode 
 character u'\xf1' in position 5: ordinal not in 
 range(128)

On Wed, Apr 11, 2007 at 08:16:07AM -0700, erikcw wrote:
> Hi all,
> 
> I'm trying to parse an email message, but am running into this
> exception.
> 
> Traceback (most recent call last):
>   File "wa.py", line 336, in ?
> main()
>   File "wa.py", line 332, in main
> print out['msg']
> UnicodeEncodeError: 'ascii' codec can't encode character u'\xd6' in
> position 238: ordinal not in range(128)
> 
> How can I decode/encode this string to print to stdout and send again
> in another email?  Do I have to know what language the email is in?
> 
> Thanks!
> Erik
> 
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> http://mail.python.org/mailman/listinfo/python-list
> 
> 


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Re: python regular expression help

[liupeng]

pattern = re.compile(r'\w+\s*=\s*[0-9]*.[0-9]*\s*')
lists = pattern.findall(s)
print lists
['a=4 ', 'b=3.4 ', 'c=4.5']
On Wed, Apr 11, 2007 at 06:10:07PM -0700, Qilong Ren wrote:
> Hi, everyone,
> 
> I am extracting some information from a given string using python RE. The
> string is ,for example,
>s = 'a = 4 b =3.4 5.4 c = 4.5'
> What I want is :
>a = 4
> b = 3.4 5.4
>c = 4.5
> Right now I use :
>pattern = re.compile(r'\w+\s*=\s*.*?\s+')
>lists = pattern.findall(s)
> It works for the string like 'a = 4 b = 3.4 c = 4.5', but does not work with
> strings like 'a=4 b=3.4 5.4 c = 4.5'
> 
> Any suggestion?
> 
> Thanks,Qilong
> 
> ━━━
> Don't get soaked. Take a quick peak at the forecast
> with theYahoo! Search weather shortcut.

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