Getting sorting order

[leodp]

Hi all,

I cannot find anything on this:
I have a few lists, and would like to sort one of them (sorting-master
list).
Then I would like to sort all other lists according to how the first
one was sorted (sorting-slave lists).

Is there a standard way to do that?
>From what I know sort() and sorted() do not return the order of
sorting.
Maybe I have to write some more code.

Ciao, leodp
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Re: Getting sorting order

[leodp]

> Or provide a better explanation and an example. Do you mean something like
> this?
>

Hi Peter,
a small example:

master=[1,4,3,2]
slave1=['d','c','b','a']
slave2=[1,2,3,4]

master.sort() # this is ok, but does not return infos on how the list
was sorted
slave1.sort(key=_maybe_something_here_referring_to_master_)
slave2.sort(key=_maybe_something_here_referring_to_master_)

Then I should get:
master=[1,2,3,4]
slave1=['d','a','b','c']
slave2=[1,4,3,2]


Hope it is more clear now.
Thanks, leodp
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Re: Getting sorting order

[leodp]

> >>> master_index.sort(key=master.__getitem__)

that was it!


Thanks Peter, leodp
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Re: Getting sorting order

[leodp]

> >>> x=zip(master,slave1,slave2)
> >>> x.sort()
> >>> master,slave1,slave2=zip(*x)

> --Mark

So nice is Python.
Leo
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