I've made a snniferr for a ICMP socket that works with IPv4. This is the
code:
import sys
import socket
import struct
import select
import time
import signal
import re
HOST = raw_input("Enter the interface to listen: ")
s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_ICMP)
s.bind((HOST, 0))
s.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1)
print "Server Started.."
for i in range(1,2000):
data = s.recvfrom(65565)
d1 = str(data[0])
data1 = re.search('@@(.*)', d1)
command = data1.group(0)
cmd = command[2:]
if i%2 == 0:
d = data[1]
d1 = str(d)
ip = d1[2:-5]
print cmd
print ip
I have done a modification to adapt it to IPv6:
s = socket.socket(socket.AF_INET6, socket.SOCK_RAW, socket.IPPROTO_ICMPV6)
However I recive the next error:
File "server.py", line 16, in
s.bind((HOST, 0))
File "/usr/lib/python2.7/socket.py", line 224, in meth
return getattr(self._sock,name)(*args)
socket.error: [Errno 22] Invalid argument
Could someone please help me?.
Thanks in advance
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