How to return an "not string' error in function?

[breakfastea]

first of all I have to claim that I'm a noob so please help me don't
blame me:)

for example:

def test(s):
   if type(s) != ? :
  return
#So here I want establish a situation about that if  is not string
#then , but how should write the  ?
#Or is there any other way to do it?

Any suggestion would be appreciate

Peace

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Re: How to return an "not string' error in function?

[breakfastea]

Thank you so much it answers my humble question perfectly:)

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Re: How to return an "not string' error in function?

[breakfastea]

Or yes that seems a handy way:)

Thanks for all wonderful people here:)

Peace


Duncan Booth wrote:
> Tim Chase <[EMAIL PROTECTED]> wrote:
>
> > This will return true for both regular strings and for unicode
> > strings.  If that's a problem, you can use
> >
> > >>> import types
> > >>> isinstance("hello", types.StringType)
> > True
> > >>> isinstance(u"hello", types.StringType)
> > False
> > >>> isinstance("hello", types.UnicodeType)
> > False
> > >>> isinstance(u"hello", types.UnicodeType)
> > True
> >
> > ...or, if you don't want to qualify them with "types." each time,
> > you can use
> >
> > >>> from types import StringType, UnicodeType
> >
> > to bring them into the local namespace.
>
> They already are in the builtin namespace under their more usual names of
> str and unicode respectively, so there is no need to import them, just use
> them:
> 
> >>> isinstance("hello", str)
> True
> 
> ... etc ...

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Re: How to return an "not string' error in function?

[breakfastea]

Thank you for your inputing which has been great inspirational:)

What I tried to do is to write a string.split() module, so I started
with:

def spilt(a):
l=[]
index=0
if not isinstance(a, basestring): #Or isinstance(a, str)
return
for i in len(a):
if a[i]=' ':
item=a[index:i]
l.append(item)
 ..

I'm still working on it:)

Thank you again

Peace

PS: Is str() the same as repr() ?



Cameron Laird wrote:
> In article <[EMAIL PROTECTED]>,
>  <[EMAIL PROTECTED]> wrote:
> >Thank you so much it answers my humble question perfectly:)
> >
>
> HOWEVER, to answer you final question, yes, there is a different
> and, in general, better, way.  While there's a lot to say about
> good Python style and typing, I'll summarize at a high level:
> you shouldn't have to check types.  I can understand that you
> are working to make a particular function particularly robust,
> and are trying to account for a wide range of inputs.  This is
> healthy.  In stylish Python, though, you generally don't need
> type checking.  How would it be, for example, if someone passed
> the number 3 to your function.  Is that an error?  Do you want
> it automatically interpreted as the string "3"?  You can achieve
> these results withOUT a sequence of
>
>   if isinstance(...
>   elif isinstance(...
>   ...
>
> perhaps with something as simple as
>
>   my_input = str(my_input).
>
> One of us will probably follow-up with a reference to a more
> detailed write-up of the subject.

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Re: How to return an "not string' error in function?

[breakfastea]

Thank you for your reminder:)

However I saw the split() function in the first place and that why I'm
trying write one myself:)

Peace

Bruno Desthuilliers wrote:
> [EMAIL PROTECTED] wrote:
> (OT : please dont top-post)
>
> > Thank you for your inputing which has been great inspirational:)
> >
> > What I tried to do is to write a string.split() module,
>
> So don't waste time:
>
> >>> "ab eced f aazaz".split()
> ['ab', 'eced', 'f', 'aazaz']
> >>> "ab-eced-ff-aazaz".split('-')
> ['ab', 'eced', 'ff', 'aazaz']
> >>>
>
>
>
> --
> bruno desthuilliers
> python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
> p in '[EMAIL PROTECTED]'.split('@')])"

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