dear readers,
i have a very simple package organized as follows:
!-!
bgp/
__init__.py
managers/
__init__.py
ManagerInterface.py
TestManager.py
!-!
and here's ManagerInterface.py and TestManager.py:
!-!
# ManagerInterface.py
class ManagerInterface(object):
def __init__(self): pass
def process(self, recset, operation):
print 'In ManagerInterface.process()...'
# TestManager.py
import ManagerInterface
class TestManager(ManagerInterface):
def process(self, recset, operation):
print 'In TestManager.process()...'
super(TestManager,self).process(recset,operation)
!---!
when i try to import the TestManager module via the interpreter, i get
the following error:
!---!
$ python
Python 2.4.1c1 (#1, Mar 14 2005, 10:28:18)
[GCC 3.2.3 20030502 (Red Hat Linux 3.2.3-49)] on linux2
>>> import bgp.managers.TestManager
Traceback (most recent call last):
File "", line 1, in ?
File "bgp/managers/TestManager.py", line 2, in ?
class TestManager(ManagerInterface):
TypeError: Error when calling the metaclass bases
module.__init__() takes at most 2 arguments (3 given)
!---!
any thoughts? i think that when python executes the TestManager class
statement, it collects the base class (ManagerInterface) into a tuple
and then executes the class body in a dictionary... is this where the
error is happening?
thanks!
aaron
--
http://mail.python.org/mailman/listinfo/python-list
