searching a list of lists as a two-dimensional array?

[agent-s]

Basically I'm programming a board game and I have to use a list of
lists to represent the board (a list of 8 lists with 8 elements each).
I have to search the adjacent cells for existing pieces and I was
wondering how I would go about doing this efficiently. Thanks

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Re: searching a list of lists as a two-dimensional array?

[agent-s]

Thanks for the help guys but I'm a newbie at this and from what I
understand from the code, it looks like you guys are using a two
dimensional array. I am not using a two dimensional array. Basically,
it looks like this:

[
[' ',' ',' ',' ',' ',' ',' ',' '],
[' ',' ',' ',' ',' ',' ',' ',' '],
[' ',' ',' ',' ',' ',' ',' ',' '],
[' ',' ',' ',' ',' ',' ',' ',' '],
[' ',' ',' ',' ',' ',' ',' ',' '],
[' ',' ',' ',' ',' ',' ',' ',' '],
[' ',' ',' ',' ',' ',' ',' ',' '],
[' ',' ',' ',' ',' ',' ',' ',' ']
]

above: a list of lists NOT a two-dimensional array

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Re: searching a list of lists as a two-dimensional array?

[agent-s]

OK I just realized that a list of lists can be accessed in the same
way a 2d array would be accessed. Thanks anyways guys.

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python not returning true

[agent-s]

I have a function, generally described as so:

def function(args):
if condition:
if condition2:
function(args+1)
elif condition3:
print "text"
return True
else:
return False

which is used in:

if function(args):
print "ok"


so here basically "text" will print out when condition3 is true but it
will not print out "ok" when condition3 is true. When it's true it
should print out borth "text" and "ok"

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Re: python not returning true

[agent-s]

On Feb 13, 9:37 pm, "John Machin" <[EMAIL PROTECTED]> wrote:
> On Feb 14, 4:15 pm, "agent-s" <[EMAIL PROTECTED]> wrote:
>
> > I have a function, generally described as so:
>
> > def function(args):
> > if condition:
> > if condition2:
> > function(args+1)
>
>   return None> elif condition3:
> > print "text"
> > return True
> > else:
> > return False
>
>else:
>return None
>
> There are two cases, indicated above, where you don't explicitly do a
> "return", so you fall off the end of the function, and Python returns
> None.
>
> Then when the function's caller tests the returned value, None is
> treated as logically false.
>
> > which is used in:
>
> > if function(args):
> > print "ok"
>
> > so here basically "text" will print out when condition3 is true but it
> > will not print out "ok" when condition3 is true. When it's true it
> > should print out borth "text" and "ok"
>
> In the second last sentence, it is difficult to determine what you
> think is expected behaviour and what you say is the actual behaviour.
> In the last sentence, what does the first "it" refer to?
>
> If the knowledge about returning None doesn't help you, try some
> standard(??) techniques like inserting print statements or debugger
> break-points.
>
> HTH,
> John

Thanks! That was exactly what it was. I solved it by using "return
function(args+1)" instead of simply "function(args+1)."

btw Steven you are so witty I hope to one day pwn noobs on newsgroups
too.

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Re: python not returning true

[agent-s]

Wow. I didn't realize you guys took this so seriously.

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