"and" and "or" on every item in a list

[GHZ]

Is this the best way to test every item in a list?


def alltrue(f,l):
return reduce(bool.__and__,map(f,l))

def onetrue(f,l):
return reduce(bool.__or__,map(f,l))

>>> alltrue(lambda x:x>1,[1,2,3])
False
>>>
>>> alltrue(lambda x:x>=1,[1,2,3])
True
>>>

Thanks

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Re: "and" and "or" on every item in a list

[GHZ]

Thanks for the answers,  I suspected something like any(), all()
existed.  Also got me thinking about generator expressions, my code is
full of list comprehensions for lists I don't keep.

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Re: Noob question

[GHZ]

Had the same issue.  What you want is: reload()
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Re: Recommended SOAP library?

[GHZ]

if you require a SOAP client, then I would recommend SUDS
https://fedorahosted.org/suds/

Other options are not in active development, so is difficult to get
support.

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Re: Installing paramiko and pycrypto

[GHZ]

I installed from here:

http://bazaar-vcs.org/WindowsInstall

first pycrypto-2.0.1.win32-py2.5.zip
then paramiko-1.7.1-ctypes.win32.exe
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Re: Why is there no GUI-tools like this for Windows?

[GHZ]

There is  http://www.codeplex.com/IronPythonStudio
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Re: How do I compare files?

[GHZ]

On Jul 23, 1:27 am, Clay Hobbs <[EMAIL PROTECTED]> wrote:
> I am making a program that (with urllib) that downloads two jpeg files
> and, if they are different, displays the new one.  I need to find a way
> to compare two files in Python.  How is this done?
>
> -- Ratfink

import hashlib

file = open(path)
m = hashlib.md5()
m.update(file.read())
digest = m.hexdigest()
file.close()


and compare the digest on both files
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filter in for loop

[GHZ]

I would like to say something like:

for x in l if :


e.g.

for filename in os.listdir(DIR) if filename[-4:] == '.xml':



instead of having to say:

for filename in os.listdir(DIR):
if filename[-4:] == '.xml':


or

for filename in (f for f in os.listdir(DIR) if f[-4] == '.xml'):



is there a shortcut I'm missing?
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