start default application for read a pdf from python
I try to start a default application for reading a pdf file inside the python script. I try os.startfile(name,option) but say me startfile not implemented there are some system to start for example acrobar or okular from the script with a name of pdf file? thenks Angelo -- http://mail.python.org/mailman/listinfo/python-list
Re: start default application for read a pdf from python
Sorry to not be very specific
My problem is a way to run a default application to read and show a pdf
file from unix or windows, i have a mixed ambient in the office, so I am
try to find a way to start a application to show this pdf file I
generate whith reportlab. actualy I write a file in a directory and then
I have to open the directory find a file and open it, I try to find a
way to do this automatic, in this way then they only have to close the
windows.
sorry I do not see before is only for windows, so this means under unix
system I cant to use.
thenks for the suggestion
Angelo
Grant Edwards ha scritto:
On 2009-09-08, Angelo Ballabio wrote:
I try to start a default application for reading a pdf file
inside the python script.
I try
os.startfile(name,option) but say me startfile not implemented
Are you _sure_ it says startfile not implemented? Or does
it say this:
>>> os.startfile("foo.bar")
Traceback (most recent call last):
File "", line 1, in
AttributeError: 'module' object has no attribute 'startfile'
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Re: start default application for read a pdf from python
Thenks for this suggestion, at the end I find this solution
import os
.
.
#then where I decide to show the file in the default application I put this
#file_name the name I construct with path and all necessary
#recor contain all the data of one record end the 4th position
#the name of the file
#for example
file_name = os.path.join('document',str(record[3]) + ".pdf")
#the joun function make the separator from ducoment to the file
#name relative to operatin system (windows '\') , (unix '/')
#then where I call the default program
if os.name == "nt":
os.filestart("%s" % nome_file)
elif os.name == "posix":
os.system("/usr/bin/xdg-open %s" % nome_file)
Other nice solution is
import webbrowser
.
.
.
webbrowser.open(file_name)
The difference is in unix sistem, the first call the default program for
read the file of type, in this case pdf, this meens okular, acroread, or
whatever, the second open the konqueror in kde desktop, in windows the
function os.filestart call the default application for thet type of file
interesting discussion about this I find in :
http://ubuntuforums.org/showthread.php?t=1003198
very thenks to all
Angelo
Albert Hopkins ha scritto:
The (most) portable way to do so in Linux (not necessarily Unix) is to
use the xdg-open command. Ex,
subprocess.Popen(['xdg-open', 'my-document.pdf'])
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