Re: [Python-Dev] how GNU stow is complementary rather than alternative to distutils

2009-05-11 Thread Giuseppe Ottaviano
Talking of stow, I take advantage of this thread to do some shameless  
advertising :)
Recently I uploaded to PyPI a software of mine, BPT [1], which does  
the same symlinking trick of stow, but it is written in Python (and  
with a simple api) and, more importantly, it allows with another trick  
the relocation of the installation directory (it creates a semi- 
isolated environment, similar to virtualenv).
I find it very convenient when I have to switch between several  
versions of the same packages (for example during development), or I  
have to deploy on the same machine software that needs different  
versions of the dependencies.


I am planning to write an integration layer with buildout and  
easy_install. It should be very easy, since BPT can handle directly  
tarballs (and directories, in trunk) which contain a setup.py.


HTH,
Giuseppe

[1] http://pypi.python.org/pypi/bpt
P.S. I was not aware of stow, I'll add it to the references and see if  
there are any features that I can steal



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Re: [Python-Dev] What if replacing items in a dictionary returns the new dictionary?

2011-05-05 Thread Giuseppe Ottaviano
On Fri, Apr 29, 2011 at 4:05 PM, Roy Hyunjin Han
 wrote:
>>   You can implement this in your own subclass of dict, no?
>
> Yes, I just thought it would be convenient to have in the language
> itself, but the responses to my post seem to indicate that [not
> returning the updated object] is an intended language feature for
> mutable types like dict or list.

In general nothing stops you to use a proxy object that returns itself
after each method call, something like


class using(object):
def __init__(self, obj):
self._wrappee = obj

def unwrap(self):
return self._wrappee

def __getattr__(self, attr):
def wrapper(*args, **kwargs):
getattr(self._wrappee, attr)(*args, **kwargs)
return self
return wrapper


d = dict()
print using(d).update(dict(a=1)).update(dict(b=2)).unwrap()
# prints {'a': 1, 'b': 2}
l = list()
print using(l).append(1).append(2).unwrap()
# prints [1, 2]
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