[issue46574] itertools.count should work with non-number types
New submission from Mital Ashok : There's no reason that `count('', 'a')` for `'', 'a', 'aa', ...` or `count((), (1,))` for `(), (1,), (1, 1), ...` shouldn't work. count(a, b) should be equivalent to accumulate(chain((a,), repeat(b))) The docs don't strongly suggest that it won't work (it says *start* is a number, but the "roughly equivalent to" generator would work for str/tuple/etc) -- components: Library (Lib) messages: 412095 nosy: Mital Ashok priority: normal severity: normal status: open title: itertools.count should work with non-number types type: enhancement versions: Python 3.11 ___ Python tracker <https://bugs.python.org/issue46574> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue30955] \\N in f-string causes next { to be literal if not escaped
New submission from Mital Ashok: Take this format python code: import unicodedata c = chr(0x012345) To print that character as a string literal, you would expect to do: print(f"'\\N{{{unicodedata.name(c)}}}'") Which should print a literal quote (`'`), a backwards slash (`\\` -> `\`), an `N`, and the two `{{` should escape and print `{`, followed by the f-expression `unicodedata.name(c)`, then the `}}` would print one `}`, and then another literal quote (`'`). However, this raises a `SyntaxError: f-string: single '}' is not allowed`. The way to do this without a syntax error is like so: print(f"'\\N{{unicodedata.name(c)}}}'") Which prints the expected: '\N{CUNEIFORM SIGN URU TIMES KI}' The shortest way to reproduce this is: f'\\N{' Which works, and: f'\\N{{' which raises an error, even though the first one should raise an error (`SyntaxError: f-string: expecting '}'`). -- messages: 298563 nosy: Mital Ashok priority: normal severity: normal status: open title: \\N in f-string causes next { to be literal if not escaped versions: Python 3.6, Python 3.7 ___ Python tracker <http://bugs.python.org/issue30955> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue24327] yield unpacking
New submission from Mital Ashok: (This is more of a feature request than a bug, but https://www.python.org/dev/peps/pep-0042/ said to post it here) My request is to have syntax like this: yield *iterable to lazily return the iterable's items, not much unlike: # ... for i in iterable: yield i # ... This is because I constantly find myself yielding all the values in, say, a list, then modifying it and yielding it in a loop. -- messages: 244397 nosy: Mital Ashok priority: normal severity: normal status: open title: yield unpacking type: enhancement versions: Python 3.6 ___ Python tracker <http://bugs.python.org/issue24327> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com