[issue30965] Unexpected behavior of operator "in"
New submission from Mihai Cara: Unexpected behavior of operator "in" when checking if a list/tuple/etc. contains a value: >>> 1 in [1] is True False >>> (1 in [1]) is True True Is this a bug? If not, please explain why first variant return False. -- messages: 298633 nosy: mcara priority: normal severity: normal status: open title: Unexpected behavior of operator "in" type: behavior versions: Python 2.7, Python 3.5 ___ Python tracker <http://bugs.python.org/issue30965> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue30965] Unexpected behavior of operator "in"
Mihai Cara added the comment: Thank you! It was my fault: I was not expecting `in` to be a comparison operator. -- ___ Python tracker <http://bugs.python.org/issue30965> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue30965] Unexpected behavior of operator "in"
Mihai Cara added the comment: I am sure that some time ago I read that `in` is a comparison operator but I forgot it and I was thinking that (x in y) would be equivalent to (replaced with) the return value of y.__contains__(x). -- ___ Python tracker <http://bugs.python.org/issue30965> ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
