New submission from Jan Švec :
re.sub() is behaving incorrectly, if re.IGNORECASE is used. Tested on 2.7, 3.4
and 3.6. The code follows:
import re
def subst(text):
text = re.sub(r"\bnine\b", "niner", text, re.IGNORECASE)
return text
print(subst("nine nine nine nine"))
It prints "niner niner nine nine". Without the re.IGNORECASE, the output is
correct: "niner niner niner niner"
--
components: Regular Expressions
messages: 321062
nosy: Jan Švec, ezio.melotti, mrabarnett
priority: normal
severity: normal
status: open
title: Bad behavior of re.IGNORECASE
type: behavior
versions: Python 2.7, Python 3.4, Python 3.6
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<https://bugs.python.org/issue34048>
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