[PHP] proxy
Hi list,
I am trying to create a link checker that would look for broken URLs
with help of the following code"
$handle = @fopen("http://www.circle.am";, "r");
if ($handle):
print "OK";
else:
print "Error";
endif;
The problem is that I want to check if the links are accessible under
certain proxy, so is there any way to tell the script to open the URL
under a proxy?
Thank you in advance.
Ed
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Re[2]: [PHP] proxy
Thank you Roman and Jochem,
I'll try both.
Best regards,
Ed
Sunday, January 21, 2007, 6:27:44 PM, you wrote:
> # [EMAIL PROTECTED] / 2007-01-21 17:29:56 +0300:
>> I am trying to create a link checker that would look for broken URLs
>> with help of the following code"
>>
>> $handle = @fopen("http://www.circle.am";, "r");
>> if ($handle):
>> print "OK";
>> else:
>> print "Error";
>> endif;
>>
>> The problem is that I want to check if the links are accessible under
>> certain proxy, so is there any way to tell the script to open the URL
>> under a proxy?
> Several, start by googling for connect.c
> --
> How many Vietnam vets does it take to screw in a light bulb?
> You don't know, man. You don't KNOW.
> Cause you weren't THERE. http://bash.org/?255991
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Re: [PHP] preg_replace();
I am not a very experienced programmer, but I think that "str_replace"
can be used in this case:
$new_string=str_replace('|', '_', $old_string)
then use the same function to replace spaces.
Ed
Friday, February 2, 2007, 9:30:37 PM, you wrote:
> Hi all,
> I want replace the "|" (pipe) and the " " (space) chars where are
> between " (double-quotes) by an underscore "_" with the
> preg_replace(); funtction.
> Can someone help me to find the correct regex.
> Thanks in advance
> Seb
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Re[2]: [PHP] preg_replace();
I have tasted the code and it worked fine (if I got you right):
$old_string="lazy \"|\" dog";
$new_string=str_replace('"|"', '_', $old_string);
print $new_string;
I got "lazy_dog"
Ed
Friday, February 2, 2007, 10:01:14 PM, you wrote:
> Thanks,
> but I think that I must use preg_replace because the condition is: replace
> the chars (pipe or space) when they are between "
> ie : src=file:///h|/hjcjdgh dlkgj/dgjk.jpg" to
> src=file:///h_/hjcjdgh_dlkgj/dgjk.jpg"
> Seb
> - Original Message -
> From: <[EMAIL PROTECTED]>
> To: "Sébastien WENSKE" <[EMAIL PROTECTED]>
> Cc:
> Sent: Friday, February 02, 2007 8:38 PM
> Subject: Re: [PHP] preg_replace();
> I am not a very experienced programmer, but I think that "str_replace"
> can be used in this case:
> $new_string=str_replace('|', '_', $old_string)
> then use the same function to replace spaces.
> Ed
> Friday, February 2, 2007, 9:30:37 PM, you wrote:
>> Hi all,
>> I want replace the "|" (pipe) and the " " (space) chars where are
>> between " (double-quotes) by an underscore "_" with the
>> preg_replace(); funtction.
>> Can someone help me to find the correct regex.
>> Thanks in advance
>> Seb
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Re[4]: [PHP] preg_replace();
Try this one:
$old_string="lazy \"some chars|some chars\" dog";
$new_string=str_replace('|', '_', $old_string);
print $new_string;
Ed
Friday, February 2, 2007, 10:39:59 PM, you wrote:
> ok, but :
> $old_string="lazy \"some chars|some chars\" dog";
> $new_string=str_replace('"|"', '_', $old_string);
> don't work
> sorry for my bad english, i'm french.
> - Original Message -
> From: <[EMAIL PROTECTED]>
> To: "Sébastien WENSKE" <[EMAIL PROTECTED]>
> Sent: Friday, February 02, 2007 9:22 PM
> Subject: Re[2]: [PHP] preg_replace();
> I have tasted the code and it worked fine (if I got you right):
> $old_string="lazy \"|\" dog";
> $new_string=str_replace('"|"', '_', $old_string);
> print $new_string;
> I got "lazy_dog"
> Ed
> Friday, February 2, 2007, 10:01:14 PM, you wrote:
>> Thanks,
>> but I think that I must use preg_replace because the condition is: replace
>> the chars (pipe or space) when they are between "
>> ie : src=file:///h|/hjcjdgh dlkgj/dgjk.jpg" to
>> src=file:///h_/hjcjdgh_dlkgj/dgjk.jpg"
>> Seb
>> - Original Message -
>> From: <[EMAIL PROTECTED]>
>> To: "Sébastien WENSKE" <[EMAIL PROTECTED]>
>> Cc:
>> Sent: Friday, February 02, 2007 8:38 PM
>> Subject: Re: [PHP] preg_replace();
>> I am not a very experienced programmer, but I think that "str_replace"
>> can be used in this case:
>> $new_string=str_replace('|', '_', $old_string)
>> then use the same function to replace spaces.
>> Ed
>> Friday, February 2, 2007, 9:30:37 PM, you wrote:
>>> Hi all,
>>> I want replace the "|" (pipe) and the " " (space) chars where are
>>> between " (double-quotes) by an underscore "_" with the
>>> preg_replace(); funtction.
>>> Can someone help me to find the correct regex.
>>> Thanks in advance
>>> Seb
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Re: [PHP] Pop up window in PHP code
Try this:
function poptastic(url)
{
newwindow=window.open(url,'name','height=490,width=900,left=150,top=175');
if (window.focus) {newwindow.focus()}
}
click here";
?>
Ed
> I am trying to open a Java script pop up widow from within the php code. Not
> able to get it done, the error I think is in the use of "" '' .. I mean
> double and/or single quote. Do not know how to place those. Please advice.
> The code is below:
> echo "
>
> $shopname
> $category
> $subcategory
> $level
> javascript:poptastic( Details
> ";
> $i++;
> The Javascript code is:
>
> var newwindow;
> function poptastic(url)
> {
>
> newwindow=window.open(url,'name','height=490,width=900,left=150,top=175');
> if (window.focus) {newwindow.focus()}
> }
>
> The javascript code works perfect with other pages and within HTML, its just
> that the PHP is not supporting the quotes and double quotes. I have even
> tried &rsquo &rdquo and all.
> Thanks in advance
> --
> View this message in context:
> http://www.nabble.com/Pop-up-window-in-PHP-code-tf3167481.html#a8786668
> Sent from the PHP - General mailing list archive at Nabble.com.
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Re: [PHP] Pop up window in PHP code
Sorry, if already posted, just did not get any confirmation, wanted to
make sure the e-mail has been sent.
Try this:
function poptastic(url)
{
newwindow=window.open(url,'name','height=490,width=900,left=150,top=175');
if (window.focus) {newwindow.focus()}
}
click here";
?>
Ed
> I am trying to open a Java script pop up widow from within the php code. Not
> able to get it done, the error I think is in the use of "" '' .. I mean
> double and/or single quote. Do not know how to place those. Please advice.
> The code is below:
> echo "
>
> $shopname
> $category
> $subcategory
> $level
> javascript:poptastic( Details
> ";
> $i++;
> The Javascript code is:
>
> var newwindow;
> function poptastic(url)
> {
>
> newwindow=window.open(url,'name','height=490,width=900,left=150,top=175');
> if (window.focus) {newwindow.focus()}
> }
>
> The javascript code works perfect with other pages and within HTML, its just
> that the PHP is not supporting the quotes and double quotes. I have even
> tried &rsquo &rdquo and all.
> Thanks in advance
> --
> View this message in context:
> http://www.nabble.com/Pop-up-window-in-PHP-code-tf3167481.html#a8786668
> Sent from the PHP - General mailing list archive at Nabble.com.
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