[PHP] PLEASE HELP! session variable fails to persist!!
Hi,
My session variables won't persist, could someone help me with this problem?
I spent all day trying to figure out what is wrong, and I still don't know
why I couldn't get it to work. Here is an example script:
";
echo "session var: ".$_SESSION["var"]."";
fnB();
function fnA(){
$_SESSION["var"]=1;
}
function fnB(){
if(isset($_SESSION["var"])){
echo "session var is set...";
}
else{
echo "session var is not set...";
fnA();
echo $_SESSION["var"];
}
}
?>
Here is the out put from this script:
"
session id: ee030ac6e15ea2c01e1dd4fe40f3ab30
session var:
session var is not set...
1
"
The session ID is the same for a given session, that means the server knows
its the same session. And since I get the value "1" each time, I can see
that the $_SESSION["var"] is a global variable with a value of "1". But it
seems that once the script is finished, this variable runs out of scope! A
session variable should persist for the duration of the session. It should
not run out of scope like this. Could someone with more experience tell me
what am I doing wrong? Thanks in advance.
Zlutarch
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Re: [PHP] PLEASE HELP! session variable fails to persist!!
Hi Stuart, I tried your idea but it didn't work. When I used session_encode(), I got nothing! It seems that it's not being registered as a session variable. Any idea why that is the case? Thanks, Zlutarch >From: Stuart Dallas <[EMAIL PROTECTED]> >Reply-To: Stuart Dallas <[EMAIL PROTECTED]> >To: [EMAIL PROTECTED] >Subject: Re: [PHP] PLEASE HELP! session variable fails to persist!! >Date: Sat, 15 Jun 2002 01:05:47 +0100 > >On Saturday, June 15, 2002 at 12:53:47 AM, Zlutarch G. wrote: > > The session ID is the same for a given session, that means the server >knows > > its the same session. And since I get the value "1" each time, I can see > > that the $_SESSION["var"] is a global variable with a value of "1". But >it > > seems that once the script is finished, this variable runs out of scope! >A > > session variable should persist for the duration of the session. It >should > > not run out of scope like this. Could someone with more experience tell >me > > what am I doing wrong? Thanks in advance. > >Your code looks ok so I'm guessing that you are just refreshing this page >to >see if the session variables persist. If that is the case then of course >you're >not seeing them persist. In order for the page to import the current >session it >must know what the session id is. Try putting a link on that page that >links to >the same page. Click on the link and you should find that the session >variable >now persists. > >-- >Stuart > > >-- >PHP General Mailing List (http://www.php.net/) >To unsubscribe, visit: http://www.php.net/unsub.php > _ Join the worlds largest e-mail service with MSN Hotmail. http://www.hotmail.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: Re[2]: [PHP] PLEASE HELP! session variable fails to persist!!
Hi Stuart,
I tried your script, but I couldn't get it to work. I guess it has to be
something wrong with my server configuration? I am using Apache 1.3.14. I am
new to Apache, so I don't know what could possibly be the configuration
problem. Do you have any ideas? Thanks a lot.
Zlutarch
>From: Stuart Dallas <[EMAIL PROTECTED]>
>Reply-To: Stuart Dallas <[EMAIL PROTECTED]>
>To: "Zlutarch G." <[EMAIL PROTECTED]>
>Subject: Re[2]: [PHP] PLEASE HELP! session variable fails to persist!!
>Date: Sat, 15 Jun 2002 01:32:51 +0100
>
>On Saturday, June 15, 2002 at 1:24:43 AM, you wrote:
> > I tried including a link, but it didn't work. When I used
>session_encode(),
> > I got nothing! Some how it was not registered as a session variable. Any
> > idea why that could be?
>
>I hope this will help clear up any confusion.
>
>Go here: http://www.devserver.org/test/session.php and click on the link.
>
>This is the code...
>
> session_start();
> $sID=session_id();
> echo "session id: $sID";
> echo "session var: ".$_SESSION["var"]."";
>
> fnB();
> function fnA(){
> $_SESSION["var"]=1;
> }
> function fnB(){
> if(isset($_SESSION["var"])){
> echo "session var is set...";
> }
> else{
> echo "session var is not set...";
> fnA();
> echo $_SESSION["var"];
> }
> }
>
> print 'reload page';
>?>
>
>It works. If this code doesn't work for you then it's something wrong with
>your
>server configuration.
>
>--
>Stuart
>
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Re: Re[4]: [PHP] PLEASE HELP! session variable fails to persist!!
Hi Stuart, Thanks. I added error_reporting (E_ALL); and it gave me the following error msg: "Warning: Undefined index: var in c:\program files\apache group\apache\htdocs\php\superstock\ssi\valuecalc\valuescreen\testsess.php on line 6" Here is line 6: echo "session var: ".$_SESSION["var"].""; Apparently, there is no session variable! Does that mean the session was not created? I thought the session is created if I get the same session ID each time I reload the page. Zlutarch P.S. I wish I could post the server address, but its on a private network. Only computers on the intra net have access to the server. I will see what I can do. >From: Stuart Dallas <[EMAIL PROTECTED]> >Reply-To: Stuart Dallas <[EMAIL PROTECTED]> >To: [EMAIL PROTECTED] >Subject: Re[4]: [PHP] PLEASE HELP! session variable fails to persist!! >Date: Sat, 15 Jun 2002 01:49:40 +0100 > >On Saturday, June 15, 2002 at 1:42:45 AM, Zlutarch G. wrote: > > I tried your script, but I couldn't get it to work. I guess it has to be > > something wrong with my server configuration? I am using Apache 1.3.14. >I am > > new to Apache, so I don't know what could possibly be the configuration > > problem. Do you have any ideas? Thanks a lot. > >Do you get any errors? Add the following line immediately before the call >to >session_start()... > >error_reporting (E_ALL); > >My guess is that it's failing to create the session, but if your error >reporting is too low you may not be told about it. > >Is the server you are using public? Can you post the URL so we can take a >look? > >-- >Stuart > > >-- >PHP General Mailing List (http://www.php.net/) >To unsubscribe, visit: http://www.php.net/unsub.php > _ Chat with friends online, try MSN Messenger: http://messenger.msn.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
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Hi,
I am learning how to use the PHP Java extension. I used the example
script/codes found in the PHP Java documentation:"
getProperty('java.version').' ';
print 'Java vendor=' .$system->getProperty('java.vendor').' ';
print 'OS='.$system->getProperty('os.name').' '.
$system->getProperty('os.version').' on '.
$system->getProperty('os.arch').' ';
// java.util.Date example
$formatter = new Java('java.text.SimpleDateFormat',
", dd, 'at' h:mm:ss a ");
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?>"
And I got the correct output:
Java version=1.3.0
Java vendor=Sun Microsystems Inc.
OS=Windows 2000 5.0 on x86
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the following error message: "Apache.exe has generated errors and will be
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this PHP script?
Thanks,
Zlutarch
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