Re: [PHP] mail() and passwords
I mean the only way is to use existing classes for sending emails via smtp socket or to write your own one. tom On Tue, 9 Mar 2004 03:37:33 -0500 "Will" <[EMAIL PROTECTED]> wrote: > How do I modify the following to except a password for the SMTP server? > > [mail function] > SMTP = localhost > > sendmail_from = [EMAIL PROTECTED] > > Please help!! > > Thanks in advance! > > ~WILL~ > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php -- == Tomas Meinlschmidt, SBN3, MCT, MCP, MCP+I, MCSE, NetApp Filer & NetCache gPG fp: CB78 76D9 210F 256A ADF4 0B02 BECA D462 66AB 6F56 / $ID: 66AB6F56 GCS d-(?) s: a- C++ ULHISC*$ P+++> L+++$> E--- W+++$ N++(+) !o !K w(---) !O !M V PS+ PE Y+ PGP++ t+@ !5 X? R tv b+ !DI D+ G e>+++ h r+++ z+++@ == -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] getting message from file
see php.net/file or php.net/fread
$file = "somefile.dat";
if ([EMAIL PROTECTED]($file)) return 0;
$filecontent = file($file);
$numbers = array();
if (is_array($filecontent) && count($filecontent)) {
foreach($filecontent as $line) {
// delete more than one space
$line = ereg_replace("[ ]*"," ", $line);
// explode whole line into array
$numbers_temp = explode(" ", $line);
// add temp arr to $numbers array
$numbers = array_merge($numbers, $numbers_temp);
}
}
and now you have all the data in $numbers array...
you DON'T need to convert strings to numbers.
/tom
On Tue, 9 Mar 2004 15:25:16 +0800
"Kenneth" <[EMAIL PROTECTED]> wrote:
> My data file is sth like:
> 2.208 2.18 2.415 2.283 2.234 2.155 2.389 2.201
> 2.204 2.181 2.43 2.285 2.231 2.164 2.387 2.197
> 2.2 2.179 2.429 2.29 2.225 2.181 2.385 2.195
> 2.196 2.178 2.424 2.291 2.225 2.213 2.386 2.19
>
> I would like to get these data in order to plot graph.
>
> I've tried to use fgets() and then convert them from string back into
> array...but it seems doesn't work~
>
> Thanks,
> Kenneth
>
>
>
> "Jason Wong" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
> > On Monday 08 March 2004 09:04, Kenneth wrote:
> >
> > > I have a problem on getting content from a data file (data.txt).
> > > I have many numbers in the file...all of them are about 2.XXX, and I
> need
> > > them to plot a graph.
> >
> > What does your data file look like? Show a few sample lines.
> >
> > > But I just can't read them out as a integer.
> >
> > What code did you use?
> >
> > --
> > Jason Wong -> Gremlins Associates -> www.gremlins.biz
> > Open Source Software Systems Integrators
> > * Web Design & Hosting * Internet & Intranet Applications Development *
> > --
> > Search the list archives before you post
> > http://marc.theaimsgroup.com/?l=php-general
> > --
> > /*
> > "Have you lived here all your life?"
> > "Oh, twice that long."
> > */
>
> --
> PHP General Mailing List (http://www.php.net/)
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==
Tomas Meinlschmidt, SBN3, MCT, MCP, MCP+I, MCSE, NetApp Filer & NetCache
gPG fp: CB78 76D9 210F 256A ADF4 0B02 BECA D462 66AB 6F56 / $ID: 66AB6F56
GCS d-(?) s: a- C++ ULHISC*$ P+++> L+++$> E--- W+++$ N++(+) !o
!K w(---) !O !M V PS+ PE Y+ PGP++ t+@ !5 X? R tv b+ !DI D+ G e>+++
h r+++ z+++@
==
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Re: [PHP] RE: R: [PHP] Get "nice" variables from POST
oops. It's much better to use single quotes and entire variable in {}
eg
.. where user_id = '{$_POST['user_id']}' ...
realize - POST variable user_id has no value, so in your code it will be as
"select * from users where user_id =";
as a result - you have wrong sql query.
/tom
On Fri, 12 Mar 2004 13:40:12 +
"Mike Mapsnac" <[EMAIL PROTECTED]> wrote:
> I try to use quotes in the query and this doesn't work.
>$query = "SELECT * FROM user WHERE user_id = '$_POST['user_id']}'";
> But you use brackets and it works.. Why do you use brackets ?
> $query = "SELECT * FROM user WHERE user_id = ${_POST['user_id']}";
>
>
> >From: "Alessandro Vitale" <[EMAIL PROTECTED]>
> >To: "Mike Mapsnac" <[EMAIL PROTECTED]>,<[EMAIL PROTECTED]>
> >Subject: R: [PHP] Get "nice" variables from POST
> >Date: Thu, 11 Mar 2004 17:30:57 +0100
> >
> >hi,
> >
> >why don't you simple use the $_POST vars? they are already available to
> >you,
> >so why you should copy them?
> >
> >example:
> >
> >function show_function()
> >{
> >$query = "SELECT * FROM user WHERE user_id = ${_POST['user_id']}";
> >
> >}
> >
> >at the same time:
> >- you save a lot of time ( you don't need to write code for copying vars )
> >- you can always identify in your script the variable you are using is the
> >one that comes from POST
> >
> >cheers,
> >
> >alessandro
> >
> >-Messaggio originale-
> >Da: Mike Mapsnac [mailto:[EMAIL PROTECTED]
> >Inviato: giovedě 11 marzo 2004 15.51
> >A: [EMAIL PROTECTED]
> >Oggetto: [PHP] Get "nice" variables from POST
> >
> >
> >I have about 10 fields in the form. And I get the fields through POST:
> >//Get Variable from the form
> >$username = $_POST['username'];
> >$password = $_POST['password'];
> >$password2 = $_POST['password2'];
> >$email = $_POST['email'];
> >$email2 = $_POST['email2'];
> >$nickname = $_POST['name'];
> >$city = $POST['city'];
> >$state = $_POST['state'];
> >$country = $_POST['country'];
> >$misc = $_POST['misc'];
> >$country = $_POST['country'];
> >
> >It works but it looks ugly. For each variable I have statemet. Is there a
> >way to get the variables in the loop?
> >
> >I'm looking for "nice" way to get variables from POST?
> >
> >Thanks
> >
> >_
> >Frustrated with dial-up? Lightning-fast Internet access for as low as
> >$29.95/month. http://click.atdmt.com/AVE/go/onm00200360ave/direct/01/
> >
> >--
> >PHP General Mailing List (http://www.php.net/)
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> >
>
> _
> Get a FREE online computer virus scan from McAfee when you click here.
> http://clinic.mcafee.com/clinic/ibuy/campaign.asp?cid=3963
>
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Re: [PHP] Get "nice" variables from POST
if (is_array($_POST)) {
foreach($_POST as $name=>$value) {
${$name} = $value;
}
}
/tom
On Fri, 12 Mar 2004 15:59:00 +0100 (CET)
Hans Juergen von Lengerke <[EMAIL PROTECTED]> wrote:
> I know this isn't what you want, but nevertheless, this
> "does not look ugly":
>
>
>
> # Get variables from the form
> #
> $username = $_POST['username'];
> $password = $_POST['password'];
> $password2 = $_POST['password2'];
> $email = $_POST['email'];
> $email2= $_POST['email2'];
> $nickname = $_POST['name'];
> $city = $POST['city'];
> $state = $_POST['state'];
> $country = $_POST['country'];
> $misc = $_POST['misc'];
> $country = $_POST['country'];
>
>
>
> and there you go, you can now easily spot a typo too :-)
>
> Hans
>
>
> PS: If you read this with variable-width font
> you might think I am an idiot. never mind.
>
>
> > Date: Thu, 11 Mar 2004 14:51:25 +
> > From: Mike Mapsnac <[EMAIL PROTECTED]>
> > To: [EMAIL PROTECTED]
> > Subject: [PHP] Get "nice" variables from POST
> >
> > I have about 10 fields in the form. And I get the fields through POST:
> > //Get Variable from the form
> > $username = $_POST['username'];
> > $password = $_POST['password'];
> > $password2 = $_POST['password2'];
> > $email = $_POST['email'];
> > $email2 = $_POST['email2'];
> > $nickname = $_POST['name'];
> > $city = $POST['city'];
> > $state = $_POST['state'];
> > $country = $_POST['country'];
> > $misc = $_POST['misc'];
> > $country = $_POST['country'];
> >
> > It works but it looks ugly. For each variable I have statemet. Is there a
> > way to get the variables in the loop?
> >
> > I'm looking for "nice" way to get variables from POST?
> >
> > Thanks
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
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Re: [PHP] load a URL and trap output
simple use fopen() or file()
as $fp = fopen("http://somedomain/some.url?blablah","r";);
and read via fread()
/tom
On Fri, 12 Mar 2004 10:54:53 -0500
Roger Spears <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I have this application which is accessed via a web portal. The first
> thing my application must do is make sure the visitor is logged in via
> the portal. The only way to do this is by making a request to a
> specific URL. This URL (which includes the log in cookie id) will
> return XML to my application. Once I parse this XML, I will know if
> visitors are logged in.
>
> Simple enough.
>
> How do I make my application load a URL and trap the returned data so
> that it never creates any browser output?
>
> My first reaction was header("Location: URL") but then I'd be handing
> off control to the URL and the output would appear in the browser.
>
> I've done some research and found system(), exec(), and passthru(). But
> I'm not sure if these functions are the proper way to do such a task
> especially since I'm calling a URL and not a specific UNIX command.
>
> Thanks,
> Roger
>
> --
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Re: [PHP] use of @ operator to suppress errors
Yes, it's normal.
You've to check if is that variable set if (isset($_GET['this'])) and than you didn't
get any
NOTICE about that undefined variable.
condition "if ($_GET['this'])" is not sufficient to check whether is variable set or
not.
/tom
On Mon, 15 Mar 2004 11:43:24 -
"Ben Joyce" <[EMAIL PROTECTED]> wrote:
> hi.
>
> i'm using error_reporting(0) and set_error_handler("MyErrorHandler") to
> manage my errors but I'm getting situations where a NOTICE error is thrown.
>
> For example if I refer to $_GET['this'] when there is no 'this' querystring
> key then i get the error.
>
> I've tried using @$_GET['this'] but it makes no difference.
>
> Is this normal?
>
> Thanks in advance.
>
> Ben
>
> p.s. PHP 4.3.4 on Windows 2003
>
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Re: [PHP] Anyway to access a class variable without using a return function?
I mean using get_object_vars() is much better.
and in the example I've seen there:
you HAVE TO define all the variables you're using in a class scope. eg
class myClass {
var $var1;
var $var2 = array();
function myClass($var) {
$vars =get_object_vars($this);
if (isset($vars[$var])) return $vars[$var];
return false;
}
}
/tom
On Mon, 15 Mar 2004 13:36:07 +0100
Marco Schuler <[EMAIL PROTECTED]> wrote:
> Hi!
>
> Am Mo, 2004-03-15 um 13.02 schrieb Dave Starling:
> > I think you could also do something like this:
> >
> > class MyClass {
> > function MyClass {
> > $this->var1="1";
> > $this->var2="2";
> > }
> > function GetVar($var) {
> > return $this->{$var};
> > }
> > }
> >
> > $test = new MyClass();
> >
> > echo $test->GetVar('var1').'';
> > echo $test->GetVar('var2').'';
>
> Better check first if property/var exists:
>
> function getVar($var)
> {
> $that = null;
> if (isset($this->$var)) {
> $that = $this->$var;
> }
> return $that;
> }
>
>
> --
> Regards
> Marco
>
> --
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Re: [PHP] catching URL#target params
Hi,
it could be done only by parsing $_SERVER['QUERY_STRING'] variable ...
eg
$querystring = $_SERVER['QUERY_STRING'];
eregi("#([a-z0-9_.-]*)", $querystring, $arg);
$hashtarget = $arg[1];
/tom
On Mon, 15 Mar 2004 08:52:43 -0500
David T-G <[EMAIL PROTECTED]> wrote:
> Hi, all --
>
> I know that I can easily see
>
> http://URL?param=value
>
> and even
>
> http://URL?value
>
> but I haven't found any way to capture
>
> http://URL#target
>
> as one would use to jump to a certain location in a plain HTML file.
> When I try this in a PHP file and run phpinfo, I see nothing that
> includes that target.
>
> Is there a var that will work for me?
>
>
> TIA & HAND
>
> :-D
> --
> David T-G * There is too much animal courage in
> (play) [EMAIL PROTECTED] * society and not sufficient moral courage.
> (work) [EMAIL PROTECTED] -- Mary Baker Eddy, "Science and Health"
> http://justpickone.org/davidtg/ Shpx gur Pbzzhavpngvbaf Qrprapl Npg!
>
>
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Re: [PHP] catching URL#target params
BACK BACK BACK. I'm a stupid fool ...
#something is NOT send to the server, so it's unable to track it ...
sorry
/tom
request was a.php?aasdf=1234a#greetz
and from apache log
someip - - [15/Mar/2004:15:01:37 +0100] "GET /~znouza/a.php?aasdf=1234a HTTP/1.1" 200
3325
On Mon, 15 Mar 2004 15:00:04 +0100
Tom Meinlschmidt <[EMAIL PROTECTED]> wrote:
> Hi,
>
> it could be done only by parsing $_SERVER['QUERY_STRING'] variable ...
>
> eg
>
> $querystring = $_SERVER['QUERY_STRING'];
> eregi("#([a-z0-9_.-]*)", $querystring, $arg);
>
> $hashtarget = $arg[1];
>
> /tom
>
> On Mon, 15 Mar 2004 08:52:43 -0500
> David T-G <[EMAIL PROTECTED]> wrote:
>
> > Hi, all --
> >
> > I know that I can easily see
> >
> > http://URL?param=value
> >
> > and even
> >
> > http://URL?value
> >
> > but I haven't found any way to capture
> >
> > http://URL#target
> >
> > as one would use to jump to a certain location in a plain HTML file.
> > When I try this in a PHP file and run phpinfo, I see nothing that
> > includes that target.
> >
> > Is there a var that will work for me?
> >
> >
> > TIA & HAND
> >
> > :-D
> > --
> > David T-G * There is too much animal courage in
> > (play) [EMAIL PROTECTED] * society and not sufficient moral courage.
> > (work) [EMAIL PROTECTED] -- Mary Baker Eddy, "Science and Health"
> > http://justpickone.org/davidtg/ Shpx gur Pbzzhavpngvbaf Qrprapl Npg!
> >
> >
>
>
> --
>
> --
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Re: [PHP] catching URL#target params
is possible to catch it by javascript, but I have no clue how to use with normal hrefs (not forms) try alert(document.location); and you'll get entrire request with #target part too. /tom -- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Anyway to access a class variable without using a return function?
thank, sure. function name should be myClassGetVar() :)
/tom
On Mon, 15 Mar 2004 14:49:55 +0100
Marco Schuler <[EMAIL PROTECTED]> wrote:
> Hi
>
> Am Mo, 2004-03-15 um 14.10 schrieb Tom Meinlschmidt:
> > I mean using get_object_vars() is much better.
> >
> > and in the example I've seen there:
> >
> > you HAVE TO define all the variables you're using in a class scope. eg
> > class myClass {
> > var $var1;
> > var $var2 = array();
> >
> > function myClass($var) {
> >$vars =get_object_vars($this);
> >if (isset($vars[$var])) return $vars[$var];
> >return false;
> > }
> > }
>
> Somewhat more elegant, yes. But: your function above is called myClass
> which is the classname and therefore this function is a _constructor_!
> As a constructor does not allow to return values, the above example
> would only work if you rename the function-name to something other than
> myClass!
>
> --
> Regards
> Marco
>
> --
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