Re: [PHP] Checkbox
Just using the readonly flag in the input tag is the easiest method, I think. - Original Message - From: "Reuben D. Budiardja" <[EMAIL PROTECTED]> Newsgroups: php.general To: "CPT John W. Holmes" <[EMAIL PROTECTED]>; "shaun" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Wednesday, March 26, 2003 2:26 PM Subject: Re: [PHP] Checkbox On Wednesday 26 March 2003 02:11 pm, CPT John W. Holmes wrote: > >On Wednesday 26 March 2003 01:43 pm, CPT John W. Holmes wrote: > > > > is it possible to have a checkbox that if it is specified to be > checked > > > > when the page is being formulated then it cannot be unchecked? > > > > > > No. No... No. > > > > > > If you already know you don't want it to be unchecked, then don't show > > > a checkbox. That's why we have PHP, so you can create your page > DYNAMICALLY > > > and not show bits and pieces when you don't need to. > > > > Although that is theoretically correct, there can be some reason why one > would > > want to display a checkbox anyway. Sometimes it can be clearer for the > user> > to see the GUI, asthetic reason, etc, etc. > True. In that case, though, I would just show an image of a checked check > box. The end result will be the same to the user, they will just think it's > a checkbox they cannot uncheck. But isn't it so much easier to type in that one line HTML + javascript than trying to get an image of a checked check box.. unless you have that handy, you'd have to eg. take a snapshot, or draw something, then save the file as an image file...hmm... and as you said, the effect will be the same to the user anyway RDB -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: php.ini question
does phpinfo(32) show the $action variable anywhere? If so just use the global array variable it shows up under. Personally I'd just use the $_GET['action'] alias. You can safely turn register_globals on if you're the only guy that runs scripts on that server and your scripts will never have to run on a server where it is off. If not you should do it for yourself in .htaccess or with ini_set(). Just be sure you are careful to initialize all internal variables that don't come directly from user input. - Original Message - From: "Joe Kupiszewski" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Wednesday, March 26, 2003 12:56 PM Subject: php.ini question > I didn't do the installation, but the phpinfo() shows the following: > > version - 4.2.3 > > ./configure' '--with-apxs=/usr/local/sbin/apxs' > '--with-config-file-path=/usr/local/etc' '--enable-versioning' > '--with-regex=system' '--without-gd' '--without-mysql' '--with-zlib' > '--with-mysql=/usr/local' '--prefix=/usr/local' 'i386-portbld-freebsd4.7' > > and the php path info is listed as > /usr/local/etc > > I do have root access as this is not a production machine, but for the life > of me cannot seem to get it to read the php.ini file. I believe php and > apache are interacting properly, or I wouldn't get the phpinfo() to work. > > The root of my real problem is that in trying to pass variable values from > php scripts to reinvocations of the same script using > http://pathtofile.php?action=3 > > I realize that this is a register_globals thing and that I can access it by > one of two ways: > > 1) Turning register_globals on (which many tell me is a security risk) > 2) Using $_REQUEST["action"] > 3) $HTTP_POST_VARS and $HTTP_GET_VARS -> with ["action"] > > However, using the second (haven't tried the 3rd) method and trying to > incorporate this variable value into an sql statement it bombs. This may be > more appropriate for an sql post, but thought I would throw it up here and > see if anyone can shed some light as to how php is interpreting 2) and 3) > > One workaround I have started with was just assigning the > $_REQUEST["action"] value to a new local variable and just using that, but > it seems like there would be an easier way and that this method is just a > lot of wasted work. > > Thanks for any thoughts and I am happy to post add'l script details. > > Joe... > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Default setting garbage
Obviously PHP got confused with your data types. I'll bet that $basedate had
been set to "5". Try this instead:
GetNextDate("4", "2003-03", 5);
Now I bet $frequency is 5 and $basedate is ""
- Original Message -
From: "Liam Gibbs" <[EMAIL PROTECTED]>
Newsgroups: php.general
To: "php list" <[EMAIL PROTECTED]>
Sent: Tuesday, March 25, 2003 4:43 PM
Subject: Re: [PHP] Default setting garbage
> < check it or try to look at it? Sorry if that sounds insulting.. just
trying
> to search for the simplest explaination. : < >>
>
> No, no. Not insulting at all. That's often my problem. But not in this
case.
> I even went to the 'trouble' of copying and pasting $frequency wherever I
> needed.
>
>
> Original problem:
> > Why is it that when I send call this function:
> > function GetNextDate($whichfriday, $month = "", $frequency = 1,
$basedate
> =
> > "")
> >
> > with this line:
> > GetNextDate("4", "2003-03", "5");
> >
> > that $frequency ends up ""? Whether I set it myself when I call the
> > function, or I leave it blank and let the function set it itself, it
ends
> up
> > with nothing in it. empty() returns 1, while isset() returns nothing on
> > this.
>
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[PHP] Re: Include Question
You could try this instead:
Checklogin.php
if (!$name || !password) {
$message = $enter_info;
}
if ($message){
include ("login.php");
echo $message;
exit;
}
But the way you had it should work, you might just need to
global $message;
right before the echo in login.php in case it is inside a function
- Original Message -
From: "Beauford.2002" <[EMAIL PROTECTED]>
Newsgroups: php.general
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Thursday, March 27, 2003 3:47 PM
Subject: Include Question
> Hi,
>
> First, I fixed my other problem of the stack overflow by moving the files
> back to the root directory (although I would rather have them in a login
> directory). Anyway, I have a question regarding the include function. I
have
> a login script in a file called login.php - in this file it includes
> checklogin.php and loginerrors.php. If the user inputs an incorrect login
I
> assign $messages the appropriate error from loginerrors, then I re-include
> login.php where I want to show the error message, but no matter what I do
> the error message will not show up.
>
> Example.
>
> Login.php
>
> Enter your Name:
> Enter Your Password:
> if ($message) { echo $message; }
>
> Checklogin.php
>
> if (!$name || !password) {
> $message = $enter_info;
> include ("login.php");
> exit;
> }
>
> Any help is appreciated.
>
>
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[PHP] Re: Can't connect to mysql
MySql is not compiled into PHP What does phpinfo say? (And not just the configure line) - Original Message - From: "Cditty" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Saturday, March 29, 2003 12:07 AM Subject: Can't connect to mysql > I just setup my home development server and I am having problems connecting > to the mysql server. Mysql is isntalled and is configured correctly. It > is running. Mysql is compiled into php, When I try to connect using > existing code, I get the following error. > > Fatal error: Call to undefined function: mysql_connect() > > I am using MySQL 4.0.12. I installed MySQL from rpms and installed the > following ones. > client, devel, server, shared, embedded > > Anyone have any ideas? > > CDitty > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] mysql ending at start up
Wow, Joe! You post to the wrong list, and your problem is sufficiently unusual (you have no err log?) that we can't give quick supportive answers, and then you whine at us. Not too cool. Please use the appropriate list. - Original Message - From: "Joseph Bannon" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Saturday, March 29, 2003 2:20 AM Subject: Re: [PHP] mysql ending at start up > > Please use the appropriate list. If you want a fast > > response take out a mysql support contract. > > > Thanks Jason. You're such a supportive individual > -lol. > > J. > > > > __ > Do you Yahoo!? > Yahoo! Platinum - Watch CBS' NCAA March Madness, live on your desktop! > http://platinum.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] require/include from a different directory
The call to include() must be relative to one of the directories listed in open_basedir, regardless of which file the call is made from. Usually the dir mentioned in open_basedir is the docroot, so in your case require "include/inc_file.php"; should work from any file, in any folder. - Original Message - From: "Greg Macek" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Saturday, March 29, 2003 3:37 PM Subject: Re: [PHP] require/include from a different directory > It seems I have found my problem. It has to do with the files I'm trying > to include. They also include other files and the directories it's > trying to include files from aren't working. I've found a workaround for > my situation for the time being. It's not pretty, but functional. > > On Sat, 2003-03-29 at 14:19, Greg Macek wrote: > > Hi, > > > > I'm having a problem hopefully can be easily answered. I'm trying to > > organize parts of my site into different directories so that they're all > > not in the "main" folder so to speak; basically breaking out by what > > part of the application it is. I also have an "include" folder for all > > my main functions and such... > > > > / (main directory) > > /include (global functions, includes) > > /app_sect1 > > /app_sect2 > > > > what I'm trying to do from /app_sect1 is include a file from the > > "include" directory, but with little success. The line looks like this: > > > > require "../include/inc_file.php"; > > > > But my page just doesn't work for me now.. any ideas what I'm missing? > > > > - Greg > > > > > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Files uploads problem
You should tell us
1. What happens
2. What you expected to happen that didn't happen.
As Kevin points out your enctype will be wrong but if that doesn't fix it
then I'd guess at the Apache 2. But tell us what the output is anyway.
- Original Message -
From: "Adrian Greeman" <[EMAIL PROTECTED]>
Newsgroups: php.general
To: <[EMAIL PROTECTED]>
Sent: Monday, March 31, 2003 5:04 PM
Subject: Files uploads problem
> I am a learner in PHP - I have been using Larry Ullman's Peachpit
beginners
> book which I have found useful to take me through the basics.
>
> But the examples were written before the general applicaton of the new
> $_POST, $_GET and similar arrays. It has been valuable learning to change
> the code for that (I use version 4.2. (and a bit) and Larry Ullman is
very
> helpful on his own website forum with readers' queries on the book
examples.
>
> But I am having real trouble making a file upload programme work. It needs
> substitution of $FileName given in the example with $_FILES array values
> which I have done and use of isset instead of a raw if(). But I still
> cannot get it to work
>
> May I put the code here and ask if anyone can tell me the problme.
> Incidentally I use Windows ME with Apache 2.0.36 and PHP 4.2.. The files
> upload is on with a max size of 2M and no specific directory given for a
> temp store (the INI says it will use the default directory.)
>
> My test out script is as follows::-
>
>
>
>
>
>
> Uploader
>
>
>
> if(isset($_FILES['File'])) {
>
> $File=$_FILES['File'];
> $File_name=$_FILES['File']['name'];
> $File_size=$_FILES['File']['size'];
>
>
> echo ("$File_name\n");
> echo ($_FILES['File']['name']);
>
> print("File name: $File_name\n");
> print("File size: $File_size\n");
>
>
>
>
> if (copy ($_FILES["File"]["tmp_name"],"users/$File_name")) {
>print("The file was sucessfully uploaded.\n");
>}else{
>print("Your file could not be copied unfortunately.\n");
>}
>
> unlink($File);
> }
>
> echo ("Upload a file to the server.");
> echo (" enctype=\multipart/form-data\>\n");
> echo ("File: \n");
> echo (" upload.\">\n");
>
>
> //test whether anything prints for the FILES array
> echo ("Can I get it to print the variable
> outside the conditional? i.e. this one
> {$_FILES['File']['name']}.\n");
>
>
>
> //set any old variable and print it to be sure basics work
> $TestPrint="Print this out
> then..\n";
>
> echo($TestPrint);
>
> ?>
>
>
>
>
> Is there something I've missed in the script. Or perhaps Apache 2 is the
> problem?
> Thanks
>
>
>
>
>
>
>
>
>
>
>
> Regards
> Adrian Greeman
> Telephone +44 20 8672 9661
> Mobile +44 780 329 7447
>
> E-mail adresses
>
> [EMAIL PROTECTED]
> or
> [EMAIL PROTECTED]
>
> **Please note - there is a 400kB filter on my e-mail so if you send a
large
> item (eg a JPEG pic) please also send a separate smaller message to tell
me
> the other one is coming.
>
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Re: [PHP] problem with mysql.
Right, defaults to /usr/local/ for the source versions of MySQL, in that case, use --with-mysql=/usr/local - Original Message - From: "Jon Haworth" <[EMAIL PROTECTED]> Newsgroups: php.general To: "Ryan Vennell" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Monday, March 31, 2003 5:00 PM Subject: RE: [PHP] problem with mysql. > Hi Ryan, > > > when configuring php i use --with-mysql and it configures just > > fine. i've even added an =/path/to/php after it to no avail. > > Try --with-mysql=/path/to/mysql instead of --with-mysql=/path/to/php. > > Cheers > Jon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: php and mysql
Assuming Month_Start is stored in MySQL date format (-mm-dd) you could Select blah blah From blah Order By DATE_FORMAT(Month_Start,%m) ASC The %m will pad on the zeroes. http://www.mysql.com/doc/en/Date_and_time_functions.html - Original Message - From: "Tyler Durdin" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Monday, March 31, 2003 1:53 PM Subject: php and mysql > > I have a db with events in it. i would like to pull the events out via php, > but i would like them to be ordered by month number (1-12). When I do this > (Select blah blah From blah Order By Month_Start ASC) it orders the months > by number, but it starts with october (month 10) I am pretty sure it is > doing this because I have no events until april (month 4). So how can i get > it to order the months by their numbers starting with january (1) and going > to december (12) even if I do not have events until april (4)? > > > > > _ > The new MSN 8: advanced junk mail protection and 2 months FREE* > http://join.msn.com/?page=features/junkmail > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Array Question
If you added a dummy field in the table that is minus one field, you might use the merge table, but I honestly have no idea whether this would be more or less efficient than sorting arrays in memory. Guess that would depend on the sizes of the tables and the number of records you'll be returning. http://www.mysql.com/doc/en/MERGE.html - Original Message - From: "Mark McCulligh" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Tuesday, April 01, 2003 12:33 PM Subject: Re: [PHP] Array Question > I have looked at the different JOINs but I can't link any fields together. > There is no relationship between the tables. The two table are basically the > same table. But the DBA didn't make them one like he should have. > > Mark. > > > "Skate" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] > look into things like JOIN and SORT BY in MySQL, they're quicker and more > efficient than PHP for doing DB stuff (so i'm told) > > took me awhile to get my head around JOIN, but once you've got it, you'll > never be without it ;) > > > "Mark McCulligh" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] > > I have two tables that I want to display together as if they were one > table > > and order them by a common date field. > > > > Because I am using MySQL I can't use the usually way I would do this. > Create > > a store procedure or view. > > > > I was thinking of creating two separate queries in PHP then loading the > data > > into one Array. In short loop though both tables copying the records into > an > > array. > > > > Then I was going to sort the Array my a common date field. Then of course > > loop through printing the Array. > > > > My question is: Is this the best way to do this or is there another way. > > Also how can you sort an Array by one date field. > > > > Any ideas on how to do link two tables together and sort my a common dat e > > field. > > > > Thanks, > > Mark. > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Can php run as a script?
Look for PHP CLI in google. Recent versions of PHP install at CLI PHP executable by default. e.g I ended up with one in: /usr/local/apache/bin/php [EMAIL PROTECTED] root]# /usr/local/apache/bin/php -v PHP 4.3.1 (cli) (built: Feb 20 2003 14:09:35) Copyright (c) 1997-2002 The PHP Group Zend Engine v1.3.0, Copyright (c) 1998-2002 Zend Technologies - Original Message - From: "Kelvin Poon" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Wednesday, April 02, 2003 11:43 AM Subject: Can php run as a script? > Hi, > > This might be a newbie question but I can't find an answer anywhere I > search. I know php can be excuted by a web browser, but can it run as a > script like Perl? > > The reason i ask is, I need to write a php script that updates a database in > a server. And this script needs to be running in the background as a > service, that's why i was wondering if I can excute it like a perl script. > > If it can't, do you guys know if I can use perl to call up a php script? > > Please advise. > > Thanks, > Kelvin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Html forms to php scripts
What version of Apache are you using? Can you point us to a phpinfo() file? - Original Message - From: "Timothy Vanzee" <[EMAIL PROTECTED]> Newsgroups: php.general To: <[EMAIL PROTECTED]> Sent: Wednesday, April 02, 2003 11:31 AM Subject: FW: [PHP] Html forms to php scripts Repost because no one replied originally. Are there any other lists that anyone knows of for php that could be more helpful? I'm quite disappointed in this one because I thought this was a fairly easy question for those who have been working with php for a while. I have the following issue between my html forms and php scripts. Html file (input.html) looks like this: Php file (input.php) looks like this: I can input text (i.e. superman) and then click submit. The resulting php page returns: supermanttt=superman It seems to me that it must be something in the php.ini file that needs to be changed, but I can't identify what exactly. Any help would be appreciated. php 4.2.2 Tim Van Zee ITS Network Specialist Governors State University -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Can php run as a script?
find / -name php -print - Original Message - From: "Poon, Kelvin (Infomart)" <[EMAIL PROTECTED]> To: "'Tim Burden'" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Wednesday, April 02, 2003 12:35 PM Subject: RE: Can php run as a script? > Thanks! > > but the thing is I have php 4.2.2 version installed in that server. And > since it is not 4.3.0 therefore CLI isn't on by default. How can I check if > CLI is on or not? If it is not on, I won't be able to excute the php as a > script in another other way? > > THnaks@ > > -Original Message- > From: Tim Burden [mailto:[EMAIL PROTECTED] > Sent: Wednesday, April 02, 2003 12:02 PM > To: Kelvin Poon > Cc: [EMAIL PROTECTED] > Subject: Re: Can php run as a script? > > > Look for PHP CLI in google. > > Recent versions of PHP install at CLI PHP executable by default. > e.g I ended up with one in: > > /usr/local/apache/bin/php > > [EMAIL PROTECTED] root]# /usr/local/apache/bin/php -v > PHP 4.3.1 (cli) (built: Feb 20 2003 14:09:35) > Copyright (c) 1997-2002 The PHP Group > Zend Engine v1.3.0, Copyright (c) 1998-2002 Zend Technologies > > > - Original Message - > From: "Kelvin Poon" <[EMAIL PROTECTED]> > Newsgroups: php.general > To: <[EMAIL PROTECTED]> > Sent: Wednesday, April 02, 2003 11:43 AM > Subject: Can php run as a script? > > > > Hi, > > > > This might be a newbie question but I can't find an answer anywhere I > > search. I know php can be excuted by a web browser, but can it run as a > > script like Perl? > > > > The reason i ask is, I need to write a php script that updates a database > in > > a server. And this script needs to be running in the background as a > > service, that's why i was wondering if I can excute it like a perl script. > > > > If it can't, do you guys know if I can use perl to call up a php script? > > > > Please advise. > > > > Thanks, > > Kelvin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Can php run as a script?
I used to use wget and run cleanup scripts from cron in the usual way. Some people also used to use lynx to do it, I believe. But the best way would be to install latest version of PHP, IMHO. - Original Message - From: "Poon, Kelvin (Infomart)" <[EMAIL PROTECTED]> To: "'Tim Burden'" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Wednesday, April 02, 2003 12:35 PM Subject: RE: Can php run as a script? > Thanks! > > but the thing is I have php 4.2.2 version installed in that server. And > since it is not 4.3.0 therefore CLI isn't on by default. How can I check if > CLI is on or not? If it is not on, I won't be able to excute the php as a > script in another other way? > > THnaks@ > > -Original Message- > From: Tim Burden [mailto:[EMAIL PROTECTED] > Sent: Wednesday, April 02, 2003 12:02 PM > To: Kelvin Poon > Cc: [EMAIL PROTECTED] > Subject: Re: Can php run as a script? > > > Look for PHP CLI in google. > > Recent versions of PHP install at CLI PHP executable by default. > e.g I ended up with one in: > > /usr/local/apache/bin/php > > [EMAIL PROTECTED] root]# /usr/local/apache/bin/php -v > PHP 4.3.1 (cli) (built: Feb 20 2003 14:09:35) > Copyright (c) 1997-2002 The PHP Group > Zend Engine v1.3.0, Copyright (c) 1998-2002 Zend Technologies > > > - Original Message - > From: "Kelvin Poon" <[EMAIL PROTECTED]> > Newsgroups: php.general > To: <[EMAIL PROTECTED]> > Sent: Wednesday, April 02, 2003 11:43 AM > Subject: Can php run as a script? > > > > Hi, > > > > This might be a newbie question but I can't find an answer anywhere I > > search. I know php can be excuted by a web browser, but can it run as a > > script like Perl? > > > > The reason i ask is, I need to write a php script that updates a database > in > > a server. And this script needs to be running in the background as a > > service, that's why i was wondering if I can excute it like a perl script. > > > > If it can't, do you guys know if I can use perl to call up a php script? > > > > Please advise. > > > > Thanks, > > Kelvin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Long screen display cut short.
I had same problem and it involved an array. In my case there was a typo, and the array I was trying to do something with didn't even exist, but it was hard to find because instead of dying with an error it would just sort of sit there, not outputting anything further, until I clicked stop in the browser. Can't remember more details. Haven't had problem since, we upgrade with releases. - Original Message - From: "Floyd Baker" <[EMAIL PROTECTED]> Newsgroups: php.general To: "Thomas Seifert" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Saturday, May 31, 2003 8:42 PM Subject: Re: [PHP] Re: Long screen display cut short. > On Sat, 31 May 2003 13:18:13 +, you wrote: > > >what is the online-version? > >I mean which webserver-software in which version? > > > > > >Thomas > > Linux RH 7.3 > Apache 1.3.24 > mySql 3.23.55 > PHP4.2.0 > > Also, this is an httpS connection if it makes a difference in some > way. > > Floyd > > > > > > >On Fri, 30 May 2003 20:45:08 -0400 [EMAIL PROTECTED] (Floyd Baker) wrote: > > > >> > >> Hello... > >> > >> I have a routine that works fine on local win98 but when it runs on > >> linux online, the screen output is cut short. I have lengthened the > >> 30 second script time max to 45 but that made no difference at all. > >> > >> Depending on the particulars, the routine stops at a certain spot. If > >> it is rerun, it stops at the very same spot again. Putting in other > >> particulars cause it to stop at a different point, further down. It > >> seems that changes which affect the number of mysql calculations, make > >> some difference in the length of the screen display, but it's only a > >> minor amount. It cuts off somewhere around 4 pages. > >> > >> Any ideas please. > >> > >> Floyd > >> > >> -- > > -- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
