[PHP] Session End
Hi
I am have created an authentication system, wherein the user is
authenticated on the basis of a MySQL database.
Here is the code
$auth = false; // Assume user is not authenticated
if (isset( $PHP_AUTH_USER ) && isset($PHP_AUTH_PW)) {
// Connect to MySQL
mysql_pconnect( 'localhost', 'mysql', 'sunny' )
or die ( 'Unable to connect to server.' );
// Select database on MySQL server
mysql_select_db( 'testbed' )
or die ( 'Unable to select database.' );
// Formulate the query
$sql = "SELECT * FROM guest WHERE
login= '$PHP_AUTH_USER' AND
password = '$PHP_AUTH_PW'";
// Execute the query and put results in $result
$result = mysql_query( $sql )
or die ( 'Unable to execute query.' );
// Get number of rows in $result.
$num = mysql_numrows( $result );
if ( $num != 0 ) {
// A matching row was found - the user is authenticated.
$auth = true;
session_start();
}
}
if ( ! $auth ) {
header( 'WWW-Authenticate: Basic realm="Pushpinder Singh\'s World"'
);
header( 'HTTP/1.0 401 Unauthorized' );
echo 'Authorization Required.';
exit;
} else {
echo 'You are authorized!';
}
?>
However this keeps the user logged on. I want to be able to close the
session once the user has finished his work.
How do I do that??
Many Thanks
--pS
Pushpinder Singh Garcha
_
Web Architect
T. Falcon Napier and Associates, Inc.
Off : 704 987 6500
Cell : 704 236 2939
Fax : 704 987 5002
_
[PHP] PHP and MySQL
Hello,
I am using PHP to create forms and then am entering the user input into
a MySQL DB
In the first query I am trying to select the values that the user
entered on the form
THIS DOES NOT WERK gives error unable to execute query
$sql = "INSERT INTO `guest` (`title`, `first_name`, `last_name`,
`login`, `password`, `passport_number`, `e_mail`, `question`, `answer`,
`industry`, `job_title`, `state`, `city`, `company`, `last_visit`)
VALUES ('\$select\', \'$f_name\', \'$l_name\', \'$login\',
\'$password\', NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL,
NOW());";
WHEN I TRY TO HARD CODE THE VALUES INTO THE MYSQL QUERY, IT WERKS FINE
// $sql = 'INSERT INTO `guest` (`title`, `first_name`, `last_name`,
`login`, `password`, `passport_number`, `e_mail`, `question`, `answer`,
`industry`, `job_title`, `state`, `city`, `company`, `last_visit`)
VALUES (\'gh\', \'ghdfghhgj\', \'hgddj\', \'ggfgfg\', \'hfgdj\', NULL,
NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NOW());';
Can somebody please tell me where I am going wrong..??
Many thanks
Pushpinder Singh Garcha
_
Web Architect
T. Falcon Napier and Associates, Inc.
Re: [PHP] PHP and MySQL
Thanks Jason...that werked fine for me..
--pS
On Wednesday, December 11, 2002, at 03:50 PM, Jason Wong wrote:
On Thursday 12 December 2002 04:30, Pushpinder Singh Garcha wrote:
Hello,
I am using PHP to create forms and then am entering the user input
into
a MySQL DB
In the first query I am trying to select the values that the user
entered on the form
THIS DOES NOT WERK gives error unable to execute query
$sql = "INSERT INTO `guest` (`title`, `first_name`, `last_name`,
`login`, `password`, `passport_number`, `e_mail`, `question`,
`answer`,
`industry`, `job_title`, `state`, `city`, `company`, `last_visit`)
VALUES ('\$select\', \'$f_name\', \'$l_name\', \'$login\',
\'$password\', NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL,
NOW());";
Not sure why you're escaping the single quote. It's unnecessary -- and
I
suspect you mis-escaped $select as well. Any you can use this format,
which
IMHO, is a lot easier on the eyes:
$sql = "INSERT INTO `guest`
SET `title` = '$title',
`first_name` = '$first_name',
...,
...,
`last_visit` = NOW()";
--
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[PHP] Help Needed
hello all I am using php and mysql in my web application. I am making use of forms to accept data from the user and add it to the mysql database. I also have a login system in place. I need to create a way for the user to edit the information that he/she entered. Can you suggest a way I can do that. I want to be able to display a form to the user where his information is present ... and then he/she can go ahead and make updates. thanks --pS Pushpinder Singh Garcha _
[PHP] Session Problem
Hello I am trying to make use of sessions to auhenticate users on the secure parts of the website. Things seems to work fine...but I keep getting this warning. Can some one pl explain what this means ... Warning: Cannot send session cache limiter - headers already sent (output started at /Users/pgarcha/Sites/edit.php:7) in /Users/pgarcha/Sites/edit.php on line 8 Thanks in advance --pS Pushpinder Singh Garcha
[PHP] Session Length
Hello Everyone: I am using Sessions to secure parts of my website. I need to know if there is a way to set a lifetime for these sessions , so that they are automatically destroyed when say the user is inactive for 30 minutes. Any help will be greatly appreciated. Thanks in advance Pushpinder Singh -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Dynamic List Using Php
Hello All I am wanting a create a dynamic List using php. When a user enters a value on a form, I need the value that he entered on the form to added to a dynamic list box, which is displayed on the next page. So the List Box continues to grow whenever a user adds a value on the form (note: The values entered every time have to be stored) Thanks in advance. Pushpinder Singh Garcha _ Web Architect T. Falcon Napier and Associates, Inc. _
[PHP] Ecard Senders
Hello there, I am looking around for some E card senders based on PHP and MySQL . Duz anyone have any ideas which I should use.? Please let me know... I really appreciate it, best Pushpinder -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] help needed with session variables
hello,
I am making use of sessions in my PHp/MySQL Database application. When
the user is successfully authenticated against the database, a session
is created in following manner:
session_register("valid_user","firstname","lastname");
$valid_user = $login;
$firstname = $first_name;
$lastname = $last_name;
While I am able to use the $valid_user variable all thru the sesion ,
when I try to use the $valid_user it works fine (i.e. I am able to
access the value) throughout the session, however when I try to use the
other two registered session variables i.e firstname and lastname, I
am not able to extract the value. Can you suggest what might be going
wrong. Note I am locally testing the setup on my Mac.
Many Thanks
Pushpinder Singh Garcha
_
Web Architect
[PHP] Help Needed
Hello All:
I am using PHP and MySQL in my application. I need to be able to allow
ONLY authorized users access to some pages in the site. For this I am
creating a session variable ''$valid_user", after the user has
successfully authenticated himself with the Database. The pages that
need to be protected are all HTML files. So far everything, works fine.
I am wondering how to finally deploy the logic on all the pages that
need to be protected.
Here is my point of view.
1). Change all the names of the protected documents to .php
2). Use the following script:
if (session_is_registered($valid_user)) {
// show the original page
PLEASE TELL me a way to display the same page
}
elseif (!session_is_registered($valid_user)) {
// display an error message to the user asking him to login before he
can see this page
}
many thanks
--Pushpinder Singh
Pushpinder Singh Garcha
_
Web Architect
[PHP] Help Needed
Hello All:
My question is related to authentication. I have made a login system
using PHP Sessions and MySQL. Once the user gets authenticated on the
website I want to be able to allow him to see some html pages on the
website. Only users who have logged in are able to see such a files. I
have asked this question before , but still I have some doubts.
My code will check for:
if (session_is_registered($valid_user))
{
/// display the reqd page
}
else {
DISPLAY ERROR MESSAGE and ASK USER TO LOGIN
}
How should I display the page ... the page has a lot of html code and
trying to write echo " blah blah blah . ";
will not be a an option. Please suggest a way out .
Many Thanks
Pushpinder
Pushpinder Singh Garcha
_
Web Architect
Re: [PHP] Re: Help Needed
Hello All:
Thanks again... I tried to use this and it is working fine for me.
Please comment:
Many Thanks
-Pushpinder
On Tuesday, February 4, 2003, at 12:32 PM, Goetz Lohmann wrote:
Pushpinder Singh Garcha schrieb:
Hello All:
My question is related to authentication. I have made a login system
using PHP Sessions and MySQL. Once the user gets authenticated on the
website I want to be able to allow him to see some html pages on the
website. Only users who have logged in are able to see such a files. I
have asked this question before , but still I have some doubts.
My code will check for:
if (session_is_registered($valid_user))
{
/// display the reqd page
}
else {
DISPLAY ERROR MESSAGE and ASK USER TO LOGIN
}
How should I display the page ... the page has a lot of html code and
trying to write echo " blah blah blah . ";
will not be a an option. Please suggest a way out .
you could include every page into a php script using
this mean, that this page is like being copyed in the php file
also instead of
you always can do
bla bla bla
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\/ --
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|| why the company needs him, until he goes on vacation.
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_
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[PHP] Protect Access to a Directory
Hi,
I am using PHP and MySQL in my application. I have created a Login
System for using "Sessions". The problem that I am facing is that I
need to protect a large number of pages in my website. So I have tried
to use this method and it works fine for me :
if (session_is_registered("valid_user"))
include ('guest.html');
else include 'not_logged_in.php';
?>
I get stumped here in order to be able to insert this code I have
to write for each of the 400 html files, 400 php files with the same
name. Most of the files are arranged in the form of directories. Is
there a better way to be able to do this (Using PHP and MySQL). Thanks
in advance !
Best Wishes
Pushpinder Singh Garcha
_
Web Architect
[PHP] PhpMyADmin Help
Hello , I am using PhpMyAdmin to control my MySQL Database. Untill now I had been using the Local Apache webserver to test my scripts, so I had installed PhpMyAdmin in the 'Sites' Folder of my Mac. Now I need to beta test the Application on the Live Server. Do I need to upload PhpMyAdmin on to the remote site? Or can I let it remain sitting on the local server. Also, I was wondering , what value should I assign to the $cfg['PmaAbsoluteUri'] variable in the config.inc.php file. Many Thanks, Pushpinder Pushpinder Singh Garcha _ Web Architect
[PHP] Php security
Hi all i wanted to check with if it is possible to see the contents of a .php file. I have heard of the Zend Encoder, but I was wondering how could a person see my php script ? Any information in this direction would be useful? TIA --Pushpinder Singh Garcha _ Web Architect
[PHP] PhpBB2 Error
Hello All, I have been runing PHP BB2 successfully on my site for a couple of months . Recently I got this error. phpBB : Critical Error Could not connect to the database Can someone tell what this means..?? Many Thanks --Pushpinder Singh Garcha _ Web Architect Pushpinder Singh Garcha _ Web Architect
[PHP] Error Opening file
Hello All;
I am trying to open a File called cmi_list.txt ( stored at the same
level as the php file) and then load these into an array.
Now I check the $passport_codes with the value the User has entered and
set the $flag accordingly
.
$PASSPORT_CODES =file("cmi_list.txt");
$count = count($PASSPORT_CODES);
for($i=0 ; $i < $count ; $i++) {
if ($PASSPORT_COUNT[$i] != $p_code ) $flag = "true";
else $flag = "false";
}
if ($flag == "false")
{
echo "Passport Code did match record on file\n\n";
exit;
}
.
.
?>
This does not seem to work correctly.
[PHP] Date/Time Logic
Hello Everyone, My php/mysql application needs to keep track of the first time that a User logs on to the site. Afterwards the User should be allowed either 3 days / 3 months/1 year of access to the site. Once the stipulated time period is over the system should invalidate the login of the user. The Admin/ User should get email notification about this. The notification part is easy the hard part to figure out is how to be able to keep and tab on the Time Period stipulated for a user. Thanks in advance Pushpinder Singh Garcha _ Web Architect
[PHP] Cron Job help Needed
Hello All, I need to ask you about some resources for "cron" jobs. Please suggest some online help Thanks Pushpinder Singh Garcha _ Web Architect
[PHP] File Trouble
Hello All
I am trying to load the contents of a file stored on the server in to
an array. The file has 125 or so lines. However when I load the file
into the array and try to print the array elements..all I see is one
continuos line.
$PASSPORT_CODES=file("../GUEST/list.txt");
if(!$PASSPORT_CODES)
{
echo "File could not be read by the system !! ";
exit;
}
else
echo "File was opened !!";
$x = count($PASSPORT_CODES);
echo "Count is : $x";
for($i=0; $i";
}
Can you please help me out with this I need to get a 125 element
array...so that my code can check the individual elements of the Array.
Thanks in advance
Pushpinder Singh Garcha
_
Web Architect
[PHP] Still having File trouble
Hello all,
I am trying to read the contents of a file called 'file.txt' into an
array and then compare it with the user inputs.
when I read the file it gets stored as a single line. I am trying to
get a way around that but alas.
I would really appreciate any help. Thanks
--Pushpinder
HERE IS THE TEST CODE
/*
abc111
asd123
aqw234
www234
edr234
vfr456
*/
$p_code = "abc111";
echo "The passport code that was entered in the system was
$p_code";
$PASSPORT_CODES = file("file.txt");
if(!$PASSPORT_CODES)
{
echo "File could not be read by array !! ";
exit;
}
else
echo "Array was opened !!";
$x = count($PASSPORT_CODES);
echo "Array Count is: $x";
for($j=0; $j<$x; $j++){
echo "$PASSPORT_CODES[$j]";
}
$A = array("\r\n", "\n\r", "\r", "\n");
$P = str_replace("$A", "\n" , "$PASSPORT_CODES");
//then simple explode() the data to receive an array of lines:
$P = explode($P,"\n");
for($i=0; $i
if (rtrim($P[$i])==$p_code) {
$flag = "true";
echo "Congratulations, $f_name your passport code has been accepted
by our system !";
break;
}
else {
$flag = "false";
}
}
if ($flag == "false") {
echo " Sorry, your passport Code was not accepted by our
system !";
exit;
}
?>
RESULTS OF THE ABOVE CODE
The passport code that was entered in the system was abc111
Array was opened !!
Array Count is: 1
abc111 asd123 aqw234 www234 edr234 vfr456
Sorry, your passport Code was not accepted by our system !
Pushpinder Singh Garcha
_
Web Architect
[PHP] Help with Arrays
Hello all
I am having some problem with arrays
THIS IS THE PHP CODE
$temp = file("file.txt");
if(!$temp)
{
echo "File could not be read by array !! ";
exit;
}
else
echo "Array was opened !!";
$x = count($temp);
echo "Array Count is: $x";
echo "$temp[0]";
//$P = str_replace("\r\n", "\n" , $temp);
echo "First: $temp[0]";
$P_new = explode(" ",$temp);
echo "Next: $P_new[0]";
THIS IS THE TEXT FILE CALLLED ''file.txt''
abc111
asd123
aqw234
www234
edr234
vfr456
When I echo "$temp[0]" ... I get abc111 asd123 aqw234 www234 edr234
vfr456 on one straight line, which is weird. I should get it on
separate lines.. Also I am unable to separate the lines of the file
using the explode().
Any help will be highly appreciated
--Pushpinder
Pushpinder Singh Garcha
_
Web Architect
Fwd: [PHP] Help with Arrays
Begin forwarded message:
From: Pushpinder Singh Garcha <[EMAIL PROTECTED]>
Date: Thu Feb 27, 2003 7:57:38 PM US/Eastern
To: olinux <[EMAIL PROTECTED]>
Subject: Re: [PHP] Help with Arrays
Thanks
My question was that each line of the file should be stored as one
element of the array.
This is because, I need to compare each line of the text file against
some user values.
TIA
--Pushpinder
On Thursday, February 27, 2003, at 04:33 PM, olinux wrote:
and what problem is that?>
how about just using the example?
http://www.php.net/manual/en/function.file.php
$lines = file ('http://www.example.com/');
// Loop through our array, show html source as html
source; and line numbers too.
foreach ($lines as $line_num => $line) {
echo "Line #{$line_num} : " .
htmlspecialchars($line) . "\n";
}
--- Pushpinder Singh Garcha <[EMAIL PROTECTED]>
wrote:
Hello all
I am having some problem with arrays
THIS IS THE PHP CODE
$temp = file("file.txt");
if(!$temp)
{
echo "File could not be read by array !!
";
exit;
}
else
echo "Array was opened !!";
$x = count($temp);
echo "Array Count is: $x";
echo "$temp[0]";
//$P = str_replace("\r\n", "\n" , $temp);
echo "First: $temp[0]";
$P_new = explode(" ",$temp);
echo "Next: $P_new[0]";
THIS IS THE TEXT FILE CALLLED ''file.txt''
abc111
asd123
aqw234
www234
edr234
vfr456
When I echo "$temp[0]" ... I get abc111 asd123
aqw234 www234 edr234
vfr456 on one straight line, which is weird. I
should get it on
separate lines.. Also I am unable to separate the
lines of the file
using the explode().
Any help will be highly appreciated
--Pushpinder
Pushpinder Singh Garcha
_
Web Architect
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Pushpinder Singh Garcha
_
Web Architect
[PHP] File Access Rights
Hello all My php script needs to read a text file that is stored in the same Dir as the php file. However I do not want to allow users to be able to see the contenst of the file from the Browser. Please suggest some remedy. Thanks in advance Pushpinder Singh Garcha _ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] File Access Rights
Thanks Kevin I have tried to chmod the file ...but I need to give others the permission to read the file...or the script itself cannot open the file ! --Pushpinder On Wednesday, March 5, 2003, at 03:27 PM, Kevin Stone wrote: chmod($file, 0600); This sets the file to Owner read and write, Group nothing, Public nothing. If you're on a shared server then chances are this function has been disabled so you may have to FTP or SSH into your account and set the permissions for the file manually using the chmod command. Good luck. - Kevin - Original Message - From: "Pushpinder Singh Garcha" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Wednesday, March 05, 2003 12:51 PM Subject: [PHP] File Access Rights Hello all My php script needs to read a text file that is stored in the same Dir as the php file. However I do not want to allow users to be able to see the contenst of the file from the Browser. Please suggest some remedy. Thanks in advance Pushpinder Singh Garcha _ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Pushpinder Singh Garcha _ Web Architect : www.MasterStream.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] File Access Rights
The error that I get is a "Permission Denied" Message !! --Puspinder On Wednesday, March 5, 2003, at 03:27 PM, Kevin Stone wrote: chmod($file, 0600); This sets the file to Owner read and write, Group nothing, Public nothing. If you're on a shared server then chances are this function has been disabled so you may have to FTP or SSH into your account and set the permissions for the file manually using the chmod command. Good luck. - Kevin - Original Message - From: "Pushpinder Singh Garcha" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Wednesday, March 05, 2003 12:51 PM Subject: [PHP] File Access Rights Hello all My php script needs to read a text file that is stored in the same Dir as the php file. However I do not want to allow users to be able to see the contenst of the file from the Browser. Please suggest some remedy. Thanks in advance Pushpinder Singh Garcha _ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Pushpinder Singh Garcha _ Web Architect : www.MasterStream.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Php File/Dir Protection
Hello All My application is based on PHP / MySQL. I am using "Sessions" to validate users before they can access the SIte. I need to use the same login to allow the users to gain access to a secret Dir. This directory is within the webfolder. I have gone through many previous threads and figured out a way. I need to make sure that it is correct: 1. Take the secret dir out of the website and place it on the ISP server i.e. ~/my_web_site/www/secret_dir would be changed to make it ~/my_web_site/www.secret_dir 2. Check if a valid session in the name of a user exists 3. If seesion exists , I would fopen() the file provided the correct file name is passed to the script Thanks Pushpinder Singh Garcha _ Web Architect : www.MasterStream.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Help Needed
Hello All I am writing again with reference to my dir Protection PHP script. The scenario is explained below. Whenever a user clicks a particular URL, it triggers a php file which first checks if the user's session exists or not. If the user's session exists, it should fopen() the particular file for him. My question is: after checking for the session, how does the php script know what file to open..meaning what file was linked by that URL. Please help! Pushpinder Singh Garcha _ Web Architect : www.MasterStream.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Help Needed
Hey All My Php App is trying to fopen() and fread() a File that is located in the Web Server. This works if the file is a simple html file. However the complicated part is that the file is not displayed correctly i.e. it has missing gifs if, it was created using Fireworks and then subsequently exported as a html. Any help will be highly appreciated TIA Pushpinder Singh Garcha _ Web Architect
Re: [PHP] Help Needed
Thanks for the prompt reply Michael I am trying to protect files on the site, my script checks for a valid session ID and fopens() a File. This file is located in a different Dir from the php script. When the file is a simple html file , I can easily fopen() the file (Even though it contains gifs) The real problem arises is when this html file has been exported from Fireworks (I.E. ".png" file ) The resulting file shows many missing links wihen I try to fread() the html file. Although the file is displayed fine when I point my Browser (Mozilla) to it. I am testing on the MAC OS Jaguar Platform Thanks again --pS On Tuesday, March 11, 2003, at 09:12 AM, Michael Roger C. Bianan wrote: Garcha, Kindly check your file paths. When you export it, it may not point to what really is the real path online. May I ask what are you trying to achieve? -Original Message----- From: Pushpinder Singh Garcha [mailto:[EMAIL PROTECTED] Sent: Monday, March 10, 2003 1:45 PM To: [EMAIL PROTECTED] Subject: [PHP] Help Needed Hey All My Php App is trying to fopen() and fread() a File that is located in the Web Server. This works if the file is a simple html file. However the complicated part is that the file is not displayed correctly i.e. it has missing gifs if, it was created using Fireworks and then subsequently exported as a html. Any help will be highly appreciated TIA Pushpinder Singh Garcha _ Web Architect -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Pushpinder Singh Garcha _ Web Architect
[PHP] .htaccess Help
Hello All I need to allow users to be able to access ONLY non-html files in a Secret Dir. Can anyone suggest a .htaccess method to do just that. I have a .htaccess script which will prevent anybody from viewing the contents of a Dir via http, but this time , I need to allow users to view the PHP Files TIA Pushpinder Singh Garcha _ Web Architect
Re: [PHP] I'm really getting annoyed with PHP
try this, use a meta-refresh ... echo "http://wherever_u_wana_go.com/hello.html\";>"; hth --Pushpinder On Thursday, July 24, 2003, at 11:24 PM, Beauford.2005 wrote: It's obvious though that PHP can not handle it. This is why I am forced to use javascript. I have already spent a week on this and am not going to waste any further time. I have posted all my code and if someone can see a problem I'll look at it, but it just ain't worth the effort at this point. -Original Message- From: Justin French [mailto:[EMAIL PROTECTED] Sent: July 23, 2003 10:52 PM To: Curt Zirzow Cc: PHP Subject: Re: [PHP] I'm really getting annoyed with PHP On Thursday, July 24, 2003, at 12:18 PM, Curt Zirzow wrote: And in my case I would never see the next page. I have javascript turned off. Never rely on javascript to do the work, excpecially in small cases like this when php can handle it without any issues, such as javascript being turned off. To follow on from this, the W3 accessibility guidelines (http://www.w3.org/TR/WCAG10/checkpoint-list.html) state: --- 6.3 Ensure that pages are usable when scripts, applets, or other programmatic objects are turned off or not supported. If this is not possible, provide equivalent information on an alternative accessible page. [Priority 1] For example, ensure that links that trigger scripts work when scripts are turned off or not supported (e.g., do not use "javascript:" as the link target). If it is not possible to make the page usable without scripts, provide a text equivalent with the NOSCRIPT element, or use a server-side script instead of a client-side script, or provide an alternative accessible page as per checkpoint 11.4. Refer also to guideline 1. --- In short, do as much as you can server side (PHP), and ensure the page doesn't break without JS. Then use JS on the client side IF YOU MUST to enhance the experience for those with it switched on. Yes, it's more work, and yes this is optional (but be aware that SOCOG (Sydney Olympics) were sued for having an inaccessible site, so it's only a matter of time before we have huge class action everywhere :)), and yes you'll reach a greater market share with an accessible page. Sorry for getting OT Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] I'm really getting annoyed with PHP
hello everyone, Can somebody tell me why meta-refresh is not preferred to do re-directs ? I know Javascript is browser dependent, so its undependable. using headers in php requires that no output is sent to the browser, what if the code logic requires that there is some output sent to the browser. I am sorry if this is a repeat question because someone earlier did mention abt output buffering as a way around. TIA --Pushpinder On Thursday, July 24, 2003, at 12:11 PM, Curt Zirzow wrote: * Thus wrote Pushpinder Singh Garcha ([EMAIL PROTECTED]): try this, use a meta-refresh ... echo "http://wherever_u_wana_go.com/hello.html\";>"; This has already been discussed, and is not the preferred method of doing redirects. PHP can handle what he is doing just fine. Curt -- "I used to think I was indecisive, but now I'm not so sure." -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Display Records (brief summary and full details)
Hello All,
I am trying to create a small MySQL application using PHP. I have a
table of contacts with each record having over 30 fields. I have a
search page where a logged-in admin can search for a particular record
on the basis of certain parameters.
This is a sample code:
$sql1 = "SELECT * from `contacts` WHERE $where";
while ($row = mysql_fetch_array($result1)) {
// Alternate the bgcolor of each row for visibility
($even % 2) == 0 ? $bgcolor = "#EFEFEF" : $bgcolor =
"#ee";
$even = $even + 1;
// print the actual row
echo "
$row[company]
$row[name_1]
$row[phone_1]
$row[city]
$row[url]
$row[email_1]
Link
";
// try to register the variable
$_SESSION['link'] = $row[company];
} // end while
// print the end of the table
echo "";
The above tables displays the results of the query in a table form
with only the main fields of the record. The last column of the table
contains a link to view the full-contents of the record. when the user
clicks this link, he will go to another script called
"profile.php" which will display all the contents of the record. In
order to do this I will need to store all the primary keys (in this
case the name of the company) of each record from the result set and
then use it to retrieve all the contents. I have been successful in
trying to do this for a single row (record) of the result by
registering it as an session variable called ['link']
I am at a loss to figure out how to store the names of the first column
of the result set i.e. the company name. Is it possible to create an
array of the session variable ['link'] ?? Another approach would be
to get the names of the companies as a separate query and register them
as an array of session variables.
any suggestions will be welcome. Thanks in advance.
--Pushpinder
Re: [PHP] Display Records (brief summary and full details)
Thanks Tom,
I appreciate your help ! however I have a 2 quick questions...
1.) should we not save the names of the companies as $companies[$row]
= $row['company'];
2.) the approach of accessing the variable as $details =
$_SESSION['link']['$_GET['name']] is not
working , when I try to echo the $details is get something else.
I am not sure how we use the
$_SESSION[ ] [ ] with 2 variables as shown.
any help will be appreciated.
regards
--Pushpinder
On Thursday, July 24, 2003, at 08:10 PM, Tom Rogers wrote:
Hi,
Friday, July 25, 2003, 7:13:27 AM, you wrote:
PSG> Hello All,
PSG> I am trying to create a small MySQL application using PHP. I
have a
PSG> table of contacts with each record having over 30 fields. I have a
PSG> search page where a logged-in admin can search for a particular
record
PSG> on the basis of certain parameters.
PSG> This is a sample code:
PSG> $sql1 = "SELECT * from `contacts` WHERE $where";
PSG> while ($row = mysql_fetch_array($result1)) {
PSG> // Alternate the bgcolor of each row for visibility
PSG> ($even % 2) == 0 ? $bgcolor = "#EFEFEF" : $bgcolor =
PSG> "#ee";
PSG> $even = $even + 1;
PSG> // print the actual row
PSG> echo "
PSG>
PSG> face=\"Verdana, Arial, Helvetica,
sans-serif\">$row[company]
PSG>
PSG> face=\"Verdana, Arial, Helvetica,
sans-serif\">$row[name_1]
PSG>
PSG> face=\"Verdana, Arial, Helvetica,
sans-serif\">$row[phone_1]
PSG>
PSG> face=\"Verdana, Arial, Helvetica,
sans-serif\">$row[city]
PSG>
PSG> face=\"Verdana, Arial, Helvetica,
sans-serif\">$row[url]
PSG>
PSG> face=\"Verdana, Arial, Helvetica,
sans-serif\">$row[email_1]
PSG>
PSG> face=\"Verdana, Arial, Helvetica, sans-serif\">
PSG> href=\"profile.php\">Link
PSG> ";
PSG> // try to register the variable
PSG>$_SESSION['link'] = $row[company];
PSG> } // end while
PSG> // print the end of the table
PSG>echo "";
PSG> The above tables displays the results of the query in a table form
PSG> with only the main fields of the record. The last column of the
table
PSG> contains a link to view the full-contents of the record. when the
user
PSG> clicks this link, he will go to another script called
PSG> "profile.php" which will display all the contents of the record.
In
PSG> order to do this I will need to store all the primary keys (in
this
PSG> case the name of the company) of each record from the result set
and
PSG> then use it to retrieve all the contents. I have been successful
in
PSG> trying to do this for a single row (record) of the result by
PSG> registering it as an session variable called ['link']
PSG> I am at a loss to figure out how to store the names of the first
column
PSG> of the result set i.e. the company name. Is it possible to create
an
PSG> array of the session variable ['link'] ?? Another approach
would be
PSG> to get the names of the companies as a separate query and
register them
PSG> as an array of session variables.
PSG> any suggestions will be welcome. Thanks in advance.
PSG> --Pushpinder
in the href put
..
Make a seperate array as you loop
$companies[$row['name']] = $row;
in your session store it as
$_SESSION['link'] = $companies;
You can then access it in profile php as
$details = $_SESSION['link']['$_GET['name']]
--
regards,
Tom
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[PHP] Array Question
hello everyone,
I am trying to store one of the fields of the resultset into an array
as I display the results.
while ($row = mysql_fetch_array($result1)) {
// Alternate the bgcolor of each row for visibility
($even % 2) == 0 ? $bgcolor = "#EFEFEF" : $bgcolor =
"#ee";
$even = $even + 1;
// print the actual row
echo "
$row[company]
$row[name_1]
$row[phone_1]
$row[city]
$row[url]
$row[email_1]
--Link--
";
// try to store the name of the company in an array called companyname
$companyname = array($row['company']);
// try to register the variable
$_SESSION['link'] = $companyname;
//$_SESSION['link'] = $row[company];
} // end while
I am trying to store the variable $row['company'] into a array called
companyname[], so that I am able to register it as a session variable
and use it on subsequent pages. I keep getting errors and am not able
to store the values in array $row['company'] . I would appreciate if
someone could throw some light on this.
Thanks in advance.
--Pushpinder
[PHP] Store array as Session Variable
hello All,
I am trying to store an array as a session variable.
while ($row = mysql_fetch_array($result))
{
if ( !is_array($company_name) ) $company_name = array();
array_push($company_name, $row['company']);
// try to register session variable
$_SESSION['link'] = $company_name;
}
Now when I try to access this session variable in another file...I am
getting a junk value.I am not sure if I am getting this right.
$details = $_SESSION['link'];
echo "LINK: ".$details."";
Can some one fill me in on this. Appreciate it ! Thanks in advance.
--Pushpinder Singh
Re: [PHP] Store array as Session Variable
$details is empty !!
Thanks
--Pushpinder
On Monday, July 28, 2003, at 03:31 PM, CPT John W. Holmes wrote:
$details is an array (just like $company_name was). Try to view
print_r($details); and see what you get.
---John Holmes...
- Original Message -
From: "Pushpinder Singh Garcha" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, July 28, 2003 3:18 PM
Subject: [PHP] Store array as Session Variable
hello All,
I am trying to store an array as a session variable.
while ($row = mysql_fetch_array($result))
{
if ( !is_array($company_name) ) $company_name = array();
array_push($company_name, $row['company']);
// try to register session variable
$_SESSION['link'] = $company_name;
}
Now when I try to access this session variable in another file...I am
getting a junk value.I am not sure if I am getting this right.
$details = $_SESSION['link'];
echo "LINK: ".$details."";
Can some one fill me in on this. Appreciate it ! Thanks in advance.
--Pushpinder Singh
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Re: [PHP] Store array as Session Variable
Thanks Chris,
I am able to see the contents of the $company_name array. The next
part involves storing this as a session variable.
I am trying to link this page to another search page using the --Link--
while ($row = mysql_fetch_assoc($result))
{
"
$row[company]
sans-serif\">$row[name_1]
$row[phone_1]
$row[city]
$row[url]
$row[email_1]
--Link-- ";
$company_name[] = $row['company'];
// try to register the variable
$_SESSION['link'] = $company_name;
}
What would be the best way to register the array $company_name as a
session var and access it on the following page. $_SESSION['link'] =
$company_name;
does not seem to work since it gives NULL when i try to echo
$_SESSION['link'];
Thanks in advance
--Pushpinder
On Monday, July 28, 2003, at 03:43 PM, Chris Shiflett wrote:
--- Pushpinder Singh Garcha <[EMAIL PROTECTED]> wrote:
I am trying to store the value in row['company'] in an array
called $company_name.
I see now. I think you might find this a bit simpler (if I understand
correctly):
$company_name = array();
while ($row = mysql_fetch_assoc($result))
{
$company_name[] = $row['company'];
}
Also, at this point, you should probably examine the contents of
$company_name
before bothering with the session stuff. You may be having trouble
with your
query or something that is totally unrelated to sessions. Try John's
suggestion
of print_r() by doing something like this:
echo '';
print_r($company_name);
echo '';
Hope that helps.
Chris
=
Become a better Web developer with the HTTP Developer's Handbook
http://httphandbook.org/
Re: [PHP] Store array as Session Variable
Thanks John, I used the $_GET['name'] on the next page to access the selection. http://psg.local/~psgarcha/CRM/full-profile.php?name=jack http://psg.local/~psgarcha/CRM/full-profile.php?name=tim http://psg.local/~psgarcha/CRM/full-profile.php?name=mary http://psg.local/~psgarcha/CRM/full-profile.php?name=evian My full-profile.php page first checks for a session before displaying the results. However if I decided to use the sessions approach how would I go about it ? I am just curious to find out why $_SESSION['company_name'] = $company_name; duz not werk for me ! Thanks in advance --Pushpinder On Monday, July 28, 2003, at 04:14 PM, CPT John W. Holmes wrote: I am able to see the contents of the $company_name array. The next part involves storing this as a session variable. I am trying to link this page to another search page using the --Link-- If you're passing the company name in the URL, why are you adding the entire array to the session? You can just use $_GET['name'] to get the name of the "company" that was clicked on... ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Store array as Session Variable
Hello Chris, I am using session_start(). All the pages after the login page use sessions and will redirect the user to the login page, if he/she is NOT logged in. So I am guessing the error lies in my logic somewhere. Thanks again. --Pushpinder On Monday, July 28, 2003, at 04:51 PM, Chris Shiflett wrote: --- Pushpinder Singh Garcha <[EMAIL PROTECTED]> wrote: However if I decided to use the sessions approach how would I go about it? I am just curious to find out why $_SESSION['company_name'] = $company_name; duz not werk for me! Did you use session_start() like I mentioned? If so, you are probably making an error somewhere due to the complexity of your script(s). If you want to learn how to use sessions, focus on that and nothing else (e.g., forget interacting with a database, passing URL variables, etc.). Start with a simple example, get that to work, then integrate it into what you are trying to do. Hope that helps. Chris = Become a better Web developer with the HTTP Developer's Handbook http://httphandbook.org/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Store array as Session Variable
Hello Chris, I am using Apache webserver on the MAc Jaguar OS Platform Regards --Pushpinder On Monday, July 28, 2003, at 05:02 PM, Chris Shiflett wrote: --- Pushpinder Singh Garcha <[EMAIL PROTECTED]> wrote: I am using session_start(). All the pages after the login page use sessions and will redirect the user to the login page, if he/she is NOT logged in. You're not using IIS by chance are you? If so, I think you will find this link helpful: http://marc.theaimsgroup.com/?l=php-general&m=102929828515647&w=2 Chris = Become a better Web developer with the HTTP Developer's Handbook http://httphandbook.org/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] _GET question
Hello All,
My application has a search / query feature where in the user
selects the search criteria and is displayed a page containing the
reults. The user must also be allowed to edit these results and save
them later on. On the results page I use the following logic,
//
// START OF PSEUDOCODE
//
if ($submit)
{
yada yada yada
Update the database with the changes the user has made in the form
$value = $_GET['val'];
echo ": ".$value."";
$UpdateString = "UPDATE contacts SET
...
.
where WHERE `company` = '$value' ";
}
elseif (isset(_SESSION['validuser'])) {
display the form with the results of the search
...
...
...
...
}
elseif ( ! isset(_SESSION['validuser'])) {
// display an error page asking the user to login
}
//
//END OF PSEUDOCODE
//
Can some one tell me if the action parameter of the form is correct ?
Since in the first part of the if() statement when I try to retrieve
the value of $_GET['val'] I do not get anything.
All suggestions are welcome. Thanks in advance
--Pushpinder
Re: [PHP] Passing Values between Pages : $_SESSION / $_GET
Hello again,
I would appreciate if someone could help me out with this one.
Thanks again
--Pushpinder
On Friday, August 8, 2003, at 11:46 AM, Pushpinder Singh Garcha wrote:
Hello All,
I am using php and mysql in my application which allows users to
search/query a database. The database is cast and has about 32 rows
per record. When the user fires the query, the result is in the form
of a table that contains only the 6 important rows of the entire
record. Also there is a provision to allow the user to see the full
record set by clicking on the link under the 'complete profile'
contained in the table. (as shown below). The name of this script is
lookup_results.php
Here is the result for a companies in city = 'Charlotte' / Primary key
of the table is the name of the company.
---
---
-
Company Name Main ContactCity Website
E-Mail Complete
Profile
---
---
-
PSG Pushpy Charlotte
http://www.psg.com[EMAIL PROTECTED]--Link--
TFNA Napier Charlotte
http://www.psg.com[EMAIL PROTECTED]--Link--
Micro Bates Charlotte
http://www.psg.com [EMAIL PROTECTED]--Link--
CNN Garcha PSCharlotte
http://www.psg.com [EMAIL PROTECTED]--Link--
---
---
-
To see the complete profile of the company I use
href=\"full_profile_1.php?name=".$row['company'] .
So once we are on the full_profile_1.php, we can see all the contents
of the record. Also we display a form where we can edit the results in
place. The logic works like this.
// full_profile_1.php LOGIC
session_start();
if (isset($_SESSION['validuser']))
{
if($submit)
{
update the changes that the user has made to the form
My question here is " How do I get the name of the company
that was passed to this script as a $_GET Parameter. I cannot use the
$company because it is out of scope. The only other option
would be to use $_SESSION['link'] i.e. Store the names of the
companies in a session array. So now the array as per the
example above would be {'PSG','TFNA', 'Micro', 'CNN' } . The way this
will work is how do I get the index of the 'link' array that
is applicable in this example.
Here the name of the company would be $company =
$_SESSION['link'][0];
If we had clicked the second row of the results table the
name of the compnay would have been 'TFNA' i.e. $_SESSION['link'][1]
and so on. How do I pass the index. ???
}
else
{
$company = $_GET['name'];
USE
ANDdisplay all the rows of the record where company_name
='company'
}
}
else {
redirect the user to the ERROR Page
}
// end of pseudo- code
Thanks in advance guys. I know this may sound a lil' vague , but I
have tried to present the logic and the problem.
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Re: [PHP] Passing Values between Pages : $_SESSION / $_GET
Hello Jay ,
I am attaching snippet of the Form Code that displays the results of
the first query
meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
"; ?>
Complete
Candidate Profile
Logout
Company
Name
>
// END OF SNIPPET
However when I try to access it in the if($submit) part as
$_POST['temp'] I get nothing !!!
Thanks in advance,
--Pushpinder
On Friday, August 8, 2003, at 04:57 PM, Jay Blanchard wrote:
[snip]
Let me clarify again. The $_GET Parameter was used to to transfer the
name from the results page (with the tables etc) to a
full-profile_1.php page. On the full_profile_1.php page the user is
displayed a form with all the details about the company. On the same
page there is a form where changes can be made to values of the fields.
I am trying to pass the company name in this form as a POST Parameter.
However the Update part of the full_profile.php page is not able to get
this value.
[/snip]
Clearer now.
Place the value in a hidden form field that can be passed along with
the
POST
Re: [PHP] Display variable with spaces -SOLVED
Thank you so much ! it works fine now ;) --Pushpinder On Wednesday, August 13, 2003, at 12:01 PM, Larry E. Ullman wrote: And I try to display it in the table using this : > if I try to echo the variable $email_1, I get the correct value i.e. "thisisa long e-mail address" /// However when it comes to displaying it using the table all I get is the "thisisa" . It simply avoids the spaces. Can anyone tell me why this is happening..?? I am sure it is something pretty minor but I just cant seem to get it right. You need to quote your value attribute. Larry -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Display variable with spaces
Hello,
I am trying to display the rows of a MySql Query in a table. I
retrieve the result using the query :
while ($row = mysql_fetch_array($result1, MYSQL_ASSOC))
{
$email_1 = $row["email_1"];
}
And I try to display it in the table using this :
>
if I try to echo the variable $email_1, I get the correct value i.e.
"thisisa long e-mail address"
/// However when it comes to displaying it using the table all I get is
the "thisisa" . It simply avoids the spaces. Can anyone tell me why
this is happening..?? I am sure it is something pretty minor but I
just cant seem to get it right.
Thanks in advance,
-Pushpinder
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[PHP] Passing Values between Pages : $_SESSION / $_GET
Hello All,
I am using php and mysql in my application which allows users to
search/query a database. The database is cast and has about 32 rows per
record. When the user fires the query, the result is in the form of a
table that contains only the 6 important rows of the entire record.
Also there is a provision to allow the user to see the full record set
by clicking on the link under the 'complete profile' contained in the
table. (as shown below). The name of this script is lookup_results.php
Here is the result for a companies in city = 'Charlotte' / Primary key
of the table is the name of the company.
---
Company Name Main ContactCity Website
E-Mail Complete
Profile
---
PSG Pushpy Charlotte
http://www.psg.com[EMAIL PROTECTED]--Link--
TFNA Napier Charlotte
http://www.psg.com[EMAIL PROTECTED]--Link--
Micro Bates Charlotte
http://www.psg.com [EMAIL PROTECTED]--Link--
CNN Garcha PSCharlotte
http://www.psg.com [EMAIL PROTECTED]--Link--
---
To see the complete profile of the company I use
href=\"full_profile_1.php?name=".$row['company'] .
So once we are on the full_profile_1.php, we can see all the contents
of the record. Also we display a form where we can edit the results in
place. The logic works like this.
// full_profile_1.php LOGIC
session_start();
if (isset($_SESSION['validuser']))
{
if($submit)
{
update the changes that the user has made to the form
My question here is " How do I get the name of the company
that was passed to this script as a $_GET Parameter. I cannot use the
$company because it is out of scope. The only other option
would be to use $_SESSION['link'] i.e. Store the names of the
companies in a session array. So now the array as per the
example above would be {'PSG','TFNA', 'Micro', 'CNN' } . The way this
will work is how do I get the index of the 'link' array that
is applicable in this example.
Here the name of the company would be $company =
$_SESSION['link'][0];
If we had clicked the second row of the results table the
name of the compnay would have been 'TFNA' i.e. $_SESSION['link'][1]
and so on. How do I pass the index. ???
}
else
{
$company = $_GET['name'];
USE
ANDdisplay all the rows of the record where company_name
='company'
}
}
else {
redirect the user to the ERROR Page
}
// end of pseudo- code
Thanks in advance guys. I know this may sound a lil' vague , but I have
tried to present the logic and the problem.
Re: [PHP] Passing Values between Pages : $_SESSION / $_GET
Thank you Jay for responding.
Let me clarify again. The $_GET Parameter was used to to transfer the
name from the results page (with the tables etc) to a
full-profile_1.php page. On the full_profile_1.php page the user is
displayed a form with all the details about the company. On the same
page there is a form where changes can be made to values of the fields.
I am trying to pass the company name in this form as a POST Parameter.
However the Update part of the full_profile.php page is not able to get
this value.
The main point to remember is that full_profile_1.php does 2 things :
1.) Display all the fields of the company as a form which is editable
2.) Now if the user were to make changes in the values that were
returned in the form above , the changes should be updated in the
record. Now my problem is trying to transfer the name of the
company from the 'form' to the update query.
The way the logic on the full_profile_1.php is designed is as
follows:
if ($submit)
{
// This is after the user has been displayed all the fields of
the record and he has made some changes and wanst to Update them
// The Problem is how do I get the same name of the company in
this loop. I have tried to pass the name as another $_POST Variable
from the Form in the else part below, but when I try to access
it over here. nothing comes.
$temp1 = $_POST['temp']; // RETURNS EMPTY
:(
}
else{
// here we get the name of the company as a $_GET Parameter from the
previous page
// display all the records of the selected company as a editable Form
}
Thanks again, and have a great weekend !
--Pushpinder
On Friday, August 8, 2003, at 04:20 PM, Jay Blanchard wrote:
[snip]
My question here is " How do I get the name of the company that was
passed to this script as a $_GET Parameter. I cannot use the $company
because it is out of scope.
[/snip]
How about $_GET['company'] ? Or am I missing something?
Have a pleasant day.
[PHP] '&' Sign in _GET Parameter
Hello All, I am using an application where I retrieve user profile from a MySQL DB using the Company Name . I pass the name of the company to the PHP script as a '$_GET' parameter. e.g. when the name of the company is 'IBM'. , the URL with the query string would look like : http://masterstream.com/CRM/full_profile_1.php?name=IBM Now one of the records had a name : PSG & Inc. , in this case the URL with the query string would look like http://masterstream.com/CRM/full_profile_1.php?name=PSG%20&%20Inc. However in the case of the latter I am not able to pull out any records from the MySQL database. It says that "no records with the name were found". I went ahead and tweaked the name of the company, to remove the "&" sign in 'PSG & Inc.' Now the query works fine. Can some one throw some light here. I am sure something minor is to be done when passing the name of the company in the parent script. Thanks in advance --Pushpinder
Re: [PHP] '&' Sign in _GET Parameter
Thanks for the link, $link = $row['company']; However this does not seem to work / what am I missing ? Thanks -Pushpinder On Friday, August 22, 2003, at 03:23 PM, CPT John W. Holmes wrote: From: "Pushpinder Singh Garcha" <[EMAIL PROTECTED]> I am using an application where I retrieve user profile from a MySQL DB using the Company Name . I pass the name of the company to the PHP script as a '$_GET' parameter. e.g. when the name of the company is 'IBM'. , the URL with the query string would look like : http://masterstream.com/CRM/full_profile_1.php?name=IBM Now one of the records had a name : PSG & Inc. , in this case the URL with the query string would look like http://masterstream.com/CRM/full_profile_1.php?name=PSG%20&%20Inc. However in the case of the latter I am not able to pull out any records from the MySQL database. It says that "no records with the name were found". I went ahead and tweaked the name of the company, to remove the "&" sign in 'PSG & Inc.' Now the query works fine. Can some one throw some light here. I am sure something minor is to be done when passing the name of the company in the parent script. The & character separates variables in the query string, so it must be encoded if it appears in the data. Take a look at http://us2.php.net/urlencode ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Installation help
I am having the same story on my Win XP system. I hv looked all over message brds @ phpbuilder/zend/php.net . No success Please let me know if you are able to sort it out. Thx --Pushpinder On Tuesday, May 27, 2003, at 12:07 PM, Brian Dunning wrote: Hi, I am a lamer & a newbie, and ran the PHP and MySQL installers on my XP box, but can't connect to any database and don't see any new processes running. Is there someplace I can find documentation for this that is optimized for the newbie lamer? Thanks, - Brian -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Session Question
Hello Ernest, SInce register_globals() is ON on my server, I need to be able to figure out a way to ensure session security. Another question I had was that, with register_globals() ON can I still use the $_SESSION to set my variables ? I want to avoid recoding the entire application, so I want to see what can be done to enhance security with the current setup. Does the super-global array approach i.e. $_SESSION work, irrespective of the fact that REGISTER_GLOBALS is ON / OFF ? If I start setting session variables in the $_SESSION array from now on, will it improve the security of the session. I am a newbie in PHP session handling and am sorry if any of the above questions sound extremely lame. Thanks in advance, --Pushpinder On Wednesday, May 21, 2003, at 04:34 PM, Ernest E Vogelsinger wrote: At 21:51 21.05.2003, Pushpinder Singh Garcha said: [snip] register_globals is ON on my site. You should really rethink this - have a look at http://www.php.net/manual/en/security.registerglobals.php http://www.php.net/manual/en/ref.session.php section "Sessions and Security" register_globals=on simply enables anyone injecting globals to your site: http://www.yoursite.com/myscript.php?valid_user=sam+spade To keep sessions secure, one might consider these steps: (1) Filesystem security: session.save_path points to a directoy owned and readable by the webserver user only: session.save_path=/tmp/php chown apache:apache /tmp/php chmod 700 /tmp/php (2) If security issues are high you may attempt to make sure that the session identifier - be it via cookie or via URL parameter - gets additional confirmation. I once used this approach: I am transmitting a random cookie (random name, random value) to the browser, making a note (in $_SESSION) of the cookie name and its value. When the session gets revisited check for the existence and the value of this cookie. If the values match construct another random cookie, having another name and another value (also sending header information to delete the old cookie). If the cookie doesn't match don't discard the session but merely redirect the browser to another URL (usually a login page), clearing the session ID if it was received it as cookie. This has a drawback - clients are forced to accept cookies, or the system wouldn't work at all. Thus you can only implement it where security is at risk, and where acceptance of the additional cookie can be enforced (extranet applications, for example). (3) As a last resort one can remember the client IP that must match for the same session. This is not secure at all, and it doesn't work with some AOL connections where client IPs change at will (by AOL using random proxies for every INet connection). You can however automatically rule out that method if the client IP stems from the AOL-assigned range. Keeping a very good eye on session security, sessions are the only thing where you can keep login data and access rights, just like you're doing it. I would only urge you NOT to use session_register() and session_is_registered(), but to use the $_SESSION[] superglobal to be absolutely sure you're using only data you yourself have put there, and not injected data. -- O Ernest E. Vogelsinger (\)ICQ #13394035 ^ http://www.vogelsinger.at/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Another Session Question
Hello all,
I have php ver 4.1.1 running with register_globals() ON on my site. I
am trying to use sessions to maintain state during a visit to the site.
I have read thru the manual, but my mind is still cluttered with
doubts. I understand that use of the $_SESSION global array will
greatly add to the security of the site and will prevent variable
poisoning.
How do I register a session?
The manual (http://www.php.net/manual/en/print/ref.session.php) says
that there are 2 methods:
Example 1. Registering a variable with $_SESSION.
---
Example 4. Registering a variable with register_globals enabled
-
This is a snippet of the code that I am testing:
if ( $_POST['validuser'] && ($_POST['password']) ) {
mysql_select_db($database_MasterStream, $MasterStream);
$query_Recordset1 = "SELECT * FROM `admin` WHERE `admin`.username =
"$_POST['validuser']" AND `admin`.password = "$_POST['password']"";
$Recordset1 = mysql_query($query_Recordset1, $MasterStream) or
die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
if ($totalRows_Recordset1)
{
echo "Success!";
if(!isset($_SESSION['validuser']))
$_SESSION['validuser'] = 0;
else $_SESSION['validuser']++;
}
else{
echo "Please try again later";
}
}
?>
Thanks in advance,
Pushpinder
[PHP] Stumped @ MySql insert query
Hello everyone, I am trying to execute a simple query using $_POST variables, so that variable poisoning is not possible. note: I have register_globals ON on my site. I am getting the error shown below . Please advise ... as I can't seem to figure out why ! // connect to the BD/Table etc // Formulate the query $sql1 = "INSERT INTO `contacts` VALUES ( $_POST['company'], $_POST['pri_name'], $_POST['sec_name'], $_POST['assistant_1'], $_POST['assistant_2'], $_POST['pri_practice'], $_POST['sec_practice'], $_POST['sic'], $_POST['date_established'], $_POST['size'], $_POST['phone_1'], $_POST['phone_2'], $_POST['phone_3'], $_POST['email_1'], $_POST['email_2'], $_POST['email_3'], $_POST['url'], $_POST['city'], $_POST['msa'], $_POST['status'], $_POST['timezone'], $_POST['first_contact'], $_POST['next_contact'], $_POST['last_contact'], $_POST['notes'], $_POST['email_history'], $_POST['battery_started'], $_POST['details'], TIMESTAMP(); $_POST['source'] )"; $result1 = mysql_query($sql1) or die ( 'Database Error has occured.'); $num_results = mysql_num_rows($result1); echo $num_results." rows added !!"; ?> Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING' in /home/ABCD/CRM/add.php Thanks in advance. Pushpinder
Re: [PHP] Stumped @ MySql insert query
On Friday, June 13, 2003, at 02:22 PM, Zak Johnson wrote: $_POST variables are still subject to poisoning; in your case, SQL injection. How is variable poisoning possible when using $_POST ?? I always felt that the php compiler should check to see if the variable was part of the POST Global array. At least this is is what I thought about the $_POST global array. Thanks in advance --Pushpinder -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] PhpMyAdmin / MySQL
Hello All, I am using phpMyAdmin to administer my MySQl DB. I am running Mac OS Jaguar. when I try to start up phpMyAdmin I get an error: Welcome to phpMyAdmin 2.4.0 Error MySQL said: Can't connect to local MySQL server through socket '/tmp/mysql.sock' (2) So I try to start up the MySQL Server manually by typing the following on my command prompt: and here are the results: [psg:/usr/local/mysql] psgarcha% sudo ./bin/mysqld_safe & [1] 558 [psg:/usr/local/mysql] psgarcha% Starting mysqld daemon with databases from /usr/local/mysql/data 030616 10:16:32 mysqld ended Please help. Thanks in advance. --Pushpinder -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Small Error in Login Script
Hello All,
I am trying to setup a simple login script on my development server
running Mac OS Jaguar. I keep getting an error
Parse error: parse error in /Users/psgarcha/Sites/CRM/ADMIN-LOGIN.php
on line 2. I am at a complete loss !
Here is the source code. Please help.
-
error_reporting(E_ALL);
if ( (isset($_POST['validuser'])) && (isset($_POST['password'])) ) {
mysql_connect( 'localhost', 'abc', 'pwd' )
or die ( 'Unable to connect to server.' );
// Select database on MySQL server
// mysql_select_db( 'masterstream' )
or die ( 'Unable to select database' );
// Formulate the query
// $sql1 = "SELECT * from `admin` where `admin`.username =
"$_POST['validuser']" AND `admin`.password = "$_POST['password']"";
$result1 = mysql_query($sql1)
or die ( 'Database Error has occured.');
$num_results = mysql_num_rows($result1);
if ($num_results == 1 ) {
echo "Success!";
if(!isset($_SESSION['validuser']))
$_SESSION['validuser'] = $_POST['validuser'];
}
else{
echo "Please try again later";
}
}
?>
ADMIN-LOGIN
if (isset($_SESSION['validuser']))
{
echo "You are already logged into the system !!!";
}
else {
echo "test";
}
echo "
Please
enter your Username and Password
Login
Password
";
?>
Thanks in advance.
Pushpinder
Re: [PHP] Small Error in Login Script ~~SOLVED
Thanks ...I figured out something myself
--Pushpinder
On Monday, June 30, 2003, at 11:41 AM, Pushpinder Singh Garcha wrote:
Hello All,
I am trying to setup a simple login script on my development server
running Mac OS Jaguar. I keep getting an error
Parse error: parse error in /Users/psgarcha/Sites/CRM/ADMIN-LOGIN.php
on line 2. I am at a complete loss !
Here is the source code. Please help.
-
error_reporting(E_ALL);
if ( (isset($_POST['validuser'])) && (isset($_POST['password'])) ) {
mysql_connect( 'localhost', 'abc', 'pwd' )
or die ( 'Unable to connect to server.' );
// Select database on MySQL server
// mysql_select_db( 'masterstream' )
or die ( 'Unable to select database' );
// Formulate the query
// $sql1 = "SELECT * from `admin` where `admin`.username =
"$_POST['validuser']" AND `admin`.password = "$_POST['password']"";
$result1 = mysql_query($sql1)
or die ( 'Database Error has occured.');
$num_results = mysql_num_rows($result1);
if ($num_results == 1 ) {
echo "Success!";
if(!isset($_SESSION['validuser']))
$_SESSION['validuser'] = $_POST['validuser'];
}
else{
echo "Please try again later";
}
}
?>
ADMIN-LOGIN
if (isset($_SESSION['validuser']))
{
echo "You are already logged into the system !!!";
}
else {
echo "test";
}
echo "
Please
enter your Username and Password
Login
Password
";
?>
Thanks in advance.
Pushpinder
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[PHP] MySQL Query
Hello ,
Can someone tell me what is wrong with the following querys ? I am
pretty sure its got something to do with the quotes around $_POST[]
variables.
$sql1 = "SELECT * from `admin` where `admin`.user =
'"$_POST['validuser']"' AND `admin`.pwd = '"$_POST['password']"'";
$sql1 = "SELECT * from `admin` where user = "$_POST['validuser']" AND
pwd = "$_POST['pass']"";
Thanks in advance,
--Pushpinder
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Re: [PHP] MySQL Query ~~ SOLVED
Thanks to all you great ppl out there !!! have a great weekend ;-) for those in north america FYI : mine has just started ! cheers --Pushpinder On Monday, June 30, 2003, at 02:36 PM, Thorsten Körner wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi Am Montag, 30. Juni 2003 20:10 schrieb Pushpinder Singh Garcha: Hello , Can someone tell me what is wrong with the following querys ? I am pretty sure its got something to do with the quotes around $_POST[] variables. $sql1 = "SELECT * from `admin` where `admin`.user = '"$_POST['validuser']"' AND `admin`.pwd = '"$_POST['password']"'"; $sql1 = "SELECT * from `admin` where user = "$_POST['validuser']" AND pwd = "$_POST['pass']""; You have forgotten to set the 'dots' 8-) $sql1 = "SELECT * from `admin` where `admin`.user = '" . $_POST['validuser'] . "' - ---^ AND `admin`.pwd = '" . $_POST['password'] . "'"; - ----^ That's it. CU Thorsten have fun - -- Thorsten Körner http://www.123tkShop.org -BEGIN PGP SIGNATURE- Version: GnuPG v1.2.2-rc1-SuSE (GNU/Linux) iD8DBQE/AIMZs5R35vLkl/cRAhzpAKCigPBeox92GTtjbGu8Ydiu5NlxIQCgqy27 SFw6/nEAUy4nsAvMzaQiFQk= =Axl+ -END PGP SIGNATURE- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Help Needed
Hi I am trying to create an online survey using PHP ...I am using MySQL as the database and MAC OS Jaguar. I do not need the results to be added to the database. I need to be able to send the results of the survey to an email addressI know that this is possible using MS FrontPage but with PHP I am not so sure. Please help. Thanks, Pushpinder Pushpinder Singh Garcha Web Developer T. Falcon Napier and Associates, Inc. Url : http://www.masterstream.com Off : 704 987 6500 Cell : 704 236 2939 Fax : 704987 5002 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] PhpMyAdmin Help Needed
Hi I am wanting to use PhpMyAdmin for my project . I am developing using PHP and MySQl and the OS is Jaguar I have downloaded the latest version of phpmyadmin and have made necessary changes in the 'config.inc.php' file When I try to access PhpMyAdmin using " http://localhost/~pgarcha/phpmyadmin/index.php"; I get the folowing error Not Found The requested URL /~pgarcha/phpmyadmin/index.php was not found on this server. Apache/1.3.26 Server at pushpinder-garchas-computer.local Port 80 This is the list of things that I have changed: 1). $cfg['PmaAbsoluteUri'] = 'http://localhost/~pgarcha/phpmyadmin/'; 2). $cfg['Servers'][$i]['auth_type'] = 'http'; // Authentication method (config, http or cookie based)? 3). $cfg['Servers'][$i]['user'] = 'root'; // MySQL user 4). $cfg['Servers'][$i]['password'] = 'sunny'; // MySQL password (only needed // with 'config' auth_type) I am not sure about the "user" attribute that I have put above actually "pgarcha' is the admin of the system. Please help me out. Thanks in advance Pushpinder Pushpinder Singh Garcha _ Web Developer T. Falcon Napier and Associates, Inc. Off : 704 987 6500 Cell : 704 236 2939 Fax : 704 987 5002 _
[PHP] Jaguar OS help
Hi i have recently upgraded from OS 10.1.5 to Jaguar. I previously had 2 users on the system. and using the main login screen I could select the user that I wanted to log on as. Now that I have installed Jaguar ...I do not get any such screen to select user and so I am unable to log on the other user. I ahve tried to play with "System Preferences / Users " option ...but that did not help. The other user exists in the /Users Directory. Thanks Pushpinder Pushpinder Singh Garcha _ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Secure Connection
Hi, I am making a secure page where users will be able to send credit card information. What kind of support does php offer? Thanks Pushpinder Singh Garcha -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Secure PHP Form
hi all I am using a php form to collect credit card information from clients and so have hosted the page on a secure server i.e. https After filing out the form ...the browser displays a "confirmation page". I am using IE 5.2 on MAC OS Jaguar when I point IE to the secure site and submit the form I get this error "Security Failure Data Decryption Failure" When I used Mozilla browser...things worked fine and I got no such error Please help me thanks Pushpinder -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Multiple Addresses Mailer
Hi All I am creating a mailing list system in which I should be able to broadcast a message to multiple recipients I am using the mail() function and putting all the recipients names in the "to" argument separated by commas. When I do this the mail goes to all the people but they come to know that it was sent to others as well. I want to be able to send mail so that each recipient thinks that this mail was ONLY sent to him/her. Thanks --pS Pushpinder Singh Garcha -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Help with using phpmailer
Hi All I am new in the php development world. I have made a simple mail application using the phph mail() function. I needed to use an attachment facility ith the mailing program...so I have tried to use this solution called phpmailer() from http://sourceforge.net/projects/phpmailer I am not able to find any installation info on the site...Has anyoneused this before? Please help .. Thanks --Pushpinder -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] help needed with phpmailer
Hi All I am new in the php development world. I have made a simple mail application using the phph mail() function. I needed to use an attachment facility ith the mailing program...so I have tried to use this solution called phpmailer() from http://sourceforge.net/projects/phpmailer I am not able to find any installation info on the site...Has anyoneused this before? Please help .. Thanks --Pushpinder Pushpinder Singh Garcha _ Web Developer T. Falcon Napier and Associates, Inc. Off : 704 987 6500 Cell : 704 236 2939 Fax : 704 987 5002 _ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Create Login Page
Hi All
I am trying to create a login page using php and mysql database.
This is the code that I am trying to use:
// File Name: auth04.php
// Check to see if $PHP_AUTH_USER already contains info
if (!isset($PHP_AUTH_USER)) {
// If empty, send header causing dialog box to appear
header('WWW-Authenticate: Basic realm="My Private Stuff"');
header('HTTP/1.0 401 Unauthorized');
exit;
} else if (isset($PHP_AUTH_USER)) {
// If non-empty, check the database for matches
// connect to MySQL
mysql_connect("localhost", "mysql", "sunny")
or die ("Unable to connect to database.");
// select database on MySQL server
mysql_select_db("masterstream")
or die ("Unable to select database.");
// Formulate the query
$sql = "SELECT *
FROM guest
WHERE login='$PHP_AUTH_USER' and
password='$PHP_AUTH_PW'";
// Execute the query and put results in $result
$result = mysql_query($sql);
// Get number of rows in $result. 0 if invalid, 1 if valid.
$num = mysql_numrows($result);
if ($num != "0") {
echo "You're authorized!";
exit;
} else {
header('WWW-Authenticate: Basic realm="My Private Stuff"');
header('HTTP/1.0 401 Unauthorized');
echo 'Authorization Required.';
exit;
}
}
?>
This is the error that I get when I point my browser to this page both
when the script is run locally and on th eremte webserver.
btw: I am running Mac OS Jagaur
Warning: Cannot add header information - headers already sent by
(output started at /Users/pgarcha/Sites/auth.php:7) in
/Users/pgarcha/Sites/auth.php on line 13
Warning: Cannot add header information - headers already sent by
(output started at /Users/pgarcha/Sites/auth.php:7) in
/Users/pgarcha/Sites/auth.php on line 14
Many Thanks
--Pushpinder
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[PHP] Help needed with the php.ini file
Hi all I am trying make changes with the register_global variable in the php.ini file, but I am unable to locate it. I am running Mac OS JaguarPlease help me out Many Thanks. --Pushpinder Pushpinder Singh Garcha _ Web Architect T. Falcon Napier and Associates, Inc. Off : 704 987 6500 Cell : 704 236 2939 Fax : 704 987 5002 _
[PHP] help needed with forms
Hello
I am using php based forms, which collect information from the client
and send it in the form a email message to the admin.
I need to start using validation i.e. check whether some field/s has
been correctly entered in the from.
My application consists of 2 php pages
1). info.php(this page consists of the plain form and the has its
action parameter set to "send_info.php")
2). send_info.php (this forms collects the information that the
client entered and composes a message and mails it to
admin)
So I use headers in the following manner:
The send_info.php code starts like this
if($email =='') {
header("Location: http://www.mysite.com/info.php";);
}
?>
This takes the user back to the info.php page with all the fields reset.
What I need is that
1). An alert box must be displayed which tells the user where he went
wrong
2). Also the data that the user had entered on the form must not be
reset to blank.
I know this sounds very trivial.
Please help me out.
Thanks
--pS
Pushpinder Singh Garcha
[PHP] Form variables lost when duplicate records are found !
Hello everyone, I am making use of a php form to add company details to a MySQL Database. Before I add the form variables I am checking to see if the SAME company name exists in the DB. If the same company exists, then a notification is provided. In between this , the variables that were entered on the form are LOST. Is there anyway I can store the variables so that if a duplicate record was found to be present, then the forms variables are stored and NOT LOST ?? Any suggestions would be greatly appreciated ! Thanks in advance --Pushpinder -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Form variables lost when duplicate records are found !
I am currently using sessions on my site // are you suggesting that I store all the possible 30 form variables in a temp session array. ?? and destroy it afterwards Thanks -Pushpinder On Tuesday, September 2, 2003, at 04:41 PM, Matt Matijevich wrote: [snip] then the forms variables are stored and NOT LOST ?? [/snip] Have you looked into sessions? http://www.php.net/manual/en/ref.session.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Read a PDF File using php
Hello All
I need to allow a user to access a PDF file, only if he/she is logged
in as a registered user. So here is the code that I am trying to use. I
have been able to make this work in the past, when I had to read .html
file, now since the file in question is a .pdf file, I am having
trouble. The browser shows a long list of weird characters instead of
the pdf file
if(session_is_registered("user_valid")){
$filepath ="docs/any_file.pdf";
$h1 = @fopen($filepath,"r");
while (!feof($h1)) {
$a = fread($h1,4096);
echo "$a";
}
}
Any ideas / suggestions would be welcome. Thanks in advance
Pushpinder
Re: [PHP] Read a PDF File using php
No I am not sending any headers to the browser. Any suggestions ! Thanks On Wednesday, October 1, 2003, at 04:05 PM, Tyler Lane wrote: Are you sending a Content-Type header to the browser to let it know what type of file you are sending it? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Display a JPG Image
Hello Everyone,
I am trying to display a JPG image to a use, who has logged in. Some
research on google revealed a way to do this. I am using the following
code to display it.
if (session_is_registered("valid_user")){
if(session_is_registered("cmi")){
header("Content-type: image/jpg");
$file = "docs/picture1.jpg";
header("Content-disposition: attachment; filename=$file" );
readfile($file);
}
My question is that while this approach works fine with Mozilla on the
MAC and Win platform. it throws up a dialog box asking whether the user
wants to download the file or view it. However IE on either platforms
does not work fine. On the PC it does not recognize the file extension
correctly. While on the MAC side of things, it just shows the image in
the same frame.
Any suggestions would be most welcome. !
Thanks in advance
Pushpinder Singh
Re: [PHP] Display a JPG Image (continued)
Hello all again,
I am still having trouble opening a jpg image using
header("Content-type: image/jpg");
$file = "docs/picture1.jpg";
header("Content-disposition: attachment; filename=$file" );
readfile($file);
The reason being that IE on the win platform does not seem to recognize
the file extension. Mozilla on the Win and Mac Platform behave
properly. Someone, suggested that just using image/jpeg. Even that duz
not werk for me.
Suggestion welcome. Thanks in advance.
Pushpinder
On Friday, October 10, 2003, at 01:25 PM, Jon Shoberg wrote:
On Fri, 10 Oct 2003, Bertrand Moulard wrote:
try image/jpeg
cheers
.b
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[PHP] DB / Tables Question
Hello everyone, I have created a PHP and MySQL powered, web-based CRM package for our office. It simply takes care of our telephone marketing strategy. I need to provide this CRM package to our other clients as well. The CRM package makes use of 2 tables i.e. 'Admin' and 'Contacts' . The table 'Admin' stores the usernames and passwords of the people who are allowed to use the system. The other table 'Contacts' contains details of the contacts like name, email,city,state, tel,zip etc. I want to be able to create a similar CRM package for other clients. My question is should I create a separate DB for each client. or is it a better design practice to create 2 tables (Admin and Contacts) per client within the same DB. I am not sure if I have been able to clearly express my doubts here, but I will be more that happy to address any questions. Thanks in advance Pushpinder -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
