[PHP] overloading members. aghhh!!!

[Kiketom]

Hi all.
Yesterday i have looking for the overloading members

Member overloading
void __set ( string name, mixed value )
mixed __get ( string name )

As an example i put this code:

class foo
{
private $ID;
private $Name;
private $LastName;

private function __get($var)
{
return $var;
}

private function __set($var,$value)
{
$var = $value;
}
}


$foo = new foo();
$foo->ID = 1;
$foo->Name = "Henry";
$foo->LastName = "Ford",


that's horrible!!!

And if i want to validate that ID > 0??

i have to put this validation in the function __set for each property??
private function __set($var,$value)
{
if ($var = 'ID')
{
//validate that ID is > 0
}
$var = $value;
}


Not exists a better method to manage the properties in a class?

Like in C#

private int _ID;

public int ID
{
get { return _ID;}
set
{
if (value > 0)
{
_ID = value;
}
 else
 {
 //Exception
 }
}
}

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Re: [PHP] overloading members. aghhh!!!

[Kiketom]

Ok, this is a great solution
Thanks ;)

"Robert Cummings" <[EMAIL PROTECTED]> escribió en el mensaje 
news:[EMAIL PROTECTED]
> On Mon, 2007-11-19 at 11:25 +0100, Kiketom wrote:
>> Hi all.
>> Yesterday i have looking for the overloading members
>>
>> Member overloading
>> void __set ( string name, mixed value )
>> mixed __get ( string name )
>>
>> As an example i put this code:
>>
>> class foo
>> {
>> private $ID;
>> private $Name;
>> private $LastName;
>>
>> private function __get($var)
>> {
>> return $var;
>> }
>>
>> private function __set($var,$value)
>> {
>> $var = $value;
>> }
>> }
>>
>>
>> $foo = new foo();
>> $foo->ID = 1;
>> $foo->Name = "Henry";
>> $foo->LastName = "Ford",
>> 
>>
>> that's horrible!!!
>>
>> And if i want to validate that ID > 0??
>>
>> i have to put this validation in the function __set for each property??
>> private function __set($var,$value)
>> {
>> if ($var = 'ID')
>> {
>> //validate that ID is > 0
>> }
>> $var = $value;
>> }
>>
>>
>> Not exists a better method to manage the properties in a class?
>>
>> Like in C#
>>
>> private int _ID;
>>
>> public int ID
>> {
>> get { return _ID;}
>> set
>> {
>> if (value > 0)
>> {
>> _ID = value;
>> }
>>  else
>>  {
>>  //Exception
>>  }
>> }
>> }
>
> Well, if you really want to, you can do the following:
>
> 
> class foo
> {
>private $ID;
>private $Name;
>private $LastName;
>
>private function __get( $var )
>{
>if( method_exists( $this, '___get_'.$var ) )
>{
>return $this->{'___get_'.$var}();
>}
>else
>{
>return $this->{$var};
>}
>}
>
>private function __set( $var, $value )
>{
>if( method_exists( $this, '___get_'.$var ) )
>{
>return $this->{'___set_'.$var}( $value );
>}
>else
>{
>return ($this->{$var} = $value);
>}
>}
>
>private function ___get_ID()
>{
>}
>
>private function ___set_ID( $value )
>{
>}
> }
>
> ?>
>
> But I wouldn't.
>
> Cheers,
> Rob.
> -- 
> ...
> SwarmBuy.com - http://www.swarmbuy.com
>
>Leveraging the buying power of the masses!
> ... 

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Re: [PHP] overloading members. aghhh!!!

[Kiketom]

Then if i make this

$foo = new foo();
$foo->ID = 12;

what is happening??
if __Set and __Get only works if a member isn't exits,

How come I do this?
$foo->ID = 12;
if the member $ID is private???

I thought that this was possible because i have declared the two method set 
and get :P


"Jochem Maas" <[EMAIL PROTECTED]> escribió en el mensaje 
news:[EMAIL PROTECTED]
> Kiketom wrote:
>> Hi all.
>> Yesterday i have looking for the overloading members
>>
>> Member overloading
>> void __set ( string name, mixed value )
>> mixed __get ( string name )
>>
>> As an example i put this code:
>>
>> class foo
>> {
>> private $ID;
>> private $Name;
>> private $LastName;
>
> when you declare these three as 'real' members, __get() and __set()
> will no longer be called - they are only called for non-existent members.
>
> so instead dump your data in an array or something
>
> private $data  = array(
> 'ID' => null,
> 'Name' => null,
> 'LastName' => null,
> );
>
>>
>> private function __get($var)
>> {
>> return $var;
>
> there is no such thing as 'implicit class scope' $var will not refer to
> $this->var as you seem to expect.
>
> return isset($this->data[$var]) ? $this->data[$var] : null;
>
>> }
>>
>> private function __set($var,$value)
>> {
>> $var = $value;
>
> same thing here.
>
>   if (array_key_exists($var, $this->data)
> $this->data[$var] = $value;
>
>> }
>> }
>> 

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Re: [PHP] overloading members. aghhh!!!

[Kiketom]

Ok, no problem
;)

"Jochem Maas" <[EMAIL PROTECTED]> escribió en el mensaje 
news:[EMAIL PROTECTED]
> Kiketom wrote:
>> Then if i make this
>>
>> $foo = new foo();
>> $foo->ID = 12;
>>
>> what is happening??
>> if __Set and __Get only works if a member isn't exits,
>>
>> How come I do this?
>> $foo->ID = 12;
>> if the member $ID is private???
>>
>> I thought that this was possible because i have declared the two method 
>> set
>> and get :P
>>
>
> ignore my previous reply - it seems it was completely wrong. 

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